Answer is
productivity
Sometimes called the office or personal productivity software,
productivity software is dedicated to producing databases, spreadsheets,
charts, graphs, documents, graphs, digital video and worksheets. Reason behind
the name productivity is due to the fact that it increases productivity in
office work.
Answer:
It is definitely not used for locating the options in the menu. its the new feature available which is available from the Tell Me text box which you can find immediately right of the very last cmd tab which is above the ribbon. And as you add any help topic to this into textbox, the excel shows all Excel command list , command which are related to the help topic in a drop down.
Explanation:
The answer is self explanatory.
Learning
planning
designing
developing
testing delivering
Answer:
Explanation:
We can use for-loop in python to calculate the tuition amount in the next 5 years. If the tuition is increasing 3% each year, in each loop we can multiply the amount by 1.03
tuition = 8000
for year in range(1,6):
tuition *= 1.03
print("The tuition amount after " + str(year) + " year(s) is $" + str(tuition))
Answer:
// here is code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int n,no_open=0;
cout<<"enter the number of lockers:";
// read the number of lockers
cin>>n;
// initialize all lockers with 0, 0 for locked and 1 for open
int lock[n]={};
// toggle the locks
// in each pass toggle every ith lock
// if open close it and vice versa
for(int i=1;i<=n;i++)
{
for(int a=0;a<n;a++)
{
if((a+1)%i==0)
{
if(lock[a]==0)
lock[a]=1;
else if(lock[a]==1)
lock[a]=0;
}
}
}
cout<<"After last pass status of all locks:"<<endl;
// print the status of all locks
for(int x=0;x<n;x++)
{
if(lock[x]==0)
{
cout<<"lock "<<x+1<<" is close."<<endl;
}
else if(lock[x]==1)
{
cout<<"lock "<<x+1<<" is open."<<endl;
// count the open locks
no_open++;
}
}
// print the open locks
cout<<"total open locks are :"<<no_open<<endl;
return 0;
}
Explanation:
First read the number of lockers from user.Create an array of size n, and make all the locks closed.Then run a for loop to toggle locks.In pass i, toggle every ith lock.If lock is open then close it and vice versa.After the last pass print the status of each lock and print count of open locks.
Output:
enter the number of lockers:9
After last pass status of all locks:
lock 1 is open.
lock 2 is close.
lock 3 is close.
lock 4 is open.
lock 5 is close.
lock 6 is close.
lock 7 is close.
lock 8 is close.
lock 9 is open.
total open locks are :3
