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SVEN [57.7K]
2 years ago
11

The variable isopen is to be used to indicate whether or not a store is currently open. Which of the following is the most appro

priate data type for isOpen?
Computers and Technology
1 answer:
Maksim231197 [3]2 years ago
3 0

Answer:

Boolean

Explanation:

Though the options are missing, the question is still answerable.

From the question, we understand that isOpen can only assume any of two values which are: open or close

i.e. whether a store is opened or currently.

When a variable can only assume any of two values, the most suitable data type of that variable is Boolean.

Hence, Boolean answers the question.

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Suppose that the data mining task is to cluster points (with (x, y) representing location) into three clusters, where the points
solong [7]

Answer:

Explanation:

K- is the working procedure:

It takes n no. of predefined cluster as input and data points.

It also randomly initiate n centers of the clusters.

In this case the initial centers are given.

Steps you can follow

Step 1. Find distance of each data points from each centers.

Step 2. Assign each data point to the cluster with whose center is nearest to this data point.

Step 3. After assigning all data points calculate center of the cluster by taking mean of data points in cluster.

repeat above steps until the center in previous iteration and next iteration become same.

A1(4,8), A2(2, 4), A3(1, 7), B1(5, 4), B2(5,7), B3(6, 6), C1(3, 7), C2(7,8)

Centers are X1=A1, X2=B1, X3=C1

A1 will be assigned to cluster1, B1 will be assigned to cluster2 ,C1 will be assigned to cluster3.

Go through the attachment for the solution.

5 0
2 years ago
In step 4 of the CSMA/CA protocol, a station that successfully transmits a frame begins the CSMA/CA protocol for a second frame
DerKrebs [107]

Answer:

There could be a collision if a hidden node problem occurs.

Explanation:

CSMA/CA(carrier sense multiple access/ collision avoidance) is a multiple access method in wireless networking, that allows multiple node to transmit. Collision avoidance of this method is based on preventing signal loss or downtime as a result of collision of transmitting multi signals.

If a node at step 4(transmit frame) sends the first frame, the node still needs to send a RTS(request to send) and to receive a Clear to send (CTS) from the WAP, the is to mitigate the issue of hidden node problem as all frame are treated as unit, so other listening nodes, not detected would seek to connect and transmit as well.

5 0
1 year ago
Locker doors There are n lockers in a hallway, numbered sequentially from 1 to n. Initially, all the locker doors are closed. Yo
kow [346]

Answer:

// here is code in C++

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

   // variables

   int n,no_open=0;

   cout<<"enter the number of lockers:";

   // read the number of lockers

   cin>>n;

   // initialize all lockers with 0, 0 for locked and 1 for open

   int lock[n]={};

   // toggle the locks

   // in each pass toggle every ith lock

   // if open close it and vice versa

   for(int i=1;i<=n;i++)

   {

       for(int a=0;a<n;a++)

       {

           if((a+1)%i==0)

           {

               if(lock[a]==0)

               lock[a]=1;

               else if(lock[a]==1)

               lock[a]=0;

           }

       }

   }

   cout<<"After last pass status of all locks:"<<endl;

   // print the status of all locks

   for(int x=0;x<n;x++)

   {

       if(lock[x]==0)

       {

           cout<<"lock "<<x+1<<" is close."<<endl;

       }

       else if(lock[x]==1)

       {

           cout<<"lock "<<x+1<<" is open."<<endl;

           // count the open locks

           no_open++;

       }

   }

   // print the open locks

   cout<<"total open locks are :"<<no_open<<endl;

return 0;

}

Explanation:

First read the number of lockers from user.Create an array of size n, and make all the locks closed.Then run a for loop to toggle locks.In pass i, toggle every ith lock.If lock is open then close it and vice versa.After the last pass print the status of each lock and print count of open locks.

Output:

enter the number of lockers:9

After last pass status of all locks:

lock 1 is open.

lock 2 is close.

lock 3 is close.

lock 4 is open.

lock 5 is close.

lock 6 is close.

lock 7 is close.

lock 8 is close.

lock 9 is open.

total open locks are :3

5 0
2 years ago
Assuming that the list newAnimals is initially empty, what would this list contain after the following code segment is run?
allochka39001 [22]

Answer:

b

Explanation:

4 0
2 years ago
Read 2 more answers
(1) Prompt the user to enter two words and a number, storing each into separate variables. Then, output those three values on a
denpristay [2]

Answer:Prompt the user to enter two words and a number, storing each into separate variables. Then, output those three values on a single line separated by a space. (Submit for 1 point) Ex: If the input is: yellow Daisy 6 the output after the prompts is: You entered: yellow Daisy 6 Note: User input is not part of the program output. (2) Output two passwords using a combination of the user input. Format the passwords as shown below. (Submit for 2 points, so 3 points total). Ex: If the input is: yellow Daisy 6 the output after the prompts is: You entered: yellow Daisy 6 First password: yellow_Daisy Second password: 6yellow6 (3) Output the length of each password (the number of characters in the strings). (Submit for 2 points, so 5 points total). Ex: If the input is: yellow Daisy 6 the output after the prompts is: You entered: yellow Daisy 6 First password: yellow_Daisy Second password: 6yellow6 Number of characters in yellow_Daisy: 12 Number of characters in 6yellow6: 8

I have tried several different ways of doing this, but I keep getting an error on line 6

Explanation:

7 0
1 year ago
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