Maturity Stage – During the maturity stage, the product is established and the aim for the manufacturer is now to maintain the market share they have built up. This is probably the most competitive time for most products and businesses need to invest wisely in any marketing they undertake. They also need to consider any product modifications or improvements to the production process which might give them a competitive advantage. i think this would be the best time for the company to purchase an emerging technology.
Answer:
a
Explanation:
Megan doesn't have a registered business. She can't claim insurance
Answer:
True.
Explanation:
An expression containing the && and operator is only true if both of the operands present in the expression are true otherwise it will give the result as false if either one of them is false or both of them are false.In the question it states that the expression in true either or both of it's operand are true.
Hence the answer is true.
Answer:
Big Oh notation is used to asymptotically bound the growth of running time above and below the constant factor.
Big Oh notation is used to describe time complexity, execution time of an algorithm.
Big Oh describes the worst case to describe time complexity.
For the equation; T(N) = 10000*N + 0.00001*N^3.
To calculate first of all discard all th constants.
And therefore; worst case is the O(N^3).
#include <stdio.h>
int main(void) {
// your code goes here
//unsigned a =float_times_four(0x80000000);
unsigned float_times_four(unsigned uf){
unsigned expn = (uf >> 23) & 0xFF;
printf(expn);
unsigned sign = uf & 0x80000000;
unsigned frac = uf & 0x007FFFFF;
if(expn == 255 ||(expn == 0 && frac ==0))
return uf;
if(expn){
expn<<2;
}else if(frac == 0x007FFFFF){
//here 0x7FFFFF given by you that is wrong you place this 0x007FFFFF will excute
frac>>2;
expn<<2;
}else{
frac<<=2;
}
return (sign) | (expn <<23) | (frac);
}
return 0;
}
