Answer:
5, 10 and 16
Explanation:
The sum of their ages is √961 = 31
If Joe is x years old, the equation that follows is:
x + (x+5) + (x+5+6) = 31
This simplifies to
3x = 31 - 11 - 5 = 15
so x=5
From that you can find
Joe = x = 5
Kate = x+5 = 10
Jody = x+5+6 = 16
Answer:
A company requires an Ethernet connection from the north end of its office building to the south end. The distance between connections is 161 meters and will need to provide speeds of up to 10 Gbps in full duplex mode. Which of the following cable combinations will meet these requirements?
ANSWER: Use multi-mode fiber optic cable
Explanation:
MULTI-MODE FIBER OPTIC CABLE
For Ethernet distances up to 100 meters, the Copper CATX cable will do just fine. In the question, we are dealing with a distance of up to 161 meters, so we need an Ethernet extension. LAN extension over fiber optic cable with media converter can be used to convert the Ethernet cable runs from copper to fiber. Multi-mode fiber has a range of 550 meters for 10/100/1000 Ethernet links.
Multi-mode optical fiber is commonly used for communication over short distances, like within a building or on a campus. They are capable of data rate of up to 100 Gbps, which surpasses the requirements in this question. They are more economical in this case as they are not as expensive a the single-mode optical fiber cable. Fiber optic cable has the advantage of being immune to electromagnetic interferences, spikes, ground loops, and surges. This makes it more suited for this purpose.
Most word-processing programs allow the user to select a command from the menu to insert a graphic. Clicks in the document where you want your file, choose insert and picture click from file select the image the press open and you picture will become inserted in to the document.
Answer:
The code to this question can be given as:
Code:
int i,j,count_previous=0,count_next=0; //define variable
for (j=0; j<n; j++) //loop for array
{
if (x[0]==x[j]) //check condition
{
count_previous++; //increment value by 1.
}
}
for (i=0; i<n; i++) //loop
{
for (j=0; j<n; j++)
{
if (x[i]==x[j]) //check condition
{
count_next++; //increment value by 1.
}
}
if (count_previous>count_next) //check condition
{
mode=x[i-1];
}
else
{
mode=x[i];
count_previous=count_next; //change value.
count_next= 0 ; //assign value.
}
}
Explanation:
In the question it is define that x is array of the string elements that is already define in the question so the code for perform operation in the array is given above. In the code firstly we define the variable that is i, j, count_previous, count_next. The variable i,j is used in the loop and variable count_previous and count_next we assign value 0 that is used for check the values of array. Then we define the for loop in this loop we use conditional statement in the if block we check that array of zero element is equal to array of j value then the count_previous is increase by 1. Then we use nested loop It is also known as loop in a loop. In this first loop is used for array and the second loop is used for check array element.In this we use the condition that if array x of i value is equal to array x of j then count_next will increment by 1.Then we use another condition that is if count_previous is greater then count_next then mode of x is decrement by 1. else mode equal to array and count_previous holds the value of count_next and count_next is equal to 0.
