Answer:
False
Explanation:
The private member of a class is not accessible by using the Dot notation ,however the private member are those which are not accessible inside the class they are accessible outside the class .The public member are accessible inside the class so they are accessible by using the dot operator .
<u>Following are the example is given below in C++ Language </u>
#include<iostream> // header file
using namespace std;
class Rectangle
{
private:
double r; // private member
public:
double area()
{ return 3.14*r*r;
}
};
int main()
{
Rectangle r1;// creating the object
r1.r = 3.5;
double t= r1.area(); // calling
cout<<" Area is:"<<t;
return 0;
}
Output:
compile time error is generated
<u>The correct program to access the private member of class is given below </u>
#include<iostream> // header file
using namespace std;
class Rectangle
{
private:
double r; // private member
public:
double area()
{
r1=r;
double t2=3.14*r2*r2;
return(t2); // return the value
}
};
int main()
{
Rectangle r1;// creating the object
r1.r = 1.5;
double t= r1.area(); // calling
cout<<" Area is:"<<t;
return 0;
}
Therefore the given statement is False
Answer:
The person watching Lances friend typing the ATM pin is an example of <u>"shoulder browsing"</u> and Lances friend should <u>"Change the ATM pin."</u>
<u />
<u>I hope this is the answer you were looking for!</u>
// This command takes input from the user.
Scanner input = new Scanner(System.in);
int response= input.nextInt();
// Making the variables required
int noCount =0 ;
int yesCount =0;
// Checking the response if it is 1 or 2 and reporting accordingly
if(response == 1 || response ==2){
yesCount+=1;
System.out.println("YES WAS RECORDED");
}
// Checking if the input is 3 or 4 then printing the required lines
else if (response == 3 || response ==4){
noCount+=1;
System.out.println("NO WAS RECORDED");
}
// if the input is not valid than printing INVALID
else{
System.out.println("INVALID");
}
Answer: b. 11
Explanation:
//The initial value is 1
//let call the value as x
x = 1
//then the user updated the value to 10
//so now x is 10
x = 10
// and update the workflow to 11
//so now the value of x is 11
x = 11
even if the programmer print x, so the output will be 11
Answer:
DoS attack
Explanation:
A Denial of Service attack involves the sending of maliciously formatted data packets to a server. The packet can be larger than the allowed IP size such that when it arrives at the server, the server cannot identify the headers in the data packet for it to process and extract data. The server can either freeze or crash, denying allowed users access to its resources and making it unavailable.
