The do-while loop for the given problem is shown below.
do
{
// user asked to enter two numbers
cout<<"Enter two numbers to be added."<<endl;
cin>>num1;
cin>>num2;
sum = num1 + num2;
// sum of the numbers is displayed
cout<<"Sum of the two numbers is "<<sum<<endl;
// user asked whether to perform the operation again
cout<<"Do you wish to continue (y/n) ?"<<endl;
cin>>choice;
}while(choice != 'n');
The variables to hold the two numbers and their sum are declared as float so that the program should work well for both integers and floating numbers.
float num1, num2, sum;
The char variable is taken since it holds only a single-character input from the user, 'y' or 'n'.
char choice;
The whole program is given below.
#include <iostream>
using namespace std;
int main() {
float num1, num2, sum;
char choice;
do
{
// user asked to enter two numbers
cout<<"Enter two numbers to be added."<<endl;
cin>>num1;
cin>>num2;
sum = num1 + num2;
// sum of the numbers is displayed
cout<<"Sum of the two numbers is "<<sum<<endl;
// user asked whether to perform the operation again
cout<<"Do you wish to continue (y/n) ?"<<endl;
cin>>choice;
}while(choice != 'n');
cout<<"Quitting..."<<endl;
}
