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Alexeev081 [22]
1 year ago
13

_____ is the process of adjusting colors in an image.

Computers and Technology
2 answers:
Luden [163]1 year ago
7 0

Answer:

Color balancing

Explanation:

i just got it right

navik [9.2K]1 year ago
4 0
Colour grading is the process that is used to change the visual tone of an image
You might be interested in
Under what category of programs and apps do databases and enterprise computing fall?
Evgesh-ka [11]
Answer is productivity

Sometimes called the office or personal productivity software, productivity software is dedicated to producing databases, spreadsheets, charts, graphs, documents, graphs, digital video and worksheets. Reason behind the name productivity is due to the fact that it increases productivity in office work.

6 0
2 years ago
8.Change the following IP addresses from binary notation to dotted-decimal notation: a.01111111 11110000 01100111 01111101 b.101
Andrews [41]

Answer:

a. 01111111 11110000 01100111 01111101 dotted decimal notation:

(127.240.103.125)

b. 10101111 11000000 11111000 00011101 dotted decimal notation: (175.192.248.29)

c. 11011111 10110000 00011111 01011101 dotted decimal notation:

(223.176.31.93)

d. 11101111 11110111 11000111 00011101 dotted decimal notation:

(239.247.199.29)

a. 208.34.54.12 class is C

b. 238.34.2.1 class is D

c. 242.34.2.8 class is E

d. 129.14.6.8 class is B

a.11110111 11110011 10000111 11011101 class is E

b.10101111 11000000 11110000 00011101 class is B

c.11011111 10110000 00011111 01011101 class is C

d.11101111 11110111 11000111 00011101 class is D

Explanation:

8 a. 01111111 11110000 01100111 01111101

we have to convert this binary notation to dotted decimal notation.

01111111 = 0*2^7 + 1*2^6 + 1*2^5 + 1*2^4 + 1*2^3 + 1*2^2 + 1*2^1 + 1*2^0

           = 0 + 1*64 + 1*32 + 1*16 + 1*8 + 1*4 + 1*2 + 1

           = 64 + 32 + 16 + 8 + 4 + 2 + 1

           = 127

11110000 = 1*2^7 + 1*2^6 + 1*2^5 + 1*2^4 + 0*2^3 + 0*2^2 + 0*2^1 + 0*2^0

               = 1*128 + 1*64 + 1*32 + 16 + 0 + 0 + 0 + 0

               = 128 + 64 + 32 + 16

               = 240

01100111 = 0*2^7 + 1*2^6 + 1*2^5 + 0*2^4 +0*2^3 + 1*2^2 + 1*2^1 + 1*2^0

               = 0 + 1*64 + 1*32 + 0 + 0 + 4 + 2 + 1

               = 64 + 32 + 4 + 2 + 1

               = 103

01111101   = 0*2^7 + 1*2^6 + 1*2^5+ 1*2^4 +1*2^3 +1*2^2 + 0*2^1 + 1*2^0

               = 0 + 1*64 + 1*32 + 1*16 + 1*8 + 1* 4 + 0 + 1

               = 64 + 32 + 16 + 8 + 4 + 1

               = 125

So the IP address from binary notation 01111111 11110000 01100111 01111101 to dotted decimal notation is : 127.240.103.125

b) 10101111 11000000 11111000 00011101

10101111 = 1*2^7 + 0*2^6 + 1*2^5 + 0*2^4 + 1*2^3 + 1*2^2 + 1*2^1 + 1*2^0

             = 175

11000000 = 1*2^7 + 1*2^6 + 0*2^5 + 0*2^4 + 0*2^3 + 0*2^2 + 0*2^1 + 0*2^0

                 = 192

11111000 = 1*2^7 + 1*2^6 + 1*2^5 + 1*2^4 +1*2^3 + 0*2^2 + 0*2^1 + 0*2^0

              = 248

00011101 = 0*2^7 + 0*2^6 + 0*2^5 + 1*2^4 +1*2^3 + 1*2^2 + 0*2^1 + 1*2^0

               = 29

So the IP address from binary notation 10101111 11000000 11111000 00011101  to dotted decimal notation is : 175.192.248.29

c) 11011111 10110000 00011111 01011101

11011111 = 1*2^7 + 1*2^6 + 0*2^5 + 1*2^4 +1*2^3 + 1*2^2 + 1*2^1 + 1*2^0

           = 223

10110000 =  1*2^7 + 0*2^6 + 1*2^5 + 1*2^4 +0*2^3 + 0*2^2 + 0*2^1 + 0*2^0

                = 176

00011111 = 0*2^7 + 0*2^6 + 0*2^5 + 1*2^4 +1*2^3 + 1*2^2 + 1*2^1 + 1*2^0

              = 31

01011101 = 0*2^7 + 1*2^6 + 0*2^5 + 1*2^4 +1*2^3 + 1*2^2 + 0*2^1 + 1*2^0

              = 93

So the IP address from binary notation 11011111 10110000 00011111 01011101 to dotted decimal notation is :223.176.31.93

d) 11101111 11110111 11000111 00011101

11101111 = 1*2^7 + 1*2^6 + 1*2^5 + 0*2^4 +1*2^3 + 1*2^2 + 1*2^1 + 1*2^0

            = 239

11110111 = 1*2^7 + 1*2^6 + 1*2^5 + 1*2^4 +0*2^3 + 1*2^2 + 1*2^1 + 1*2^0

           = 247

11000111 =  1*2^7 + 1*2^6 + 0*2^5 + 0*2^4 +0*2^3 + 1*2^2 + 1*2^1 + 1*2^0

              = 199

00011101 = 0*2^7 + 0*2^6 + 0*2^5 + 1*2^4 +1*2^3 + 1*2^2 + 0*2^1 + 1*2^0

               = 29

So the IP address from binary notation 11101111 11110111 11000111 00011101 to dotted decimal notation is : 239.247.199.29

9. In order to the find the class check the first byte of the IP address which is first 8 bits and check the corresponding class as follows:                

Class A is from 0 to 127

Class B is from 128 to 191

Class C is from 192 to 223

Class D is from 224 to 239

Class E is from 240 to 255

a. 208.34.54.12

If we see the first byte of the IP address which is 208, it belongs to class C as class C ranges from 192 to 223.

b. 238.34.2.1

If we see the first byte of the IP address which is 238, it belongs to class D as Class D ranges from 224 to 239.

c. 242.34.2.8

If we see the first byte of the IP address which is 242, it belongs to class E as Class E ranges from 240 to 255.

d. 129.14.6.8

If we see the first byte of the IP address which is 129, it belongs to class B as Class B ranges from 128 to 191.

10. In order to find the class of the IP addresses in easy way, start checking bit my bit from the left of the IP address and follow this pattern:

0 = Class A

1 - 0 = Class B

1 - 1 - 0 = Class C

1 - 1 - 1 - 0 = Class D

1 - 1 - 1 - 1 = Class E

a. 11110111 11110011 10000111 11011101

If we see the first four bits of the IP address they are 1111 which matches the pattern of class E given above. So this IP address belongs to class E.

b. 10101111 11000000 11110000 00011101

If we see the first bit is 1, the second bit is 0 which shows that this is class B address as 1 0 = Class B given above.

c. 11011111 10110000 00011111 01011101

The first bit is 1, second bit is 1 and third bit is 0 which shows this address belongs to class C as 110 = Class C given above.

d. 11101111 11110111 11000111 00011101

The first bit is 1, the second bit is also 1 and third bit is also 1 which shows that this address belongs to class D.

3 0
2 years ago
Row array gameScores contains all player scores. Construct a row array highScores than contains all player scores greater than m
Sever21 [200]

Answer:

The solution is written using Python as it has a simple syntax.

  1. def getHighScores(gameScores, minScore):
  2.    meetsThreshold = []
  3.    for score in gameScores:
  4.        if(score > minScore):
  5.            meetsThreshold.append(score)
  6.    return meetsThreshold
  7. gameScores = [2, 5, 7, 6, 1, 9, 1]
  8. minScore = 5
  9. highScores = getHighScores(gameScores, minScore)
  10. print(highScores)

Explanation:

Line 1-8

  • Create a function and name it as <em>getHighScores</em> which accepts two values, <em>gameScores</em> and <em>minScore</em>. (Line 1)
  • Create an empty list/array and assign it to variable <em>meetsThreshold</em>. (Line 2)
  • Create a for loop to iterate through each of the score in the <em>gameScores</em> (Line 4)
  • Set a condition if the current score is bigger than the <em>minScore</em>, add the score into the <em>meetsThreshold</em> list (Line 5-6)
  • Return <em>meetsThreshold</em> list as the output

Line 11-12

  • create a random list of <em>gameScores</em> (Line 11)
  • Set the minimum score to 5 (Line 12)

Line 13-14

  • Call the function <em>getHighScores()</em> and pass the<em> gameScores</em> and <em>minScore </em>as the arguments. The codes within the function <em>getHighScores()</em>  will run and return the <em>meetsThreshold </em>list and assign it to <em>highScores.</em> (Line 13)
  • Display <em>highScores</em> using built-in function print().
8 0
1 year ago
As part of the duties of a digital forensics examiner, creating an investigation plan is a standard practice. Write a 3 to 4 (no
Simora [160]

Answer:

A digital forensic investigation is a special case of a digital investigation. Where the procedure and techniques are used will allow the results to be entered into cost of low foreg on investigation may be started to answer a question about whether or not centraband digital images exist on a computer.

Here we are considering the case of Global Finance Company with wide range of financial products and wide range of customers throughout the world. A suspect of compromise has been detected from the manager's computer. Now the team has been deployed to the branch office and conduct the Digital Forensic Investigation.

Concern of the Company

1. Regular updates for application infrastructure and network infrastructure.

2. One branch managers from porisbane branch felt compromises in his computer.

3. Both the servers and work station from all the offices are based on Microsoft Windows.

4. The firewalls and network segmentation are fully implemented.

5. Through intrasion detection and logging exist in the brances these are hardly used.

Digital Forensic Investigation Approach

The audit term of the Global Finacnce Company can follow four step. The digital forensic investigation model stands to be most effective model for investigation of the compromise happened int he reginal branch of the Global Finance Company.

1. Collection

a. All information from the manager's workstation, servers and other workstations must be collected.

b. Obtain all the important informtation.

c. Identify storage context noth internal and external devices.

d. Forensic tools that are applicable and to be used for the investigation are to be listed and made available for usage.

e. Target computer forensic imaging to be done and hashed to check the integrity of data.

f. Line network traffic has to captured.

Digital Evidance Collection done in two stages:

Volatile memory is the temporary memory and primary volatile memory is RAM

By cinning command: Cryptcat6543 -k key

Computer data can now required with the command Cryptcat -1 -p6543 -k key>>

Non volatile Memory Acquisition: Permanent memory or volatile memory stands significant source for the digital forensic investigation.

Parmanent data is collected through both online and offline methods:

Offline data is collected from the hard drive applications tool such as Guymayers etc.

Online data like firewall logs, antivirus logs and domain controller log with help of wires work and ethernal collected.

2. Examination

Once the data collected detailed examination is done by comparing the original and logical copies collected. Such examination gives us clues of how manege for window registry examination. Command used echo text_mess > file1.text : file2.txt

The above file retrieved through the command more < file1.txt : file2.txt

The network forensic is enabled using the tools and techniques so that the following potential information can be accessed.

System Information, Service listing, Process listing, Registry information, Binary dumped of memory

3. Analysis with Assumption

Many tools and methodologies are used by the audit team to analyse the collection and examined evidence. Analysis is done according to the following:

a. Leyword searches in all the files

b. Recovering the deleted files

c. Registry information extraction from the workstation

The tools used in this phase are FTK and ILOOKIX. These tools are helpful to recover the document, chat, logs, emails.

4. Report

The final report is generated by the audit team

Purpose of report Digital Forensic investigation conducted on the compromise of manager's computer

Author of the report Aufit Team

Incident Summery The source of compromise are x, y, x

Evidence All the effected files, registry, log files

Analysis All the analyzed data analyzed

Conclusion All digital evidence are extracted and found from the source

Document support volatile and non volatile data, tools, log info, registry info and so on.

7 0
2 years ago
Suppose your company has decided that it needs to make certain busy servers faster. Processes in the workload spend 60% of their
vekshin1

Answer:

CPU need 50% much faster

disk need 100% much faster

Explanation:

given data

workload spend time CPU  = 60%

workload spend time I/O = 40%

achieve overall system speedup = 25%

to find out

How much faster does CPU need and How much faster does the disk need

solution

we apply here Amdahl’s law for the overall speed of a computer that is express as

S = \frac{1}{(1-f)+ \frac{f}{k} }      .............................1

here f is fraction of work i.e 0.6 and S is overall speed  i.e 100% + 25% = 125 % and k is speed up of component

so put all value in equation 1 we get

S = \frac{1}{(1-f)+ \frac{f}{k} }  

1.25 = \frac{1}{(1-0.6)+ \frac{0.6}{k} }  

solve we get

k = 1.5

so we can say  CPU need 50% much faster

and

when f = 0.4 and S = 125 %

put the value in equation 1

S = \frac{1}{(1-f)+ \frac{f}{k} }  

1.25 = \frac{1}{(1-0.4)+ \frac{0.4}{k} }  

solve we get

k = 2

so here disk need 100% much faster

7 0
2 years ago
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