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1 year ago

Explain what might happen if two stations are accidentally assigned the same hardware address?

1 answer:

5 0

Answer: If two different station are addressed with the same hardware address then there are chances of occurrence of the failure in the network at irregular intervals.The failure or error will occur because of the both the devices are seen as one by the network due to same address.

An intelligent network system id used ,it can identify the error can help in the prevention of the failure.Other option for configuring the situation is assigning the MAC(media access control)address to devices which are unique in nature thus, no device can have same address.

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Write a method that accepts a String object as an argument and displays its contents backward. For instance, if the string argum

Nata [24]

Answer:

// importing the necessary libraries

import java.util.Scanner;

public class BackwardString {

public static void main(String[] args) {

String input;

// Scanner object to read string from user input

Scanner scanner = new Scanner(System.in);

System.out.print("Enter String here : ");

input=scanner.next();

// calling backward method to reverse passed string

backward(input);

// closing Scanner object

scanner.close();

}

// Method to Reverse the input string

private static void backward(String source) {

int i, len = source.length();

StringBuilder dest = new StringBuilder(len);

for (i = (len - 1); i >= 0; i--){

dest.append(source.charAt(i));

}

System.out.println("Reversed String : "+dest);

}

Explanation:

// importing the necessary libraries

import java.util.Scanner;

public class BackwardString {

public static void main(String[] args) {

String input;

// Scanner object to read string from user input

Scanner scanner = new Scanner(System.in);

System.out.print("Enter String here : ");

input=scanner.next();

// calling backward method to reverse passed string

backward(input);

// closing Scanner object

scanner.close();

}

// Method to Reverse the input string

private static void backward(String source) {

int i, len = source.length();

StringBuilder dest = new StringBuilder(len);

for (i = (len - 1); i >= 0; i--){

dest.append(source.charAt(i));

}

System.out.println("Reversed String : "+dest);

}

The program above accepts a String object as an argument and displays its contents backward.

It reverses the any string inputed while producing the output.

6 0

2 years ago

For the (pseudo) assembly code below, replace X, Y, P, and Q with the smallest set of instructions to save/restore values on the

Dimas [21]

Answer:

Explanation:

Let us first consider the procedure procA; the caller in the example given.

Some results: $s0,$s1,$s2, $t0,$t1 and $t2 are being stored by procA. Out of these registers, few registers are accessing by procA after a call to procB. But, procB might over-write these registers.

Thus, procA need to save some registers into stack first before calling procB, .

only $s1,$t0 and $t1 are being used after return from procB in the given example,

Caller saves and restores only values in $t0-$t9, according to MIPS guidelines for caller-saved and callee-saved registers, .

Thus, procA needs to save only $t0 and $t1.

jal instruction overwrites the register $ra by writing the address, to which the control should jump back, after completing the instructions of procB, when procB is called,.

Therefore, procA also need to save $ra into stack.

ProcA is writing new values into $a0,$a2, procA must save $a0 and $a1 first before calling procB, .

In the given example, after return from procB, only $a0 is being used. It is therefore enough to save $a0.

Also, procA needs to save frame pointer, which points the start of the stack space for each procedure.

Generally, as soon as the procedure begins, frame pointer is set to the current value of the stack pointer,.

Let us consider the procedure procB; the callee in the given example.

The callee is responsible for saving values in $s0-$s7 and restoring them before returning to caller, this is according to MIPS guidelines for caller-saved and callee-saved registers,

procB is expected to over-write the registers $s2 and $t0. Nonetheless, in the first two lines, procB might over-write the registers $s0 and $s1.

Thus, procB is responsible for saving and restoring $s0,$s1 and $s2.

We need to create space for 5 values on the stack since procA needs to save $a0,$ra,$t0,$t1 and $fp(frame pointer), . Each value(word) takes 4 bytes.

$sp = $sp – 20 # on the stack, create space for 5 values

sw $a0, 16($sp) # store the result in $a0 into the memory address

# indicated by $sp+20

sw $ra, 12($sp) # save the second value on stack

sw $t0, 8($sp) # save the third value on stack

sw $t1, 4($sp) # save the fourth value on stack

sw $fp, 0($sp) # To the stack pointer, save the frame pointer

$fp = $sp # To the stack pointer, set the frame pointer

lw $fp, 0($sp) # from stack, start restoring values

lw $t1, 4($sp)

lw $t0, 8($sp)

lw $ra, 12($sp)

lw $a0, 16($sp)

$sp = $sp + 20 # decrease the size of the stack

$sp = $sp – 12 # for three values, create space on the stack

sw $s0, 0($sp) # save the value in $s0

sw $s1, 0($sp) # save the value in $s1

sw $s2, 0($sp) # save the value in $s2

lw $s0, 0($sp) # from the stack, restore the value of $s0

lw $s1, 0($sp) # from the stack, restore the value of $s1

lw $s2, 0($sp) # from the stack, restore the value of $s2

$sp = $sp + 12 # decrease the stack size

8 0

2 years ago

In C++ the declaration of floating point variables starts with the type name double, followed by the name of the variable, and t

Vadim26 [7]

Answer:

See explaination

Explanation:

Given a partial grammar which represents the specification for C++ style variable declaration. In this range a - z indicates terminals that represents the variable names.

'S' is the start symbol of the

non-terminal.

Hence, given,

S= TV

V= CX

Please kindly refer to attachment for further instructions and complete step by step solution.

8 0

2 years ago

What technology gets its name from the notion that it ignores the traditional A, B, and C class designations for IP addresses?

goblinko [34]

Answer:

Classless Inter-Domain Routing

Explanation:

Classless Inter-Domain Routing (CIDR), pronounced “cider” or “sidder,” gets its name from the notion that it ignores the traditional A, B, and C class designations for IPv4 addresses and sets the network-host ID boundary wherever it wants to, in a way that simplifies routing across the resulting IP address spaces.

3 0

1 year ago

Most injury crashes in Florida happen in __________ conditions.

ivolga24 [154]

Answer:

Most injury crashes in Florida happen in dusk conditions

Explanation:

Dusk is the time of the day when the sun is setting. At this time of the day, the visibility on the roads is less. This time of the day, the number of cars on the roads is also significantly greater. This indirectly means that the possibility of most injury crashes in Florida in dusk conditions considerably increases.

The amount of tourism happening in the state is also a condition that takes part in injury crashes due to increased traffic on the roads.

7 0

2 years ago