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nignag [31]
2 years ago
9

Write an expression that will cause the following code to print "18 or less" if the value of user_age is 18 or less. Write only

the expression. Sample output with input: 17 18 or less
Computers and Technology
2 answers:
Tcecarenko [31]2 years ago
7 0

Answer:

user_age = int(input())

if user_age <= 18:

  print('18 or less')

else:

  print('Over 18')

Explanation:

#define user_age with: integer (input(' #from user')

user_age = int(input())

#"if" statement: user_age is less than or equal to 18 than ///

if user_age <= 18:

#Print ('Enter desired output here')

  print('18 or less')

#"else" statement: If above is not true then ///

else:

#Print ('Enter desired output here')

  print('Over 18')

lana [24]2 years ago
6 0

Answer:

if (user_age<=18){

           System.out.println("18 or less");

       }

Explanation:

The above expression in Java will print "18 or less" if the input is less than 18.

Consider a complete java program that request a user to input his/her age below and prints "18 or Less" if the user age is less or equal to 18.

import java.util.Scanner;

public class num2 {

   public static void main(String[] args) {

   Scanner in = new Scanner(System.in);

       System.out.println("enter age:");

       int user_age =in.nextInt();

       if (user_age<=18){

           System.out.println("18 or less");

       }

       else

       {

           System.out.println("greater than 18");

       }

   }

}

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Code to copy:

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