Answer:
a. cd into the nested directories/ nested - level - 1 / directory using an absolute path
Explanation:
The directory is a location on the hard disk, which is also called a folder. It contains the files and also contains the other directories called sub directories.
A path to a file is merged with a slash and determines the file or directory in the operating system. An absolute path is the location file or directory from the actual file system
The directory's absolute path starts with a slash, and all slashed in the directory separates the directions.
All directions in the absolute path are written on the left side. The last name in the path may belong to the file, and the pwd command can determine the current directory.
The relative path is the location of the file. It begins with the working directory. An absolute path is unambiguous and working with deeply nested directories.
There are two commands which are used such as
- cd is used for changing directory
- pwd is used for the working directory
We easily navigate the file system with the help of an absolute path.
Parallel circuit. On a wire you put the lights and one switch, on the other you put a resistor and another switch. (and the third wire contains the generator)
Answer:
to print a three-dimensional image on a piece of paper he should use autocad
The simulation, player 2 will always play according to the same strategy.
Method getPlayer2Move below is completed by assigning the correct value to result to be returned.
Explanation:
- You will write method getPlayer2Move, which returns the number of coins that player 2 will spend in a given round of the game. In the first round of the game, the parameter round has the value 1, in the second round of the game, it has the value 2, and so on.
#include <bits/stdc++.h>
using namespace std;
bool getplayer2move(int x, int y, int n)
{
int dp[n + 1];
dp[0] = false;
dp[1] = true;
for (int i = 2; i <= n; i++) {
if (i - 1 >= 0 and !dp[i - 1])
dp[i] = true;
else if (i - x >= 0 and !dp[i - x])
dp[i] = true;
else if (i - y >= 0 and !dp[i - y])
dp[i] = true;
else
dp[i] = false;
}
return dp[n];
}
int main()
{
int x = 3, y = 4, n = 5;
if (findWinner(x, y, n))
cout << 'A';
else
cout << 'B';
return 0;
}
