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netineya [11]
2 years ago
15

Write code that determines the number of full days represented by the number of hours stored in the variable hours and stores th

at value in the variable full_days. For example, the number of full days in 50 hours is 2. Ignore any leftover hours that don't contribute to a full day. Assume the value of hours has already been initialized. Solve It!
Computers and Technology
1 answer:
taurus [48]2 years ago
4 0

Answer:

hours = 50

full_days = int(hours / 24)

print("The number of full days in " + str(hours) + " hours is " + str(full_days))

Explanation:

Initialize the hours

Since there are 24 hours in a full day, divide the hours by 24. Note that you need to typecast it to the int, because the result is a decimal value by default

Print the values as requested

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Write a class with a constructor that accepts a String object as its argument. The class should have a method that returns the n
mote1985 [20]

Answer:

import java.util.Scanner;

public class VowelsAndConsonantsDemo {

   /**

   The printMenu methods displays a menu to the user

    */

   public static void printMenu() {

       System.out.println("Please select an option: ");

       System.out.println();

       System.out.print("a. Count the number of vowels in the string.\n"

               + "b. Count the number of consonants in the string.\n"

               + "c. Count both the vowels and consonants in the string.\n"

               + "d. Enter another string.\n"

               + "e. Exit the program\n");

   }

   public static void main(String[] args) {

       String input;      // to hold the user's input

       String option;     // to hold the user's input

       char choice;       // to hold a single character

       char exit;         // user chooses 'e' to exit the program

       char letter;       //the Y or N from the user's decision to exit

       // create a Scanner object to read keyboard input.

       //  Scanner keyboard = new Scanner(System.in);

       Scanner keyboard;

       do {

           keyboard = new Scanner(System.in);

           // ask user to enter string

           System.out.print("Enter a string: ");

           input = keyboard.nextLine();

           input = input.toLowerCase();

           System.out.println();

           printMenu();

           option = keyboard.nextLine();

           choice = option.charAt(0);

           VowelsAndConsonants words = new VowelsAndConsonants(input);

           switch (choice) {

               case 'a':

               case 'A':

                   System.out.println("Number of Vowels: " + words.getVowels());

                   break;

               case 'b':

               case 'B':

                   System.out.println("Number of Consonants: " + words.getConsonants());

                   break;

               case 'c':

               case 'C':

                   System.out.println("Number of Vowels & Consonants: " + words.getConsonants()

                           + words.getVowels());

                   break;

               case 'd':

               case 'D':

                   System.out.println("Enter a string: ");

                   break;

               case 'e':

               case 'E':

                   System.exit(0);

                   break;

               default:

                   System.out.println("You did not enter a valid choice.");

           }

           //

           // keyboard.nextLine();    //consumes the new line character after the choice

           // String answer = keyboard.nextLine();

           // letter = answer.charAt(0);

       } while (true);

   }

}

4 0
1 year ago
Recall the problem of finding the number of inversions. As in the text, we are given a sequence of n numbers a1, . . . , an, whi
Kay [80]

Answer:

The algorithm is very similar to the algorithm of counting inversions. The only change is that here we separate the counting of significant inversions from the merge-sort process.

Algorithm:

Let A = (a1, a2, . . . , an).

Function CountSigInv(A[1...n])

if n = 1 return 0; //base case

Let L := A[1...floor(n/2)]; // Get the first half of A

Let R := A[floor(n/2)+1...n]; // Get the second half of A

//Recurse on L. Return B, the sorted L,

//and x, the number of significant inversions in $L$

Let B, x := CountSigInv(L);

Let C, y := CountSigInv(R); //Do the counting of significant split inversions

Let i := 1;

Let j := 1;

Let z := 0;

// to count the number of significant split inversions while(i <= length(B) and j <= length(C)) if(B[i] > 2*C[j]) z += length(B)-i+1; j += 1; else i += 1;

//the normal merge-sort process i := 1; j := 1;

//the sorted A to be output Let D[1...n] be an array of length n, and every entry is initialized with 0; for k = 1 to n if B[i] < C[j] D[k] = B[i]; i += 1; else D[k] = C[j]; j += 1; return D, (x + y + z);

Runtime Analysis: At each level, both the counting of significant split inversions and the normal merge-sort process take O(n) time, because we take a linear scan in both cases. Also, at each level, we break the problem into two subproblems and the size of each subproblem is n/2. Hence, the recurrence relation is T(n) = 2T(n/2) + O(n). So in total, the time complexity is O(n log n).

Explanation:

5 0
2 years ago
Suppose your name was George Gershwin. Write a complete program that would print your last name, followed by a comma, followed b
NNADVOKAT [17]

Answer:

I will write the code in C++ and JAVA      

Explanation:

<h2>JAVA CODE</h2>

public class Main

{ public static void main(String[] args) {

       // displays Gershwin,George

     System.out.println("Gershwin,George"); }  }

<h2>C++ Code:</h2>

#include <iostream>

using namespace std;  

int main()

{  cout<<"Gershwin,George"; }    

// displays last name Gershwin followed by , followed by first name George

//displays Gershwin,George as output.

6 0
2 years ago
Read 2 more answers
Write a loop that displays all possible combinations of two letters where the letters are 'a', or 'b', or 'c', or 'd', or 'e'. T
Dafna11 [192]

Answer:

for (char outerChar='a'; outerChar<='e'; outerChar++){

for (char innerChar='a'; innerChar<='e'; innerChar++){

cout << outerChar << innerChar << "\n";

}

}

3 0
1 year ago
GJAUDRO: A member of a team. Question 2 with 1 blankARBCUE: Activity that is practiced under the water. Question 3 with 1 blankE
kramer

Answer:

1 jugador

2 bucear

3 equipo

4 ciclismo

5 pasear

6 tenis

Explanation:

ur welcome

6 0
2 years ago
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