Answer:
Make use of hash tables
Explanation:
The appropriate thing to use for this should be a hash table.
A Hash Table can be described as a data structure which stores data in an associative manner. In a hash table, data is stored in an array format, where each data value has its own unique index value. Access of data becomes very fast if we know the index of the desired data. So we can perform Hashing on ISBN Number since its unique and based on the Hash Function w ecan store the Information record.
There is no requirement for printing the file in order - HashTables dont store the data in order of insertions, so no problems with that
It becomes a data structure in which insertion and search operations are very fast irrespective of the size of the data. So Querying books details can be fast and searching will take less time.
It can also be pointed out that it wont be too expensive for Hardware implemtation as HashTables stores data based on Hash Functions and memory consumption is also optimal which reduces memory wastages.
Because this is a on your own problem, it cannot be solved. You must speak to it after the person says something.
Answer:
d) Social networking sites
Explanation:
-Intranet is a network that is created by an organization to share information, tools and different services inside the company.
-Wikis are websites used to share content and knowledge and different users can modify the information.
-VoIP is a technology that allows you to make calls over the internet.
-Social networking sites are online platforms that allow people to connect with organizations and other people, create communities online and share different types of information.
-Unified communications is a system that has different communication methods through a single application.
According to this, the collaboration technology that is becoming more and more popular within organizations because it provides a means for forming ad hoc groups, networking and locating potential business allies is social networking sites.
Answer:
19.71 ms
Explanation:
The disk rotates at 3600 rpm, hence the time for one revolution = 60 / 3600 rpm = 16.67 ms.
Hence time to read or write on a sector = time for one revolution / number of sectors per track = 16.67 ms / 32 sectors = 0.52 ms
Head movement time from track 8 to track 9 = seek time = 2 ms
rotation time to head up sector 1 on track 8 to sector 1 on track 9 = 16.67 * 31/32 = 16.15 ms
The total time = sector read time +head movement time + rotational delay + sector write time = 0.52 ms + 2 ms + 16.15 ms + 0.52 ms = 19.19 ms
Answer:
It will be a java code.
Explanation:
import java.util.Scanner;
public class StringInputStream {
public static void main (String [] args) {
Scanner inSS = null;
String userInput = "Jan 12 1992";
inSS = new Scanner(userInput);`
String userMonth = "";
int userDate = 0;
int userYear = 0;
/* Your solution goes here */
System.out.println("Month: " + userMonth);
System.out.println("Date: " + userDate);
System.out.println("Year: " + userYear);
return;
}
}
