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Shkiper50 [21]
2 years ago
5

A slide contains three text boxes and three images that correspond to the text boxes. Which option can you use to display a text

box with its image, one after the other, in a timed sequence?
a.)slide transitions
b.)video
c.)custom animations
d.)page turnover
e.)animations
Computers and Technology
2 answers:
Bond [772]2 years ago
8 0
Answer  c) custom animations

rodikova [14]2 years ago
7 0
The answer is C. custom animations. 
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You cannot change data directly in the PivotTable. Instead, you must edit the Excel table, and then ____, or update, the PivotTa
Fudgin [204]

Answer:

d. refresh

Explanation:

The Excel software does not allow a user to change values/data directly in the Pivottable. You will get an error message like "Cannot change this part of a PivotTable report" when you try to type data directly.  You will have to edit the Excel Table and then refresh to reflect the updated data.

5 0
2 years ago
Read 2 more answers
A Color class has three public, integer-returning accessor methods: getRed, getGreen, and getBlue, and three protected, void-ret
jek_recluse [69]

Answer:

The following code are:

public void dissolve() {

setRed(getRed()+1);

setGreen(getGreen()+1);

setBlue(getBlue()+1);

alpha+=1;

}

Explanation:

Here, we define the void type function "dissolve()" inside it, we set three function i.e, "setRed()", "setGreen()", "setBlue()" and then we increment the variable "alpha" by 1.

Inside those three mutators method we set three accessor methods i.e, "getRed()", "getGreen()" , "getBlue()" and increment these accessor by 1.

The values will not be returned by the mutator functions, the accessor will be returned the values.

6 0
2 years ago
How can we make our programs behave differently each time they are run?
tensa zangetsu [6.8K]

Answer:

By given the right speech as much as the answers must be

Explanation:

By given the right speech as much as the answers must be

7 0
2 years ago
Write a function called sum_scores. It should take four arguments, where each argument is the team's score for that quarter. It
saw5 [17]

Answer:

Here is the Python program which has a function sum_scores:

def sum_scores(score1, score2, score3, score4):

   sum = score1 + score2 + score3 + score4

   print(sum)    

sum_scores(14,7,3,0)

Explanation:

  • Method sum_scores takes four arguments, score1, score2, score3, score4.
  • The sum variable adds these four scores and stores the value of their addition.
  • Lastly print statement is used to print the value stored in sum variable which is the value obtained by adding the four scores.
  • Last statement calls the sum_scores method and passes four values to it which are 14,7,3,0
  • The output of the above program is:
  • 24
  • If you want to use return statement instead of print statement you can replace print(sum) with return sum. But in order to display the sum of the scores you can replace sum_scores(14,7,3,0) with print(sum_scores(14,7,3,0))
  • The program along with the output is attached as a screenshot.

5 0
2 years ago
Problem 1a. Write a function named hasFinalLetter that takes two parameters 1. strList, a list of non-empty strings 2. letters,
mash [69]

Answer:

The answer is the programming in Python language has strings and characters that has to be declared in the method.

Explanation:

#method

def hasFinalLetter(strList,letters):

output = #output list

#for every string in the strList

for string in strList:

#findout the length of each string in strList

length = len(string)

#endLetter is last letter in each string

endLetter = string[length-1]

#for each letter in the letters list

for letter in letters:

#compare with endLetter

#if we found any such string

#add it to output list

if(letter == endLetter):

output.append(string)

#return the output list

return output

#TestCase 1 that will lead to return empty list

strList1 = ["user","expert","login","compile","Execute","stock"]

letters1 = ["a","b","y"]

print hasFinalLetter(strList1,letters1)

#TestCse2

strList2 = ["user","expert","login","compile","Execute","stock"]

letters2 = ["g","t","y"]

print hasFinalLetter(strList2,letters2)

#TestCase3

strList3 = ["user","expert","login","compile","Execute","stock"]

letters3 = ["k","e","n","t"]

print hasFinalLetter(strList3,letters3)

8 0
2 years ago
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