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Ad libitum [116K]
2 years ago
6

Read first a user's given name followed by the user's age from standard input. Then use an ofstream object named outdata to writ

e this information separated by a space into a file called outdata. Assume that this is the extent of the output that this program will do. Declare any variables that you need.
Computers and Technology
1 answer:
Stells [14]2 years ago
8 0

Answer:

/*

* Program to write data to text file.

*/

#include<iostream>

#include<fstream>

#include<string.h>

using  namespace std;

int main()

{

//Variable to name and age of a person.

string name;

int age;

cout<<"Enter your name"<<endl;

cin>>name;

cout<<"Enter your age"<<endl;

cin>>age;

     //Creating object of ofstream.

   ofstream file;

   file.open ("outdata.txt");

   //Writing data to file named outdata.txt

   file<<name<<" "<<age;

   file.close();

 

}

Output:

Enter your name

John

Enter your age

25

Content of Output.txt:

John 25

Explanation:

To write data to a file  ofstream object is used. An ofstream object file is created first and then using this object a file named "outdata.txt" is created.

Finally using shift operator (<<), by means  of operator overloading, name and age of  person is transferred to file outdata.txt.

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Method getPlayer2Move below is completed by assigning the correct value to result to be returned.

Explanation:

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int main()  

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   int x = 3, y = 4, n = 5;  

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Answer:

C++ code given below with appropriate comments

Explanation:

pattern.cpp

#include<iostream>

using namespace std;

void printCross(int n)

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int i,j,k;

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for(int i=n;i>=1;i--)

{

for(int j=n;j>=1;j--)

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{

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}

}

}

void printForwardSlash(int n)

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if(n%2)

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for(int i=n;i>=1;i--)

{

for(int j=n;j>=1;j--)

{

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{

cout<<j;

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cout<<"\n";

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else

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{

if(j==(n-i+1))

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void printBackwardSlash(int n)

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cout<<"\n";

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}

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int num;

char ch;

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printForwardSlash(num);

else if(ch=='b' || ch=='B')

printBackwardSlash(num);

else

cout<<"\nWrong input"<<endl;

return 0;

}

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