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labwork [276]
2 years ago
5

Why is project scope management so challenging in IT projects? What suggestions do you have for preventing scope creep in projec

ts? What did you think about the approach Northwest Airlines used for improving user input and reducing scope changes on their reservation system project?
Computers and Technology
1 answer:
seropon [69]2 years ago
6 0

Answer:

Explanation:

<u>Ways to Avoid Scope Creep</u>

Scope creep is what happens when changes are made to the scope of a project without any control. Changes happen to projects all the time without been notify ontime as a project manager. It is that very rare project that ends up delivering exactly what was asked for on the first day. However, without there being some control over the changes, a project manager has little chance of keeping on top of the work and managing the project effectively.

Generally, scope creep is when new requirements are added after the project has commence. These changes are not properly reviewed. The project team is expected to deliver them with the same resources and in the same time as the original scope.

On the other hand, as a project manager you could end up with a project with lots of approved, considered changes, that never ends because every time you think you have finished a new requirement arrives in your inbox and you have to make more changes.

The following are five ways to keep control of your project.

<em>1-Document the Requirements</em>

<em>2-Set up Change Control Processes</em>

<em>3-Create a Clear Project Schedule</em>

<em>4-Verify the Scope with the Stakeholders</em>

<em>5-Engage the Project Team</em>

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front zise24

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2 years ago
You are a high school student learning about computers and how to build them. As a class project, you have built a new computer.
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Answer:

You can use thermal paste, active heat sink, liquid pipes, and even a fan. These are just some that I've heard.

Explanation:

All of these are cooling and will stop the Central Processing Unit from overheating.

Hope this helps :)

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1 year ago
Design two subclasses of Employee…SalariedEmployee and HourlyEmployee. A salaried employee has an annual salary attribute. An ho
avanturin [10]

Answer:

Complete answer to above question is given below.

Explanation:

Employee.java

import java.util.Date;

public class Employee

{

private int empID;

private Address address;

private Name name;

private Date date;

public Employee()

{

}

public Employee(int empID)

{

this.empID = empID;

}

public int getEmpID()

{

return empID;

}

public void setEmpID(int empID)

{

this.empID = empID;

}

public Address getAddress()

{

return address;

}

public void setAddress(Address address)

{

this.address = address;

}

public Name getName()

{

return name;

}

public void setName(Name name)

{

this.name = name;

}

public Date getDate()

{

return date;

}

public void setDate(Date date)

{

this.date = date;

}

}

Name.java

public class Name {

private String name;

public Name(String name) {

super();

this.name = name;

}

public String getName() {

return name;

}

public void setName(String name) {

this.name = name;

}

}

Address.java

public class Address {

private String addr;

public Address(String addr) {

super();

this.addr = addr;

}

public String getAddr() {

return addr;

}

public void setAddr(String addr) {

this.addr = addr;

}

}

SalariedEmployee.java

public class SalariedEmployee extends Employee {

private double annualSalary;

public SalariedEmployee(double annualSalary) {

super();

this.annualSalary = annualSalary;

}

public double getAnnualSalary() {

return annualSalary;

}

public void setAnnualSalary(double annualSalary) {

this.annualSalary = annualSalary;

}

}

HourlyEmployee.java

public class HourlyEmployee extends Employee {

private double hourlyrate;

private double hours_worked;

private double earnings;

public HourlyEmployee(double hourlyrate, double hours_worked) {

super();

this.hourlyrate = hourlyrate;

this.hours_worked = hours_worked;

}

public double getEarnings()

{

if(hours_worked<=40)

{

earnings=hours_worked*hourlyrate;

}

else if(hours_worked>40)

{

earnings=40*hourlyrate+(hours_worked-40)*hourlyrate*1.5;

}

return earnings;

}

public double getHourlyrate() {

return hourlyrate;

}

public void setHourlyrate(double hourlyrate) {

this.hourlyrate = hourlyrate;

}

public double getHours_worked() {

return hours_worked;

}

public void setHours_worked(double hours_worked) {

this.hours_worked = hours_worked;

}

public void setEarnings(double earnings) {

this.earnings = earnings;

}

Test.java

import java.util.Date;

public class Test {

public static void main(String[] args) {

System.out.println("_____Salaried Employee_____");

SalariedEmployee se=new SalariedEmployee(50000);

se.setEmpID(1234);

se.setName(new Name("Williams"));

se.setAddress(new Address("4,Richmond Street"));

se.setDate(new Date("Oct-11-2014"));

System.out.println("Employee Id :"+se.getEmpID());

System.out.println("Employee Name :"+se.getName().getName());

System.out.println("Employee Address :"+se.getAddress().getAddr());

System.out.println("Joining Date :"+se.getDate());

System.out.println("The Annual Salary :"+se.getAnnualSalary());

System.out.println("\n_____Hourly Employee_____");

HourlyEmployee he1=new HourlyEmployee(8.5,39);

he1.setEmpID(4567);

he1.setName(new Name("Kane"));

he1.setAddress(new Address("5,lake View Road"));

he1.setDate(new Date("Nov-12-2015"));

System.out.println("Employee Id :"+he1.getEmpID());

System.out.println("Employee Name :"+he1.getName().getName());

System.out.println("Employee Address :"+he1.getAddress().getAddr());

System.out.println("Joining Date :"+he1.getDate());

System.out.println("The Earnings Of An HourlyEmployee :"+he1.getEarnings());

System.out.println("\n_____Hourly Employee_____");

HourlyEmployee he2=new HourlyEmployee(9.5,47);

he2.setEmpID(1111);

he2.setName(new Name("John"));

he2.setAddress(new Address("17,Villey Parley Street"));

he2.setDate(new Date("Dec-13-2011"));

System.out.println("Employee Id :"+he2.getEmpID());

System.out.println("Employee Name :"+he2.getName().getName());

System.out.println("Employee Address :"+he2.getAddress().getAddr());

System.out.println("Joining Date :"+he2.getDate());

System.out.println("The Earnings Of An HourlyEmployee :"+he2.getEarnings());

}

}

Output:

_____Salaried Employee_____

Employee Id :1234

Employee Name :Williams

Employee Address :4,Richmond Street

Joining Date :Sat Oct 11 00:00:00 IST 2014

The Annual Salary :50000.0

_____Hourly Employee_____

Employee Id :4567

Employee Name :Kane

Employee Address :5,lake View Road

Joining Date :Thu Nov 12 00:00:00 IST 2015

The Earnings Of An HourlyEmployee :331.5

_____Hourly Employee_____

Employee Id :1111

Employee Name :John

Employee Address :17,Villey Parley Street

Joining Date :Tue Dec 13 00:00:00 IST 2011

The Earnings Of An HourlyEmployee :479.75

7 0
2 years ago
In step 4 of the CSMA/CA protocol, a station that successfully transmits a frame begins the CSMA/CA protocol for a second frame
DerKrebs [107]

Answer:

There could be a collision if a hidden node problem occurs.

Explanation:

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If a node at step 4(transmit frame) sends the first frame, the node still needs to send a RTS(request to send) and to receive a Clear to send (CTS) from the WAP, the is to mitigate the issue of hidden node problem as all frame are treated as unit, so other listening nodes, not detected would seek to connect and transmit as well.

5 0
2 years ago
Write a script that inputs a line of encrypted text and a distance value and outputs plaintext using a Caesar cipher. The script
jenyasd209 [6]

Answer:

# Request the inputs

codedText = input("Enter the coded text: ")

distance = int(input("Enter the distance value: "))

# Calculate the decryption

# see comment for the rest. Brainly won't let me save an answer which contains code.

Explanation:

Above is your program fixed, but it is unclear on how to deal with unprintable characters, i.e., characters that originally were near the highest printable character ('~')

4 0
2 years ago
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