The term load is often used to describe opening a page in a ___

OH GOD PLEASE HELP I CAN'T FIGURE THIS OUT-

Angelina_Jolie [31]

Answer:

what does that even mean like what is the problem in the question

5 0

2 years ago

Describe how the process of sampling, RGB pixels, and binary sequences work together to display a digital color image

Rina8888 [55]

Explanation:

Sampling and RBG (red blue green) pixels and also the binary sequences working together such that it display any digitally colored image by allowing the computer system know where the Red Blue Green pixel is going to be placed and also what the opacity would be for that pixel. The combination of these components is what gives you a digital color image.

5 0

2 years ago

A 1.17 g sample of an alkane hydrocarbon gas occupies a volume of 674 mL at 28°C and 741 mmHg. Alkanes are known to have the gen

Nina [5.8K]

Answer:

C3H8

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Mass of alkane = 1.17g

Volume (V) = 674 mL

Temperature (T) = 28°C

Pressure (P) = 741 mmHg.

Gas constant (R) = 0.08206 atm.L/Kmol

Step 2:

Conversion to appropriate unit.

For Volume:

1000mL = 1L

Therefore, 674mL = 674/1000 = 0.674L

For Temperature:

Temperature (Kelvin) = Temperature (celsius) + 273

Temperature (celsius) = 28°C

Temperature (Kelvin) = 28°C + 273 = 301K

For Pressure:

760mmHg = 1atm

Therefore, 741 mmHg = 741/760 = 0.975atm

Step 3:

Determination of the number of mole of the alkane..

The number of mole of the alkane can be obtained by using the ideal gas equation. This is illustrated below:

Volume (V) = 0.674L

Temperature (T) = 301K

Pressure (P) = 0.975atm

Gas constant (R) = 0.08206 atm.L/Kmol

Number of mole (n) =?

PV = nRT

n = PV /RT

n = (0.975 x 0.674)/(0.08206x301)

n = 0.0266 mole

Step 4:

Determination of the molar mass of the alkane.

Mass of alkane = 1.17g

Number of mole of the alkane = 0.0266mole

Molar Mass of the alkane =?

Number of mole = Mass/Molar Mass

Molar Mass = Mass/number of mole

Molar Mass of the alkane = 1.17/0.0266 = 44g/mol

Step 5:

Determination of the molecular formula of the alkane.

This is illustrated below:

The general formula for the alkane is CnH2n+2

To obtain the molecular formula for the alkane we shall assume n = 1, 2, 3 or more till we arrive at molar Mass of 44.

When n = 1

CnH2n+2 = CH4 = 12 + (4x1) = 16g/mol

When n = 2

CnH2n+2 = C2H6 = (12x2) + (6x1) = 30g/mol

When n = 3

CnH2n+2 = C3H8 = (12x3) + (8x1) = 44g/mol

We can see that when n is 3, the molar mass is 44g/mol.

Therefore, the molecular formula for the alkane is C3H8.

7 0

2 years ago

Write the recursive function max_depth; it is passed a binary (any binary tree, not necessarily a binary search tree) and a valu

OleMash [197]

Answer:

A python code was used in writing of the recursive function max_depth; and passed a binary (any binary tree, not necessarily a binary search tree) and a value as arguments.

Explanation:

Solution

To solve this given question we make use of Python programming language.

Thus

THE CODE:

class BinaryTreeNode:

def __init__(self, value, left=None, right=None):

self.value = value

self.left = left

self.right = right

# recursive max_depth function implementation

def max_depth(tree, value):

if tree == None:

return -1

# recursive calls to this function

leftDepth = max_depth(tree.left, value)

rightDepth = max_depth(tree.right, value)

# return the maximum depth

if tree.value == value or leftDepth > -1 or rightDepth > -1:

return 1 + max(leftDepth, rightDepth)

else:

return max(leftDepth, rightDepth)

btn1 = BinaryTreeNode(2)

btn2 = BinaryTreeNode(3, None, btn1)

btn3 = BinaryTreeNode(3)

btn4 = BinaryTreeNode(3)

btn5 = BinaryTreeNode(2, btn2, btn3)

btn6 = BinaryTreeNode(1, btn4)

tree = BinaryTreeNode(3, btn5, btn6)

print('max_depth(tree, 1):',max_depth(tree, 1))

print('max_depth(tree, 2):',max_depth(tree, 2))

print('max_depth(tree, 3):',max_depth(tree, 3))

Note: Kindly find an attached copy of the Implementation of max_depth() function, Code to test the max_depth() function and the sample output below.

8 0

2 years ago

Computers represent color by combining the sub-colors red, green, and blue (rgb). Each sub-color's value can range from 0 to 255

maxonik [38]

Answer:

Follows are the code to this question:

#include <iostream>//defining a header file

using namespace std; //using namespace

int main() //defining main method

{

int red,green,blue,s; //defining integer variable

cout<<"Enter value: \n ";//print message

cin>>red>>green>>blue; //input value

if(red<green && red<blue)//defining if block that checks red value

s=red;//store red variable value to s variable

else if(green<blue)//defining else if block that checks green value less then blue

s=green;//store green variable value in s variable

else//defining else block

s=blue; //store blue variable value in s variable

//calculating red, green, blue value

red=red-s;//store red value

green=green-s;//store green value

blue=blue-s;//store blue value

cout<<red<<" "<<green<<" "<<blue;

}

Output:

Enter value:

130

50

130

80 0 80

Explanation:

In the above code, inside the Main method, four integer variable "red, green, blue, and s" is defined, in which "red, green, and blue" is used for input the value from the user end.

In the next step, a conditional statement is used, that checks the red variable value, if the condition is true, it will store its value in the "s" variable, otherwise, it will go to else if block.
In this block, the green variable checks its value less than then blue variable value, if the condition is true, it will store the green value in the "s" variable, otherwise, it will goto else block.
In this block, it will store the blue variable value in the "s" variable, and subtract the value of "red, green, and blue" value from "s" and store its value, and at the last, it will print its value.

4 0

2 years ago

The term load is often used to describe opening a page in a ____. Answer