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IgorLugansk [536]
2 years ago
5

Read the four detective reports and the combined affidavit and warrant for the M57 Patents case. Write a one- to two-page paper

describing the evidence the police found and explaining whether they had enough information for the search warrant. Did the information justify taking all the computers and USB drives
Computers and Technology
1 answer:
Fantom [35]2 years ago
4 0

Answer:The 2009-M57-Patents scenario tracks the first four weeks of corporate history of the M57 Patents company. The company started operation on Friday, November 13th, 2009, and ceased operation on Saturday, December 12, 2009. As might be imagined in the business of outsourced patent searching, lots of other activities were going on at M57-Patents.

Two ways of working the scenario are as a disk forensics exercise (students are provided with disk images of all the systems as they were on the last day) and as a network forensics exercise (students are provided with all of the packets in and out of the corporate network). The scenario data can also be used to support computer forensics research, as the hard drive of each computer and each computer’s memory were imaged every day.

Explanation:

You might be interested in
Instead of sending an entire file in one big chunk across the​ Internet, __________ is used which dices the file up into little
azamat

Answer:

TCP/IP

Explanation:

TCP/IP which stands for Transmission Control Protocol and Internet Protocol are network protocols which divide your message into smaller chunks or fragments known as network packets and sends them out onto the Internet. When the chunks arrive at the intended destination, TCP/IP on the receiving end reassembles the network packets into the original message.

TCP/IP are the main protocols used for sending data over the internet.

7 0
2 years ago
Write a function addOddMinusEven that takes two integers indicating the starting point and the end point. Then calculate the sum
snow_lady [41]

Answer:g

   public static int addOddMinusEven(int start, int end){

       int odd =0;

       int even = 0;

       for(int i =start; i<end; i++){

           if(i%2==0){

               even = even+i;

           }

           else{

               odd = odd+i;

           }

       }

       return odd-even;

   }

}

Explanation:

Using Java programming language:

  • The method addOddMinusEven() is created to accept two parameters of ints start and end
  • Using a for loop statement we iterate from start to end but not including end
  • Using a modulos operator we check for even and odds
  • The method then returns odd-even
  • See below a complete method with a call to the method addOddMinusEven()

public class num13 {

   public static void main(String[] args) {

       int start = 2;

       int stop = 10;

       System.out.println(addOddMinusEven(start,stop));

   }

   public static int addOddMinusEven(int start, int end){

       int odd =0;

       int even = 0;

       for(int i =start; i<end; i++){

           if(i%2==0){

               even = even+i;

           }

           else{

               odd = odd+i;

           }

       }

       return odd-even;

   }

}

8 0
2 years ago
Locker doors There are n lockers in a hallway, numbered sequentially from 1 to n. Initially, all the locker doors are closed. Yo
kow [346]

Answer:

// here is code in C++

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

   // variables

   int n,no_open=0;

   cout<<"enter the number of lockers:";

   // read the number of lockers

   cin>>n;

   // initialize all lockers with 0, 0 for locked and 1 for open

   int lock[n]={};

   // toggle the locks

   // in each pass toggle every ith lock

   // if open close it and vice versa

   for(int i=1;i<=n;i++)

   {

       for(int a=0;a<n;a++)

       {

           if((a+1)%i==0)

           {

               if(lock[a]==0)

               lock[a]=1;

               else if(lock[a]==1)

               lock[a]=0;

           }

       }

   }

   cout<<"After last pass status of all locks:"<<endl;

   // print the status of all locks

   for(int x=0;x<n;x++)

   {

       if(lock[x]==0)

       {

           cout<<"lock "<<x+1<<" is close."<<endl;

       }

       else if(lock[x]==1)

       {

           cout<<"lock "<<x+1<<" is open."<<endl;

           // count the open locks

           no_open++;

       }

   }

   // print the open locks

   cout<<"total open locks are :"<<no_open<<endl;

return 0;

}

Explanation:

First read the number of lockers from user.Create an array of size n, and make all the locks closed.Then run a for loop to toggle locks.In pass i, toggle every ith lock.If lock is open then close it and vice versa.After the last pass print the status of each lock and print count of open locks.

Output:

enter the number of lockers:9

After last pass status of all locks:

lock 1 is open.

lock 2 is close.

lock 3 is close.

lock 4 is open.

lock 5 is close.

lock 6 is close.

lock 7 is close.

lock 8 is close.

lock 9 is open.

total open locks are :3

5 0
2 years ago
Dan is a Civil Engineer for a company that builds nuclear power plants throughout the world. Which best describes the places he
Yanka [14]
IN a laboratory... C 
4 0
2 years ago
Read 2 more answers
Write the prototype for a function named showSeatingChart that will accept the following two-dimensional array as an argument. c
barxatty [35]

Answer:

See explaination

Explanation:

void showSeatingChart(string seatingChart[20][40], const int ROWS, const int COLS){

for(int i = 0;i<ROWS;i++){

for(int j = 0;j<COLS;j++){

cout<<seatingChart[i][j]<<" ";

}

cout<<endl;

}

}

4 0
2 years ago
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