It could be old ... could be your connection to the internet... could be a virus. You can go to walmart or your super store and buy a usb for your computer. There are ones that can speed up your computer. I had to buy it for mine and it worked. It might be over 20 dollars depends on where you go.
Answer:
offline backup solution
Explanation:
In such a scenario, the best option would be an offline backup solution. This is basically a local and offline server that holds all of the flight record data that the cloud platform has. This offline backup server would be updated frequently so that the data is always up to date. These servers would be owned by the aviation company and would be a secondary solution for the company in case that the cloud platform fails or the company cannot connect to the cloud service for whatever reason. Being offline allows the company to access the database regardless of internet connectivity.
<span>C. proofread her work carefully, ask a coworker to look it over, and correct all mistakes
</span>
Answer:
// here is code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int n,no_open=0;
cout<<"enter the number of lockers:";
// read the number of lockers
cin>>n;
// initialize all lockers with 0, 0 for locked and 1 for open
int lock[n]={};
// toggle the locks
// in each pass toggle every ith lock
// if open close it and vice versa
for(int i=1;i<=n;i++)
{
for(int a=0;a<n;a++)
{
if((a+1)%i==0)
{
if(lock[a]==0)
lock[a]=1;
else if(lock[a]==1)
lock[a]=0;
}
}
}
cout<<"After last pass status of all locks:"<<endl;
// print the status of all locks
for(int x=0;x<n;x++)
{
if(lock[x]==0)
{
cout<<"lock "<<x+1<<" is close."<<endl;
}
else if(lock[x]==1)
{
cout<<"lock "<<x+1<<" is open."<<endl;
// count the open locks
no_open++;
}
}
// print the open locks
cout<<"total open locks are :"<<no_open<<endl;
return 0;
}
Explanation:
First read the number of lockers from user.Create an array of size n, and make all the locks closed.Then run a for loop to toggle locks.In pass i, toggle every ith lock.If lock is open then close it and vice versa.After the last pass print the status of each lock and print count of open locks.
Output:
enter the number of lockers:9
After last pass status of all locks:
lock 1 is open.
lock 2 is close.
lock 3 is close.
lock 4 is open.
lock 5 is close.
lock 6 is close.
lock 7 is close.
lock 8 is close.
lock 9 is open.
total open locks are :3
Answer:
he should cite the websites of where he got his information.
Explanation:
