get int input for a
get int input for b
get string input for operator
if a is not int or b is not int throw exception and print error
if operator is not * / // or % throw exception and print error
if operator is * do multiplication of a and b and make answer c
else if operator is / do division of a and b and make answer c
else if operator is // do floor division of a and b and make answer c
else if operator is % do floor modulo of a and b and make answer c
print c
Answer: Machine learning
Explanation:
The technology that could be combined with the current solution to do this is the machine learning.
Machine learning refers to the use and development of the computer systems which can learn and adapt without them following explicit instructions. This is done through the use of statistical models and algorithms in order to analyse inferences from the patterns in data.
Since the bank wants to streamline their operations for the receiving and processing checks while also enhancing the solution to recognize signs of potential check fraud, then the machine learning can be used.
The TCP/IP stack is responsible for the "chopping up" into packets of the data for transmission and for their acknowledgment. Depending on the transport protocol that is used (TCP or UDP) each packet will be <span>acknowledged or not, respectively.
</span><span>the strategy when the file is chopped up into packets, which are individually acknowledged by the receiver, but the file transfer as a whole is not acknowledged is OK in situations (Applications) that do not need the whole file to be sent, Web site for example: different parts of the web site can arrive in different times.
The other strategy, in which </span><span>the packets are not acknowledged individually, but the entire file is acknowledged when it arrives is suitable for FTP (mail transfer), we need whole mail, not parts of it. </span>
Answer:
C code explained below
Explanation:
#include <stdio.h>
#include <stdbool.h>
int main(void) {
int userNum;
bool isPositive;
bool isEven;
scanf("%d", &userNum);
isPositive = (userNum > 0);
isEven = ((userNum % 2) == 0);
if(isPositive && isEven){
printf("Positive even number");
}
else if(isPositive && !isEven){
printf("Positive number");
}
else{
printf("Not a positive number");
}
printf("\n");
return 0;
}
Answer:
Explanation:
temporal locality can be defined as: when a particular memory is referenced or accessed several times within a specific period of time. In the question, i think the variable that exhibit temporal locality are I, J and 0(all the variable). This is because the variable J and 0 are accessed several times within the loop. I would not have been part of it, but in the A[I][J]=B[I][0]+A[J][I], the variable "I" is also accessed in the addition. this is why it is part of the temporal locality.
