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2 years ago

When using preventative insecticides which holiday period should trigger an application?

Computers and Technology

2 answers:

swat322 years ago

8 0

Further explanation

Towards the end of the year especially the 10th month is the time for rice farmers to start a new cycle of planting. As stated by farmers from Lebak Regency, Unang, in their area in October the water had begun to overflow and could irrigate their fields. Rain began to fall regularly.

But the arrival of rain does not necessarily make them happy, because often farmers actually inconvenience because of pest attacks that also come. Starting from stem borer pests, brown plant hopper, mice and others. At most, rats and stem borer routinely come in every rain.

Rat pest control is usually done through tungkreban (similar to gropyokan) or using owls. Often we release snakes. But during the release, our children are asked not to play in the fields, he said.

Especially for brown borer and plant hopper, farmers are accustomed to using pesticides. We spray more often because pesticides dissolve in water. So if we spray it keeps raining, tomorrow we will spray again.

This condition is common in all areas of Indonesian plantations. In fact, Brebes Regency is the highest pesticide user in ASEAN. In one planting season, Brebes can use up to 330 thousand liters of pesticides and in a year the onion center can reach 4 planting seasons.

Learn More

insecticides: brainly.com/question/9579932

Details

Class: college

Subject: Computer and technology

Keywords : insecticides, control, condition

Savatey [412]2 years ago

4 0

Spring break around Easter I would believe

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Driving is expensive. Write a program with a car's miles/gallon and gas dollars/gallon (both doubles) as input, and output the g

I am Lyosha [343]

Answer:

#program in Python.

#function to calculate driving cost

def driving_cost(d_miles, m_per_gallon, doll_per_gallon):

#calculate cost and return the value

return (d_miles / m_per_gallon) * doll_per_gallon

#read the miles per gallon

m_per_gallon = float(input("Enter car's miles/gallon:"))

#read dollars per gallon

doll_per_gallon = float(input("Enter gas dollars/gallon:"))

#call function to find cost for 10 miles

print('%0.2f' % driving_cost(10, m_per_gallon, doll_per_gallon))

#call function to find cost for 50 miles

print('%0.2f' % driving_cost(50, m_per_gallon, doll_per_gallon))

#call function to find cost for 400 miles

print('%0.2f' % driving_cost(400, m_per_gallon, doll_per_gallon))

Explanation:

Read the value of miles per gallon and assign it to variable "m_per_gallon". Then read dollars per gallon from user and assign it to variable "doll_per_gallon". Call the function driving_cost() with parameter miles, m_per_gallon and doll_per_gallon. This function will find the cost of driving and return the cost.Call function for 10, 50 and 400 miles.

Output:

Enter car's miles/gallon:20

Enter gas dollars/gallon:3.1599

1.58

7.90

63.20

5 0

2 years ago

Read 2 more answers

The __________ contains a list of all the resources owned by the library.

Ira Lisetskai [31]

The catalog contains a list of all the resources owned by the library.

- Mabel <3

5 0

2 years ago

zybooks cis 110 challenge activity 9.8.1 Write a program that takes in a positive integer as input, and outputs a string of 1's

irakobra [83]

Answer:

public class IntegerToBinary

{

public static void main(String[] args) {

integerToBinary(6);

}

public static void integerToBinary(int num){

while(num > 0){

System.out.print(num%2);

num = Math.floorDiv(num, 2);

}

Explanation:

*The code is in Java.

Create a function called integerToBinary that takes one parameter, num

Inside the function, create a while loop that iterates while the num is greater than 0. Inside the loop, print the num%2. Then, get the floor division of the num by to and assign it to the num.

Inside the main, call the function with parameter 6.

7 0

2 years ago

Users need to be able to make use of _____ , such as rumors, unconfirmed reports, and stories, when solving problems.

jekas [21]

Answer:

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Explanation:

The informal information system is employee based system design to meet personnel and vocational needs and to help in the solution of work-related problems. it also funnels information upward through indirect channels.

However, one of the most important reasons for why informal communication is critical to businesses is that it allows employees to give feedback to their superiors.

Thus, the informal or grapevine communication promotes social relationship among the participants. It helps to build up unity, integrity and solidarity among them and boosts up their morale. Grapevine or informal communication is faster than the formal communication.

8 0

2 years ago

Input a number [1-50] representing the size of the shape and then a character [x,b,f] which represents the shape i.e. x->cros

Gnoma [55]

Answer:

C++ code given below with appropriate comments

Explanation:

pattern.cpp

#include<iostream>

using namespace std;

void printCross(int n)

{

int i,j,k;

if(n%2) //odd number of lines

{

for(int i=n;i>=1;i--)

{

for(int j=n;j>=1;j--)

{

if(j==i || j==(n-i+1))

cout<<j;

else

cout<<" ";

}

cout<<"\n";

}

else //even number of lines

{

for(int i=1;i<=n;i++)

{

for(int j=1;j<=n;j++)

{

if(j==i || j==(n-i+1))

{

cout<<" "<<j<<" ";

}

else

cout<<" ";

}

cout<<"\n";

}

void printForwardSlash(int n)

{

if(n%2)

{

for(int i=n;i>=1;i--)

{

for(int j=n;j>=1;j--)

{

if(j==n-i+1)

{

cout<<j;

}

else

cout<<" ";

}

cout<<"\n";

}

else

{

for(int i=1;i<=n;i++)

{

for(int j=1;j<=n;j++)

{

if(j==(n-i+1))

{

cout<<j;

}

else

cout<<" ";

}

cout<<"\n";

}

void printBackwardSlash(int n)

{

if(n%2) // odd number of lines

{

for(int i=n;i>=1;i--)

{

for(int j=n;j>=1;j--)

{

if(j==i)

{

cout<<j;

}

else

cout<<" ";

}

cout<<"\n";

}

else //even number of lines

{

for(int i=1;i<=n;i++)

{

for(int j=1;j<=n;j++)

{

if(j==i)

{

cout<<j;

}

else

cout<<" ";

}

cout<<"\n";

}

int main()

{

int num;

char ch;

cout<<"Create a numberes shape that can be sized."<<endl;

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if(ch=='x' || ch=='X')

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printForwardSlash(num);

else if(ch=='b' || ch=='B')

printBackwardSlash(num);

else

cout<<"\nWrong input"<<endl;

return 0;

}

4 0

2 years ago