Answer:
CPU need 50% much faster
disk need 100% much faster
Explanation:
given data
workload spend time CPU = 60%
workload spend time I/O = 40%
achieve overall system speedup = 25%
to find out
How much faster does CPU need and How much faster does the disk need
solution
we apply here Amdahl’s law for the overall speed of a computer that is express as
S = 
.............................1
here f is fraction of work i.e 0.6 and S is overall speed i.e 100% + 25% = 125 % and k is speed up of component
so put all value in equation 1 we get
S =
1.25 = 
solve we get
k = 1.5
so we can say CPU need 50% much faster
and
when f = 0.4 and S = 125 %
put the value in equation 1
S =
1.25 = 
solve we get
k = 2
so here disk need 100% much faster
Answer:
C++.
Explanation:
<em>Code snippet.</em>
#include <map>
#include <iterator>
cin<<N;
cout<<endl;
/////////////////////////////////////////////////
map<string, string> contacts;
string name, number;
for (int i = 0; i < N; i++) {
cin<<name;
cin<<number;
cout<<endl;
contacts.insert(pair<string, string> (name, number));
}
/////////////////////////////////////////////////////////////////////
map<string, string>::iterator it = contacts.begin();
while (it != contacts.end()) {
name= it->first;
number = it->second;
cout<<word<<" : "<< count<<endl;
it++;
}
/////////////////////////////////////////////////////////////////////////////////////////////////////////
I have used a C++ data structure or collection called Maps for the solution to the question.
Maps is part of STL in C++. It stores key value pairs as an element. And is perfect for the task at hand.
Answer:
2^7= 128
Explanation:
An instruction format characterizes the diverse part of a guidance. The fundamental segments of an instruction are opcode and operands. Here are the various terms identified with guidance design: Instruction set size tells the absolute number of guidelines characterized in the processor. Opcode size is the quantity of bits involved by the opcode which is determined by taking log of guidance set size. Operand size is the quantity of bits involved by the operand. Guidance size is determined as total of bits involved by opcode and operands.
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