Which data type stores images and audio visual clips?

There are two cons to an OLTP database. Which of the following are a solution of these cons?

Delicious77 [7]

Answer:

The answer is below

Explanation:

An OLTP (Online transaction processing) database is a database that allows for quick transaction processing. It involves inserting, deleting, updating data in the database.

OLTP has many drawbacks like if the system fails, all transactions are going to have problems. Also, since multiple users are allowed to access the data, it makes it prone to hackers.

The solution to the problems associated to the OLTP database is the OLAP (online analytical processing) database.

The OLAP systems allow users to analyze database information from multiple database systems at one time thereby allowing analysis for business decisions.

6 0

2 years ago

Consider the following skeletal C program: void fun1(void); /* prototype */ void fun2(void); /* prototype */ void fun3(void); /*

natita [175]

Answer:

Check the explanation

Explanation:

a) main calls fun1; fun1 calls fun2; fun2 calls fun3

fun3() d, e, f

fun2() c, d, e

fun1() b, c, d

main() a, b,c

CALL STACK SHOWING THE VARIABLES OF EVERY FUNCTION

From the above call stack diagram, it is very clear that the last function call is made to fun3().

In fun3(), the local variables "d, e, f" of fun3() will be visible

variable "c" of fun2() will be visible

variable "b" of fun1() will be visible

variable "a" of main() will be visible

b) main calls fun1; fun1 calls fun3

fun3() d, e, f

fun1() b, c, d

main() a, b,c

CALL STACK SHOWING THE VARIABLES OF EVERY FUNCTION

From the above call stack diagram, it is very clear that the last function call is made to fun3().

In fun3(), the local variables "d, e, f" of fun3() will be visible

variable "b, c" of fun1() will be visible

variable "a" of main() will be visible

c) main calls fun2; fun2 calls fun3; fun3 calls fun1

fun1() b, c, d

fun3() d, e, f

fun2() c, d, e

main() a, b,c

CALL STACK SHOWING THE VARIABLES OF EVERY FUNCTION

From the above call stack diagram, it is very clear that the last function call is made to fun1().

In fun1(), the local variables "b, c, d" of fun1() will be visible

variable "e, f" of fun3() will be visible

variable "a" of main() will be visible

d) main calls fun1; fun1 calls fun3; fun3 calls fun2

fun2() c, d, e

fun3() d, e, f

fun1() b, c, d,

main() a, b,c

CALL STACK SHOWING THE VARIABLES OF EVERY FUNCTION

From the above call stack diagram, it is very clear that the last function call is made to fun2().

In fun2(), the local variables "c, d, e" of fun2() will be visible

variable "f" of fun3() will be visible

variable "b" of fun1() will be visible

variable "a" of main() will be visible

The last function called will comprise of all its local variables and the variables other than its local variables from all its preceding function calls till the main function.

8 0

1 year ago

The groups_per_user function receives a dictionary, which contains group names with the list of users. Users can belong to multi

Akimi4 [234]

The groups_per_user function receives a dictionary, which contains group names with the list of users.

Explanation:

The blanks to return a dictionary with the users as keys and a list of their groups as values is shown below :

def groups_per_user(group_dictionary):

user_groups = {}

# Go through group_dictionary

for group,users in group_dictionary.items():

# Now go through the users in the group

for user in users:

# Now add the group to the the list of

# groups for this user, creating the entry

# in the dictionary if necessary

user_groups[user] = user_groups.get(user,[]) + [group]

return(user_groups)

print(groups_per_user({"local": ["admin", "userA"],

"public": ["admin", "userB"],

"administrator": ["admin"] }))

3 0

2 years ago

A windows host sends a tcp segment with source port number 1200 and destination port number 25. the sending host is a(n) _______

tigry1 [53]

Email client as port 25 is the default port for an email server.

6 0

1 year ago

Suppose you are given an unknown chip which could be any one of the of the following: 7400, 7402, 7404, 7408, 7410, 7420, 7427,

Olenka [21]

The answer & explanation for this question is given in the attachment below.

3 0

1 year ago