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sineoko [7]
2 years ago
10

Constantine forms the following hypothesis. Let n be any non-negative number that meets the following condition: when n is divid

ed by 5, the remainder cannot equal 2. For such values of n, the quantity Q = 97 − 6n is a prime number so long as Q > 0. Which of the following values of n would provide a counterexample to this hypothesis? Indicate all such values.
Computers and Technology
1 answer:
notka56 [123]2 years ago
8 0

Answer:

n=5

Explanation:

if n= 5

i.     n/5=5/5=1  so it divides completely the remainder is 0

ii.  97 - 6(5) = 97 - 30 = 67,   67 is a prime number.

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Write two methods: encrypt and decrypt. encrypt should #take as input a string, and return an encrypted version #of it according
Harman [31]

Answer:

The code is given below with appropriate comments

Explanation:

CIPHER = (("D", "A", "V", "I", "O"),

         ("Y", "N", "E", "R", "B"),

         ("C", "F", "G", "H", "K"),

         ("L", "M", "P", "Q", "S"),

         ("T", "U", "W", "X", "Z"))

# Add your code here!

def encrypt(plaintext):

   theList = []

   for char in plaintext:

       if char.isalpha():

           char = char.upper()

           if char == "J":

               char = "I"

           theList.append(char)

   if len(theList) % 2 == 1:

       theList.append("X")

   for i in range(0, len(theList), 2):

       if theList[i] == theList[i + 1]:

           theList[i + 1] = "X"

       findex = [-1, -1]

       sindex = [-1, -1]

       for j in range(len(CIPHER)):

           for k in range(len(CIPHER)):

               if theList[i] == CIPHER[j][k]:

                   findex = [j, k]

               if theList[i + 1] == CIPHER[j][k]:

                   sindex = [j, k]

       # same row

       if (findex[0] == sindex[0]):

           findex[1] += 1

           sindex[1] += 1

           if findex[1] == 5:

               findex[1] = 0

           if sindex[1] == 5:

               sindex[1] = 0

           theList[i] = CIPHER[findex[0]][findex[1]]

           theList[i + 1] = CIPHER[sindex[0]][sindex[1]]

       # same column

       elif (findex[1] == sindex[1]):

           findex[0] += 1

           sindex[0] += 1

           if findex[0] == 5:

               findex[0] = 0

           if sindex[0] == 5:

               sindex[0] = 0

           theList[i] = CIPHER[findex[0]][findex[1]]

           theList[i + 1] = CIPHER[sindex[0]][sindex[1]]

       else:

           theList[i] = CIPHER[findex[0]][sindex[1]]

           theList[i + 1] = CIPHER[sindex[0]][findex[1]]

   return "".join(theList)

def decrypt(ciphertext):

   theString = ""

   findex = [-1, -1]

   sindex = [-1, -1]

   for i in range(0, len(ciphertext), 2):

       for j in range(len(CIPHER)):

           for k in range(len(CIPHER)):

               if ciphertext[i] == CIPHER[j][k]:

                   findex = [j, k]

               if ciphertext[i + 1] == CIPHER[j][k]:

                   sindex = [j, k]

       if (findex[0] == sindex[0]):

           findex[1] -= 1

           sindex[1] -= 1

           if findex[1] == -1:

               findex[1] = 4

           if sindex[1] == -1:

               sindex[1] = 4

           theString += CIPHER[findex[0]][findex[1]]

           theString += CIPHER[sindex[0]][sindex[1]]

       # same column

       elif (findex[1] == sindex[1]):

           findex[0] -= 1

           sindex[0] -= 1

           if findex[0] == -1:

               findex[0] = 4

           if sindex[0] == -1:

               sindex[0] = 4

           theString += CIPHER[findex[0]][findex[1]]

           theString += CIPHER[sindex[0]][sindex[1]]

       else:

           theString += CIPHER[findex[0]][sindex[1]]

           theString += CIPHER[sindex[0]][findex[1]]

   return theString

# Below are some lines of code that will test your function.

# You can change the value of the variable(s) to test your

# function with different inputs.

#

# If your function works correctly, this will originally

# print: QLGRQTVZIBTYQZ, then PSHELXOWORLDSX

print(encrypt("PS. Hello, worlds"))

print(decrypt("QLGRQTVZIBTYQZ"))

5 0
2 years ago
Given 4 integers, output their product and their average, using integer arithmetic.
solmaris [256]

Answer:

see explaination

Explanation:

Part 1:

import java.util.Scanner;

public class LabProgram {

public static void main(String[] args) {

Scanner scnr = new Scanner(System.in);

int num1;

int num2;

int num3;

int num4;

int avg=0, pro=1;

num1 = scnr.nextInt();

num2 = scnr.nextInt();

num3 = scnr.nextInt();

num4 = scnr.nextInt();

avg = (num1+num2+num3+num4)/4;

pro = num1*num2*num3*num4;

System.out.println(pro+" "+avg);

}

}

------------------------------------------------------------------

Part 2:

import java.util.Scanner;

public class LabProgram {

public static void main(String[] args) {

Scanner scnr = new Scanner(System.in);

int num1;

int num2;

int num3;

int num4;

double avg=0, pro=1; //using double to store floating point numbers.

num1 = scnr.nextInt();

num2 = scnr.nextInt();

num3 = scnr.nextInt();

num4 = scnr.nextInt();

avg = (num1+num2+num3+num4)/4.0; //if avg is declared as a float, then use 4.0f

pro = num1*num2*num3*num4;

System.out.println((int)pro+" "+(int)avg); //using type conversion only integer part

System.out.printf("%.3f %.3f\n",pro,avg);// \n is for newline

}

}

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When you register to take classes, the registrar office pulls up a file full of information about you, including your contact in
FinnZ [79.3K]
What are your choices? My first answer would be a database but...
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A form that dedicates a page for each item retrieved for a case; it allows investigators to add more detail about exactly what w
gregori [183]

Answer:

Single-evidence form​

Explanation:

Single-evidence form​  dedicates a page for each item retrieved for a case; it allows investigators to add more detail about exactly what was done to the evidence each time it was taken from the storage locker.

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When a Python program is reading a file, the data is input as plain ASCII characters in a string. What is the following code doi
Aleksandr [31]

Answer:

The given python code mainly add values.

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