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Alinara [238K]
2 years ago
7

python Consider this data sequence: "3 11 5 5 5 2 4 6 6 7 3 -8". Any value that is the same as the immediately preceding value i

s considered a CONSECUTIVE DUPLICATE. In this example, there are three such consecutive duplicates: the 2nd and 3rd 5s and the second 6. Note that the last 3 is not a consecutive duplicate because it was preceded by a 7. Write some code that uses a loop to read such a sequence of non-negative integers, terminated by a negative number. When the code finishes executing, the number of consecutive duplicates encountered is printed. In this case,3 would be printed. ASSUME the availability of a variable, stdin, that references a Scanner object associated with standard input.
Computers and Technology
1 answer:
Vika [28.1K]2 years ago
7 0

int firstNumber,secondNumber = -1, duplicates = 0;

do {

cin >> firstNumber;

if ( secondNumber == -1) {

secondNumber = firstNumber;

}else {

if ( secondNumber == firstNumber )

duplicates++;

else

secondNumber = firstNumber;

}

} while(firstNumber > 0 );

cout << duplicates;

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Using range(1,101), make two list, one containing all even numbers and other containing all odd numbers. How can I do this on Py
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Answer:

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for i in range(1,101):

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In your own words, what is pair-programming? What is the role of the driver? What is the role of the navigator? What are some be
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<u>Paired programming:</u>

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Overcome Method

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2 years ago
Computers represent color by combining the sub-colors red, green, and blue (rgb). Each sub-color's value can range from 0 to 255
maxonik [38]

Answer:

Follows are the code to this question:

#include <iostream>//defining a header file

using namespace std; //using namespace

int main() //defining main method

{

int red,green,blue,s; //defining integer variable

cout<<"Enter value: \n ";//print message

cin>>red>>green>>blue; //input value

if(red<green && red<blue)//defining if block that checks red value

s=red;//store red variable value to s variable

else if(green<blue)//defining else if block that checks green value less then blue

s=green;//store green variable value in s variable

else//defining else block

s=blue; //store blue variable value in s variable

//calculating red, green, blue value

red=red-s;//store red value

green=green-s;//store green value

blue=blue-s;//store blue value

cout<<red<<" "<<green<<" "<<blue;

}

Output:

Enter value:

130  

50

130

80 0 80

Explanation:

In the above code, inside the Main method, four integer variable "red, green, blue, and s" is defined, in which "red, green, and blue" is used for input the value from the user end.

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  • In this block, it will store the blue variable value in the "s" variable, and subtract the value of "red, green, and blue" value from "s" and store its value, and at the last, it will print its value.    
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