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lord [1]
1 year ago
8

Which of the following is not a benefit of active listening?

Computers and Technology
1 answer:
muminat1 year ago
7 0
Active listening is watching and taking noted and asking questions on the subject anything else is not active listening
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The second version of css, css2, was introduced in 1998, expanding the language to provide styles to _________.
Evgen [1.6K]

Answer:

Structured Documents

Explanation:

Structured Documents consist of hierarchy in the files. They may include data files. HTML (Hyper-text markup language) documents and XML (Extensible Markup Language) applications are the examples of Structured Documents.

6 0
2 years ago
All the employees of Delta Corporation are unable to access the files stored in the server. What do you think is the reason behi
CaHeK987 [17]
C serve crash hope this is correct
5 0
1 year ago
What elements of SANS 20 you could leverage to reduce the TCP/IP vulnerabilities of your workstation
Vlada [557]

Answer:

- limitation and control of network ports, protocols and services.

- Continuous vulnerability assessment and remediation.

Explanation:

The TCP or transmission control protocol is a layer 4 protocol (transport), that reliably transports packets in sequential segments to an application in the destination computer, using the ip address and the port number of the application.

The ICMP sent during the TCP/ip activities, can render the network vulnerable to attacks. limitation and control of the network ports, protocols and services and continuous assessment would mitigate the vulnerability of the TCP/ip model.

5 0
1 year ago
When Liam went to print his presentation, the boot process established the connection to the printer, sent the presentation to t
Mars2501 [29]

Answer:

b. False

Explanation:

When Liam went to print his presentation, the boot process established the connection to the printer, sent the presentation to the printer, and let other software know the printer was busy. It is a false statement.

6 0
2 years ago
In a survey of 7200 T.V. viewers, 40% said they watch network news programs. Find the margin of error for this survey if we want
olga_2 [115]

Answer:

Margin of Error=M.E= ± 0.0113

Explanation:

Margin of Error= M.E= ?

Probability that watched network news programs = p = 0.4

α= 95%

Margin of Error =M.E= zₐ/₂√p(1-p)/n

Margin of Error=M.E= ±1.96 √0.4(1-0.4)/7200

Margin of Error=M. E = ±1.96√0.24/7200

Margin of Error=M. E- ±1.96* 0.005773

Margin of Error=M.E= ±0.0113

The Margin of Error is the estimate of how much error is possible as a result of random sampling.

6 0
2 years ago
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