Answer:
See explaination
Explanation:
StackExample.java
public class StackExample<T> {
private final static int DEFAULT_CAPACITY = 100;
private int top;
private T[] stack = (T[])(new Object[DEFAULT_CAPACITY]);
/**
* Returns a reference to the element at the top of this stack.
* The element is not removed from the stack.
* atreturn element on top of stack
* atthrows EmptyCollectionException if stack is empty
*/
public T peek() throws EmptyCollectionException
{
if (isEmpty())
throw new EmptyCollectionException("stack");
return stack[top-1];
}
/**
* Returns true if this stack is empty and false otherwise.
* atreturn true if this stack is empty
*/
public boolean isEmpty()
{
return top < 0;
}
}
//please replace "at" with the at symbol
Note:
peek() method will always pick the first element from stack. While calling peek() method when stack is empty then it will throw stack underflow error. Since peek() method will always look for first element ffrom stack there is no chance for overflow of stack. So overflow error checking is not required. In above program we handled underflow error in peek() method by checking whether stack is an empty or not.
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Answer:
Available Options are :
A <b>
B <l>
C <body>
D <small>
Ans : A <b>
Explanation:
Normally AD and BC are written in bold letters.
for example : The terms anno Domini (AD) and before Christ (BC).
Within available option the best option to choose is <b>
The <body> element used to define the document body.
The <small> tag used to defines smaller text
But, the best option to choose is in case if they are using the HTML5 then html <time> element will be used to display BC date and AD dates.
for ex : <time datetime="-314-07-01"
calendar="Ancient Roman">1 July 314 BC</time>
Answer: b. 11
Explanation:
//The initial value is 1
//let call the value as x
x = 1
//then the user updated the value to 10
//so now x is 10
x = 10
// and update the workflow to 11
//so now the value of x is 11
x = 11
even if the programmer print x, so the output will be 11
Answer:
def words_in_both(a, b):
a1 = set(a.lower().split())
b1 = set(b.lower().split())
return a1.intersection(b1)
common_words = words_in_both("She is a jack of all trades", 'Jack was tallest of all')
print(common_words)
Explanation:
Output:
{'all', 'of', 'jack'}
