Answer:
This is a multicolinearity problem and the student should determine the variable(s) that cause(s) the problem and remove it.
Explanation:
This information means that there exists a linear combination between the independent variables. The problem might have developed due to multicolinearity producing almost perfectly linearly dependent columns.
This could also be as a results of single matrix created when the student use an incorrect indicator variables and included an additional indicator column which created linearly dependent columns.
Base on the question, and in my further computation, the possible answers would be the following and I hope you are satisfied with my answer and feel free to ask for more.
- If you want to determine the Thevenin equivalent voltage and resistance without overloading the battery, then apply some known resistance
<span><span>RL</span><span>RL</span></span> and measure the output voltage as <span><span>VL</span><span>VL</span></span>. Measure the voltage without a load as <span><span>V<span>OC</span></span><span>V<span>OC</span></span></span>. The voltage divider equation tells us that
<span><span><span>VL</span>=<span>V<span>OC</span></span><span><span>RL</span><span><span>R<span>TH</span></span>×<span>RL</span></span></span></span><span><span>VL</span>=<span>V<span>OC</span></span><span><span>RL</span><span><span>R<span>TH</span></span>×<span>RL</span></span></span></span></span>
Solve for <span><span>R<span>TH</span></span><span>R<span>TH</span></span></span>, and you know that <span><span><span>V<span>TH</span></span>=<span>V<span>OC</span></span></span><span><span>V<span>TH</span></span>=<span>V<span>OC</span></span></span></span>.
Answer:
Python Code:
def validate_url(url):
#Creating the list of valid protocols and file name extensions
valid_protocols = ['http', 'https', 'ftp']
valid_fileinfo = ['.html', '.csv', '.docx']
#splitting the url into two parts
url_split = url.split('://')
isProtocolValid = False
isFileValid = False
#iterating over the valid protocols and file names for validity
for x in valid_protocols:
if x in url_split[0]:
isProtocolValid = True
break
for x in valid_fileinfo:
if x in url_split[1]:
isFileValid = True
break
#Returning the result if the URL has both valid protocol and file extension
return (isProtocolValid and isFileValid)
url = input("Enter an URL: ")
print(validate_url(url))
Explanation:
The image of the output code is attached. Hope it helps.
Because the string is invalid or your source is not attached to your search engine.
