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Kitty [74]
2 years ago
10

Gabe wants to move text from one document to another document. He should _____.

Computers and Technology
2 answers:
Pachacha [2.7K]2 years ago
6 0
<span>B.)highlight the text, select the cut command, move to the new document, make sure the cursor is in the correct location, and select the paste command 


hope this helps</span>
Lunna [17]2 years ago
6 0
B.

He should highlight the text, select the cut command, move to the new document, make sure the cursor is in the correct location, and select the paste command.


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Whoever helps me with these questions i will help them with the same number of questions in any subject: 1. As the operations ma
mezya [45]
I'm going have to go with with 1.b and 2.d hope this helps and I don't need help right now.
6 0
2 years ago
Write a program that has the following String variables: firstName, middleName, and lastName. Initialize these with your first,
Licemer1 [7]

Answer:

The programming language is not stated; However, I'll answer your question using C++ programming language.

Comments are used for explanatory purpose

Program starts here

#include<iostream>

#include <string>

using namespace std;

int main()

{

//Declare Variables

string firstName, middleName, lastName;

char firstInitial, middleInitial, lastInitial;

/*Initialize firstName, middleName and lastName (Replace values with your details)*/

firstName = "First Name";

middleName = "Middle Name";

lastName = "Last Name";

 

// Get Initials

firstInitial = firstName.at(0);

middleInitial = middleName.at(0);

lastInitial = lastName.at(0);

 

//Print Results

cout<<"Lastname: "<<lastName<<endl;

cout<<"Firstname: "<<firstName<<endl;

cout<<"Middlename: "<<middleName<<endl;

cout<<"Last Initial: "<<lastInitial<<endl;

cout<<"First Initial: "<<firstInitial<<endl;

cout<<"Middle Initial: "<<middleInitial<<endl;

return 0;

}

3 0
2 years ago
Write a loop to populate the list user_guesses with a number of guesses. The variable num_guesses is the number of guesses the u
Masja [62]

Answer:

num_guesses = int(input())

user_guesses = []

for i in range(num_guesses):

    x = int(input())

    user_guesses.append(x)

   

print(user_guesses)

Explanation:

This solution is provided in Python

This line prompts the user for a number of guesses

num_guesses = int(input())

This line initializes an empty list

user_guesses = []

This loop lets user input each guess

for i in range(num_guesses):

This line takes user input for each guess

    x = int(input())

This appends the input to a list

    user_guesses.append(x)

This prints the user guesses    

print(user_guesses)

6 0
1 year ago
A large department store has been attaching tags with barcodes to merchandise, and employees use barcode readers to scan merchan
77julia77 [94]

The department store should consider using RFIDs (Radio Frequency Identification) for tracking inventory. Unlike the wireless barcodes, RFID uses radio waves to communicate with readers. One very common advantage of an RFID is the scanning range. Wireless barcodes, for instance, requires the reader to be close to the barcode before it can see it to scan it. However, RFID systems can scan a tag as long as it is within range. This is important because it reduces wastage of time on labor-intensive processes and increases task speed, convenience, and project turnover.

Many passive RFIDs use tags that are powered by electromagnetic energy. Such energy does not consume power.


8 0
2 years ago
Read 2 more answers
Suppose that you need to maintain a collection of data whose contents are fixed- i.e., you need to search for and retrieve exist
Keith_Richards [23]

Answer:

Option a: a sorted array

Explanation:

Since the expectation on the data structure never need to add or delete items, a sorted array is the most desirable option. An array is known for its difficulty to modify the size (either by adding item or removing item). However, this disadvantage would no longer be a concern for this task. This is also the reason, linked list, binary search tree and queue is not a better option here although they offer much greater efficiency to add and remove item from collection.

On another hand,  any existing items from the sorted array can be easily retrieved using address indexing and therefore the data query process can be very fast and efficient.

4 0
2 years ago
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