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mylen [45]
2 years ago
11

Dr. Robbins wants to know if there are different opinions regarding the value of public school education between Native American

s who have at least one relative who attended Indian Boarding School and Native Americans who have no family experience with Indian Boarding School. Dr. Robbins contacts 35 Native American participants in each group. He wants each group to include younger as well as older adults, and a mix of male and female participants. He asks each person to complete a survey about their attitudes toward public education. In this study, _____ is the independent variable.
Computers and Technology
1 answer:
zmey [24]2 years ago
5 0

Answer:

The independent variable is Native American participants

Explanation:

Why Native Americans is the independent variable is bacause the survey population is Native Americans and the result of the survey won't be affected by the gender and age of the native american participants. So it the independent variable.

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Computers represent color by combining the sub-colors red, green, and blue (rgb). Each sub-color's value can range from 0 to 255
maxonik [38]

Answer:

Follows are the code to this question:

#include <iostream>//defining a header file

using namespace std; //using namespace

int main() //defining main method

{

int red,green,blue,s; //defining integer variable

cout<<"Enter value: \n ";//print message

cin>>red>>green>>blue; //input value

if(red<green && red<blue)//defining if block that checks red value

s=red;//store red variable value to s variable

else if(green<blue)//defining else if block that checks green value less then blue

s=green;//store green variable value in s variable

else//defining else block

s=blue; //store blue variable value in s variable

//calculating red, green, blue value

red=red-s;//store red value

green=green-s;//store green value

blue=blue-s;//store blue value

cout<<red<<" "<<green<<" "<<blue;

}

Output:

Enter value:

130  

50

130

80 0 80

Explanation:

In the above code, inside the Main method, four integer variable "red, green, blue, and s" is defined, in which "red, green, and blue" is used for input the value from the user end.

  • In the next step, a conditional statement is used, that checks the red variable value, if the condition is true, it will store its value in the "s" variable, otherwise, it will go to else if block.
  • In this block, the green variable checks its value less than then blue variable value, if the condition is true, it will store the green value in the "s" variable, otherwise, it will goto else block.
  • In this block, it will store the blue variable value in the "s" variable, and subtract the value of "red, green, and blue" value from "s" and store its value, and at the last, it will print its value.    
4 0
2 years ago
A school principal trying to find out if parents will help buy new playground equipment shows digital leadership by.
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Answer:

D. is the correct answer!

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2 years ago
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7. Which control is used to display multiple records in List Form
padilas [110]

Answer:

I think a is correct answer.

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2 years ago
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Carrie is looking at the Form Properties Sheet. Which tab will control how the data is displayed and the data source it is bound
Lemur [1.5K]
The Answer is: Data


Hope this help
8 0
2 years ago
Network flow issues come up in dealing with natural disasters and other crises, since major unexpected events often require the
nasty-shy [4]

Answer:

Check the explanation

Explanation:

Algorithm for solving flood condition:

We suggest an algorithm to resolve the flood condition by creating a flow network graph.

Let us assume for every patient "p" there is a node "2" and for every hospital "h" there is a node "uh" and there is an edge ()T, uh) exist between patient "p" and hospital "h" with flow capacity of 1 iff patient "p" is reachable to hospital "h" within a half-hour.

Then source node "s" is made between all the patient-nodes by an edge with flow capacity of 1 and then the sink "t" is made by linking all the hospital nodes by an edge with capacity "[n/k]".

There is an approach to send patients to hospitals: when there is a source "s" to sink "t" flow of "n". We can send 1 flow-unit from source "s" to sink "t" along the paths (s, yp, uh, t) whenever a probable approach is available to send patients.

This approach of sending patients to hospitals doesn't break the capacity limitation of edges. Hence we can send patient "p" to hospital "h" with 1 flow- unit if edge(m uh) permits at least 1 flow- unit.

The running-time of this algorithm is found by finding the time needed to solve max-flow graph with nodes O(n+k) and edges O(n^{k}) edges.

5 0
2 years ago
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