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Cloud [144]
1 year ago
10

.Ten pounds of candy were prepared for the school party.

Computers and Technology
1 answer:
Elena L [17]1 year ago
6 0

Answer:

There were 16 bags of lollipops and 17 of tootsie

Explanation:

In the problem it says "Ten pounds of candy"  It also says that Lollipops were 1.6 pounds while tootsie bars were 1.7 pounds. Knowing this I multiplied 1.6 × 10 = 16 for the lollipops. Then I multiplied 1.7 × 10 = 17 for the tootsie bars. Therefore I came to the conclusion that there were 16 bags of lollipops and 17 bags of tootsie bars.

I'm extremely sorry if I am incorrect :(

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JAVA
avanturin [10]

Answer:

   public ArrayList onlyBlue(String[] clothes){

       ArrayList<String> blueCloths = new ArrayList<>();

       for(int i =0; i<clothes.length; i++){

           if(clothes[i].equalsIgnoreCase("blue")){

               blueCloths.add(clothes[i]);

           }

       }

       return blueCloths;

   }

Explanation:

  • Create the method to accept an Array object of type String representing colors with a return type of an ArrayList
  • Within the method body, create and initialize an Arraylist
  • Use a for loop to iterate the Array of cloths.
  • Use an if statement within the for loop to check if item equals blue and add to the Arraylist.
  • Finally return the arrayList to the caller
3 0
1 year ago
Nathan wants to make the quotation stand out further. Which order of steps does he need to follow to do this task?
Alina [70]

Answer:

B.

Explanation:

Go to the Borders and Shading option, click the Shading tab, and click the color under the Fill option.

5 0
2 years ago
Read 2 more answers
If I execute the expression x &lt;- 4L in R, what is the class of the object `x' as determined by the `class()' function?
FinnZ [79.3K]

Answer:

integer

Explanation:

The expression can be implemented as follows:

x <- 4L

class(x)

Here x is the object. When this expression is executed in R, the class "integer" of object 'x' is determined by the class() function. R objects for example x in this example have a class attribute determines the names of the classes from which the object inherits. The output of the above expression is:

"integer"

Here function class prints the vector of names of class i.e. integer that x inherits from. In order to declare an integer, L suffix is appended to it. Basically integer is a subset of numeric. If L suffix is not appended then x<-4 gives the output "numeric". Integers in R are identified by the suffix L while all other numbers are of class numeric independent of their value.

7 0
1 year ago
In C++ the declaration of floating point variables starts with the type name double, followed by the name of the variable, and t
Vadim26 [7]

Answer:

See explaination

Explanation:

Given a partial grammar which represents the specification for C++ style variable declaration. In this range a - z indicates terminals that represents the variable names.

'S' is the start symbol of the

non-terminal.

Hence, given,

S= TV

V= CX

Please kindly refer to attachment for further instructions and complete step by step solution.

8 0
2 years ago
A.Create the logic for a program that calculates and displays the amount of money you would have if you invested $5000 at 2 perc
lianna [129]

Answer:

see explaination

Explanation:

a)

amount = 5000

rate = 2

year = 1

interest = calculateInterest(amount, rate, year);

finalAmount = amount + interest

###### function ######

calculateInterest(amount, rate, year):

interest = (amount*rate*year)/100;

return interest

b)

amount <- enter amount

rate = 2

year = 1

interest = calculateInterest(amount, rate, year);

finalAmount = amount + interest

###### function ######

calculateInterest(amount, rate, year):

interest = (amount*rate*year)/100;

return interest

c)

#include <iostream>

using namespace std;

// function defination

double calculateInterest(double amount, double rate, int year);

int main(){

double amount, rate;

int year = 1;

cout<<"Enter amount: ";

cin>>amount;

cout<<"Enter rate: ";

cin>>rate;

// calling method

double interest = calculateInterest(amount, rate, year);

cout<<"Amount after 1 year: "<<(amount+interest)<<endl;

return 0;

}

// function calculation

double calculateInterest(double amount, double rate, int year){

return (amount*rate*year)/100.0;

}

7 0
1 year ago
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