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Serga [27]
2 years ago
10

Susan needs to change the color scheme in all the slides of her multimedia presentation. The presentation software program Susan

is using has a slide master. Put the steps in the order that Susan should perform them.
A. Select a theme from the themes option
B.Select a slide master layout
C.Select the view tab and click slide master under presentation views
D.Select a color theme from the colors option

1.
2.
3.
4.
Computers and Technology
2 answers:
kolbaska11 [484]2 years ago
5 0

Answer:

  1. C
  2. B
  3. A
  4. D

Explanation:

The presentation software program Susan is using has a slide master and in order for Susan to make any change to her slide, she has to first access the slide master.

<em>C.Select the view tab and click slide master under presentation views </em>

Susan needs to change the color scheme in all her slides and this has to do with the layout. She needs the master layout.

<em>B.Select a slide master layout</em>

In the master layout Susan will have to select a theme, she can choose to select her default theme or change the theme to a new one. The theme affects the color scheme of all her slides.

<em>A. Select a theme from the themes option </em>

Finally, to change the color of scheme of all her slides she must select a preferred or she will have to go with the default color of the  theme she previously selected.

<em>D.Select a color theme from the colors option</em>

siniylev [52]2 years ago
4 0
I believe this would be C, B, A, D
Sorry if it wasn’t.
You might be interested in
When a program has several modules calling other modules, programmers often use a program ____, which operates similarly to an o
maw [93]

Answer:

hierarchy chart

Explanation:

Based on the information provided within the question it can be said that in this scenario programmers usually use a hierarchy chart. This is a chart that shows the relationship that exists between various different modules that are able to call on another. Therefore showing the programmers the organization of the entire overall program.

3 0
2 years ago
Add the following 2's complement binary numbers. Also express the answer in decimal. a. 01+ 1011b. 11+ 01010101c. 0101+ 110d. 01
kenny6666 [7]

Answer:

(a) 01 + 1011

Convert the two numbers into their 4-bit representation.

=> 01 = 0001

=> 1011

Addition of the two numbers (in their 2's complement form) gives the following:

0 0 0 1       ------------------> + 1 (in decimal)

<u>1  0 1  1 </u>      ------------------> - 5 (in decimal)

<u>1  1  0 0 </u>    -------------------> - 4 (in decimal)

Explanation for (a)

<em>01 or 0001</em>

Since the most significant bit is 0 (leftmost bit), it shows that it is a positive number. Therefore, it can be directly converted to its decimal representation as follows:

0001 = 0 x 2^{3} + 0 x 2^{2} + 0 x 2^{1} + 1 x 2^{0} = 1

0001 is + 1 in decimal.

<em>1011</em>

Its most significant bit(MSB) is 1 showing that it is negative.

Flipping all its bits and adding 1 to the result, will convert it to it's positive counterpart.

i.e 1011 => 0100 + 1 = 0101.

Converting the result (0101) to decimal gives

0101 = 0 x 2^{3} + 1 x 2^{2} + 0 x 2^{1} + 1 x 2^{0} = 5

1011 is -5 in decimal

<em>01 + 1011 or 0001+ 1011 = 1100</em>

The result (1100), of the addition of the two numbers, is a negative number as the MSB is 1.

Convert it to it's positive counterpart.

i.e 1100 => 0011 + 1 = 0100.

Converting the result (0100) to decimal gives

0100 = 0 x 2^{3} + 1 x 2^{2} + 0 x 2^{1} + 0 x 2^{0} = 4

Therefore, the result, 1100 is -4 in decimal.

===================================================

(b) 11 + 01010101

Convert the two numbers into their 8-bit representation since one of them is in 8-bit.

PS: Taking 11, its MSB is 1 showing that it is a negative number. Also, it's 8-bit representation will mean pre-padding it with ones(1s) rather than zeros as follows. In other words, pre-padding a 2's complement  number is done using its sign bit.

=> 11 = 11111111

=> 01010101

Addition of the two numbers (in their 2's complement form) gives the following:

  1  1  1  1  1  1  1  1       ------------------> - 1 (in decimal)

<u>   0 1  0 1  0  1 0 1 </u>      ------------------> + 85 (in decimal)

<u>1 0 1  0 1  0  1 0 0</u>    ------------------->  + 84 (in decimal)

Discard the carry-out bit (1) making the result 01010100

Explanation for (b)

<em>11 or 11111111</em>

Its MSB is 1 showing that it is negative.

Convert it to it's positive counterpart.

11111111 => 00000000 + 1 = 00000001

Converting the result (00000001) to decimal gives 1

11 or 11111111 is  - 1 in decimal.

<em>01010101</em>

Its MSB is 0 showing that it is also positive. Now, convert to decimal

01010101 = 85

01010101 is + 85 in decimal.

<em>11111111 + 01010101 = 01010100</em>

The result (01010100), is also positive as the MSB is 0. Now, convert to decimal.

01010100 = 84

Therefore the result (01010100) is + 84 in decimal.

===================================================

(c) 0101 + 110

Convert the two numbers into their 4-bit representations.

=> 0101 = 0101

=> 110 = 1110

Addition of the two numbers (in their 2's complement form) gives the following:

     0 1 0 1       ------------------> + 5 (in decimal)

<u>      1  1 1  0 </u>      -----------------> - 2 (in decimal)

<u>   1 0 0 1  1 </u>    -------------------> + 3 (in decimal)

Dicard the carry-out bit (leftmost bit) to get 0011 as result.

Explanation for (c)

<em>0101</em>

Since the MSB is 0 (leftmost bit), it shows that it is a positive number. Now, convert to decimal.

0101 =  5

0101 is +5 in decimal.

<em>110 or 1110</em>

Its MSB is 1 showing that it is negative.

Convert it to it's positive counterpart.

i.e 1110 => 0001 + 1 = 0010.

Converting the result (0010) to decimal gives

0010 =  2

1110 is -2 in decimal

<em>0101 + 110 = 0101+ 1110 = 0011</em>

The result (0011), is a positive number as the MSB is 0.

Converting the result (0011) to decimal gives

0011 = 3

Therefore, the result, 0011 is 3 in decimal.

===================================================

(d) 01 + 10

Convert the two numbers into their 4-bit representation.

=> 01 = 0001

=> 10 = 1110

Addition of the two numbers (in their 2's complement form) gives the following:

0 0 0 1       ------------------> + 1 (in decimal)

<u>1  1  1  0 </u>      ------------------> - 2 (in decimal)

<u>1  1  1  1 </u>    -------------------> - 1 (in decimal)

Explanation for (d)

<em>01 or 0001</em>

Since the MSB is 0 (leftmost bit), it shows that it is a positive number. Now convert to decimal.

0001 = 1

0001 is + 1 in decimal.

<em>1110</em>

Its MSB is 1 showing that it is negative.

Convert it to it's positive counterpart.

i.e 1110 => 0001 + 1 = 0010.

Converting the result (0010) to decimal gives

0010  = 2

1110 is -2 in decimal

<em>01 + 1011 or 0001+ 1110 = 1111</em>

The result (1111), is a negative number as the MSB is 1.

Convert it to it's positive counterpart.

i.e 1111 => 0000 + 1 = 0001.

Converting the result (0001) to decimal gives

0001 = 1

Therefore, the result, 1111 is -1 in decimal.

7 0
2 years ago
Let's assume that the smallest possible message is 64 bytes (including the 33-byte overhead). if we use 100base-t, how long (in
Ostrovityanka [42]

As we know that 10-bAse data travels at the rate of 10 mbps, therefore at 1 sec we have 10240 bytes.

We have to calculate for 64 bytes travelling in one second. Multiply both sides by 64.

64 sec = 10240 x 64 bytes

64 bytes = 64 / 10240 sec

Now we have to calculate for light of speed

1 sec = 186000 miles

Substitute this value to the formula above

64 bytes = 64 / 10240 x 1 sec = 64 / 10240 x 186000 miles = 64 / 10240 x 186000 x 5280 feet = 6138x10^3 feet

Therefore, 64 bytes is equal to 6138 x 10^3 feet long message

3 0
2 years ago
A shipping company uses the following function to calculate the cost in dollars of shipping based on the weight of the package (
Gwar [14]

Answer:

I am writing the code in JAVA and C++. Let me know if you want the code in some other programming language. Both the programs works the same but the only difference is that i have used logical operator AND (&&) with C++ code to check each condition.

JAVA code:

import java.util.Scanner;    // to take input from the user

public class ShippingCost {  // ShippingCost class

public static void main(String[] args) {   // main method entry to the program

Scanner input = new Scanner(System.in);  //allows to take input from user

System.out.print("please enter the weight of the package: "); /*prompts the user to enter the weight of package.*/

double weight = input.nextDouble();  /*reads and stores the input values(weight) entered by the user*/

       double cost=0;  //holds the value of cost

 if (weight<=0)  /* checks if the user enters weight value less than or equals to 0 */

 { System.out.println("invalid input."); //prints invalid input

     System.exit(0); //exits the program

 }

    else if (weight > 0 && weight <= 1)  /*if weight is greater than 0 and less than or equal to 1*/

   cost = 3.5;  /*if the above condition is true then it stores the value 3.5 in cost variable */

 else if (weight <= 3)  // if value of weight is less than or equal to 3

   cost = 5.5;  /*if the above condition is true then it stores the value 5.5 in cost variable */

 else if (weight <= 10)  // if value of weight is less than or equal to 10

   cost = 8.5;  /*if the above condition is true then it stores the value 8.5 in cost variable */

 else if (weight <= 20)  // if value of weight is less than or equal to 20

   cost = 10.5;/*if the above condition is true then it stores the value 10.5 in cost variable */

 else  // if the value of weight is greater than 20

 {  System.out.println("The package cannot be shipped");

// displays package cannot be shipped

      System.exit(0);  //exits the program if weight>20}

 System.out.println("The shipping cost is: $" + cost);     /*prints the value stored in the cost from any of the above conditions */

} }

C++ Code

#include <iostream>//to use input output functions

using namespace std;

int main() // start of main() function body

{ double weight; //stores weight value

   double cost= 0; //stores cost value

cout << "please enter the weight of the package:" << endl;

//prompts user to enter the weight

cin >> weight;    

//reads the value of weight entered by the user

  if (weight<=0) //if value of weight entered by user is less than or equal to 0

 { cout<<"invalid input."; //displays invalid input

     exit(0); //exits the program

 }

/*the below else if conditions are checked, if any one of them is true then the cost displayed in the output will be the which is assigned to cost variable of that specific if condition's body which evaluates to true. */

    else if (weight > 0 && weight <= 1)

   cost = 3.5;

 else if (weight > 1 && weight <=3)

   cost = 5.5;

 else if (weight > 3 && weight <= 10)

   cost = 8.5;

 else if (weight> 10 && weight <= 20)

   cost = 10.5;

 else //if weight>20

//displays the message below and exits the program

 {  cout<<"The package can not be shipped";

      exit(0); }

 cout<<"The shipping cost is: $"<<cost;  /*displays the value stored in cost variable of that else-if condition which evaluates to true */

}

Explanation:

Everything is well explained in the comments above. I will summarize it all.

The program takes the input weight from the user and checks the value of weight.

If and else-if conditions are used to check the value of weight.

if the value of weight is less than 0 or equal to 0 then invalid input is displayed.

Else the weight value is checked for the given ranges. && operator is used in each else if statement which is used to specify the range of the weight values the input weight should be in order to display the shipping cost.

For example take this statement: else if (weight > 0 && weight <= 1)

This statement checks the value entered by the user that if it lies in the range mentioned in this statement which is that the weight value should be greater than 0 AND less than or equal to 1. The value cannot lie above or below the given range in order for this condition to be true so && operator is used here.

If the weight entered by user exceeds 20 then the message is displayed:The package can not be shipped and the program exits. In JAVA System.exit(0) and in c++ exit(0) function is used to exit the program.

The output of both the programs is as following:

please enter the weight of the package: 3

The shipping cost is: $ 5.5

8 0
2 years ago
At one college, the tuition for a full-time student is $8,000 per semester. It has been announced that the tuition will increase
inn [45]

Answer:

#include <iostream>

using namespace std;

 

int main () {

  // for loop execution

  int semester_fees=8000;

  int b=1;

  cout<<"there are 5 years or 10 semester fees breakdown is given below"<<endl;

  for( int a = 1; a <=5; a++ ) {

     semester_fees = semester_fees*1.03;

     cout<<"Semester fees for each of semester"<<b++<<"and"<<b++<<"is:$"<<semester_fees<<endl;

     

  }

 

  return 0;

}

Explanation:

code is in c++ language

Fees is incremented yearly and i have considered only two semester per year

3 0
1 year ago
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