Answer:
f = 2 * (&A[0])
See explaination for the details.
Explanation:
The registers $s0, $s1, $s2, $s3, and $s4 have values of the variables f, g, h, i, and j respectively. The register $s6 stores the base address of the array A and the register $s7 stores the base address of the array B. The given MIPS code can be converted into the C code as follows:
The first instruction addi $t0, $s6, 4 adding 4 to the base address of the array A and stores it into the register $t0.
Explanation:
If 4 is added to the base address of the array A, then it becomes the address of the second element of the array A i.e., &A[1] and address of A[1] is stored into the register $t0.
C statement:
$t0 = $s6 + 4
$t0 = &A[1]
The second instruction add $t1, $s6, $0 adding the value of the register $0 i.e., 32 0’s to the base address of the array A and stores the result into the register $t1.
Explanation:
Adding 32 0’s into the base address of the array A does not change the base address. The base address of the array i.e., &A[0] is stored into the register $t1.
C statement:
$t1 = $s6 + $0
$t1 = $s6
$t1 = &A[0]
The third instruction sw $t1, 0($t0) stores the value of the register $t1 into the memory address (0 + $t0).
Explanation:
The register $t0 has the address of the second element of the array A (A[1]) and adding 0 to this address will make it to point to the second element of the array i.e., A[1].
C statement:
($t0 + 0) = A[1]
A[1] = $t1
A[1] = &A[0]
The fourth instruction lw $t0, 0($t0) load the value at the address ($t0 + 0) into the register $t0.
Explanation:
The memory address ($t0 + 0) has the value stored at the address of the second element of the array i.e., A[1] and it is loaded into the register $t0.
C statement:
$t0 = ($t0 + 0)
$t0 = A[1]
$t0 = &A[0]
The fifth instruction add $s0, $t1, $t0 adds the value of the registers $t1 and $t0 and stores the result into the register $s0.
Explanation:
The register $s0 has the value of the variable f. The addition of the values stored in the regsters $t0 and $t1 will be assigned to the variable f.
C statement:
$s0 = $t1 + $t0
$s0 = &A[0] + &A[0]
f = 2 * (&A[0])
The final C code corresponding to the MIPS code will be f = 2 * (&A[0]) or f = 2 * A where A is the base address of the array.
