Answer:
int i = 0; i < names.size(); i++
Explanation:
The ArrayList must be read in the forward direction, and it is going to start from 0 certainly. Also, the iteration is going to end when i is exactly one less than the size of the ArrayList. And this is possible only if we choose the option mentioned in the Answer section. In this, i starts from 0 and iterates till i is one less than name.size() which is the size of the ArrayList.
Answer:
Explanation:
.exe: is a file extension, means file that contain executable program which can be run by Microsoft windows.
.txt: is also file extension which contains text (characters).
.avi: means (audio video interleave) is a file extension, which contains audio and video data encoded.
Answer:
The program to this question can be given as:
Program:
def swap_values(user_val1, user_val2): #define function
return (user_val2, user_val1) #return values
if __name__ == '__main__': #define constructor.
n1 = int(input('Enter first number :')) #input value form user
n2 = int(input('Enter second number :')) #input value form user
(n1,n2) = swap_values(n1,n2) #hold function values.
print(n1) #print values
print(n2) #print values
Output:
Enter first number :3
Enter second number :8
8
3
Explanation:
The explanation of the above python program can be given as:
- In the python program we define a function that is "swap_values". This function takes two integer values that is "user_val1 and user_val2" as a parameters and returns variable values that is "user_val2 and user_val1".
- Then we use a constructor in this we define two variable that is "n1 and n2" these variable are use to take user-input from the user and pass the value into the function.
- To hold the value of the function we use n1 and n2 variable and print these variable value.
Answer:
// A optimized school method based C++ program to check
// if a number is composite.
#include <bits/stdc++.h>
using namespace std;
bool isComposite(int n)
{
// Corner cases
if (n <= 1) return false;
if (n <= 3) return false;
// This is checked so that we can skip
// middle five numbers in below loop
if (n%2 == 0 || n%3 == 0) return true;
for (int i=5; i*i<=n; i=i+6)
if (n%i == 0 || n%(i+2) == 0)
return true;
return false;
}
// Driver Program to test above function
int main()
{
isComposite(11)? cout << " true\n": cout << " false\n";
isComposite(15)? cout << " true\n": cout << " false\n";
return 0;
}
Explanation:
Explanation:
Sampling and RBG (red blue green) pixels and also the binary sequences working together such that it display any digitally colored image by allowing the computer system know where the Red Blue Green pixel is going to be placed and also what the opacity would be for that pixel. The combination of these components is what gives you a digital color image.
