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kolezko [41]
2 years ago
12

Consider the following relation:CAR_SALE(Car#, Date_sold, Salesperson#, Commission%, Discount_amt)Assume that a car may be sold

by multiple salespeople, and hence{Car#, Salesperson#}is the primary key. Additional dependencies areDate_sold ? Discount_amtSalesperson# ? Commission%Based on the given primary key, is this relation in 1NF, 2NF, or 3NF? Why or whynot? How would you successively normalize it completely?
Computers and Technology
1 answer:
GalinKa [24]2 years ago
5 0

Answer:

The answer to this question can be given as:

Normalization:

Normalization usually includes the division of a table into two or more tables as well as defining a relation between the table. It is also used to check the quality of the database design. In the normalization, we use three-level that are 1NF, 2NF, 3NF.

First Normal Form (1NF):

In the 1NF each table contains unique data. for example employee id.  

Second Normal Form (2NF):

In the 2NF form, every field in a table that is not a determiner of another field's contents must itself be a component of the table's other fields.

Third Normal Form (3NF):

In the 3NF form, no duplication of information is allowed.

Explanation:

The explanation of the question can be given as:

  • Since all attribute values are single atomic, the given relation CAR_SALE is in 1NF.  
  • Salesperson# → commission% …Given  Thus, it is not completely dependent on the primary key {Car#, Salesperson#}. Hence, it is not in 2 NF.                                                                                                        

The 2 NF decomposition:

        CAR_SALE_1(Car#, Salesperson#, Date_sold, Discount_amt)

         CAR_SALE_2(Salesperson#, Commission%)

  • The relationship in question is not in 3NF because the nature of a transitive dependence occurs
  • Discount_amt → Date_sold → (Car#, Salesperson#) . Thus, Date_sold is neither the key itself nor the Discount amt sub-set is a prime attribute.  

The 3 NF decomposition :

        CAR_SALES_1A(Car#, Salesperson#, Date_sold)

        CAR_SALES_1B(Date_sold, Discount_amt)

        CAR_SALE_3(Salesperson#, Commission%)

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C3H8

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Mass of alkane = 1.17g

Volume (V) = 674 mL

Temperature (T) = 28°C

Pressure (P) = 741 mmHg.

Gas constant (R) = 0.08206 atm.L/Kmol

Step 2:

Conversion to appropriate unit.

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1000mL = 1L

Therefore, 674mL = 674/1000 = 0.674L

For Temperature:

Temperature (Kelvin) = Temperature (celsius) + 273

Temperature (celsius) = 28°C

Temperature (Kelvin) = 28°C + 273 = 301K

For Pressure:

760mmHg = 1atm

Therefore, 741 mmHg = 741/760 = 0.975atm

Step 3:

Determination of the number of mole of the alkane..

The number of mole of the alkane can be obtained by using the ideal gas equation. This is illustrated below:

Volume (V) = 0.674L

Temperature (T) = 301K

Pressure (P) = 0.975atm

Gas constant (R) = 0.08206 atm.L/Kmol

Number of mole (n) =?

PV = nRT

n = PV /RT

n = (0.975 x 0.674)/(0.08206x301)

n = 0.0266 mole

Step 4:

Determination of the molar mass of the alkane.

Mass of alkane = 1.17g

Number of mole of the alkane = 0.0266mole

Molar Mass of the alkane =?

Number of mole = Mass/Molar Mass

Molar Mass = Mass/number of mole

Molar Mass of the alkane = 1.17/0.0266 = 44g/mol

Step 5:

Determination of the molecular formula of the alkane.

This is illustrated below:

The general formula for the alkane is CnH2n+2

To obtain the molecular formula for the alkane we shall assume n = 1, 2, 3 or more till we arrive at molar Mass of 44.

When n = 1

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When n = 2

CnH2n+2 = C2H6 = (12x2) + (6x1) = 30g/mol

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We can see that when n is 3, the molar mass is 44g/mol.

Therefore, the molecular formula for the alkane is C3H8.

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