What is the value of the variable result after these lines of code are executed?

JAVA...Write a statement that calls the recursive method backwardsAlphabet() with parameter startingLetter.

scoray [572]

Answer:

RecursiveCalls.backwardsAlphabet(startingLetter);

Explanation:

The statement that is needed is a single-line statement. Since the class RecursiveCalls is already in the same file we can simply use that class and call its function without making a new class object. Once we call that class' function we simply pass the variable startingLetter (which is already provided) as the sole parameter for the function in order for it to run and use the letter 'z' as the starting point.

RecursiveCalls.backwardsAlphabet(startingLetter);

3 0

2 years ago

Suppose a host has a 1-MB file that is to be sent to another host. The file takes 1 second of CPU time to compress 50%, or 2 sec

kozerog [31]

Answer: bandwidth = 0.10 MB/s

Explanation:

Given

Total Time = Compression Time + Transmission Time

Transmission Time = RTT + (1 / Bandwidth) xTransferSize

Transmission Time = RTT + (0.50 MB / Bandwidth)

Transfer Size = 0.50 MB

Total Time = Compression Time + RTT + (0.50 MB /Bandwidth)

Total Time = 1 s + RTT + (0.50 MB / Bandwidth)

Compression Time = 1 sec

Situation B:

Total Time = Compression Time + Transmission Time

Transmission Time = RTT + (1 / Bandwidth) xTransferSize

Transmission Time = RTT + (0.40 MB / Bandwidth)

Transfer Size = 0.40 MB

Total Time = Compression Time + RTT + (0.40 MB /Bandwidth)

Total Time = 2 s + RTT + (0.40 MB / Bandwidth)

Compression Time = 2 sec

Setting the total times equal:

1 s + RTT + (0.50 MB / Bandwidth) = 2 s + RTT + (0.40 MB /Bandwidth)

As the equation is simplified, the RTT term drops out(which will be discussed later):

1 s + (0.50 MB / Bandwidth) = 2 s + (0.40 MB /Bandwidth)

Like terms are collected:

(0.50 MB / Bandwidth) - (0.40 MB / Bandwidth) = 2 s - 1s

0.10 MB / Bandwidth = 1 s

Algebra is applied:

0.10 MB / 1 s = Bandwidth

Simplify:

0.10 MB/s = Bandwidth

The bandwidth, at which the two total times are equivalent, is 0.10 MB/s, or 800 kbps.

(2) . Assume the RTT for the network connection is 200 ms.

For situtation 1:

Total Time = Compression Time + RTT + (1/Bandwidth) xTransferSize

Total Time = 1 sec + 0.200 sec + (1 / 0.10 MB/s) x 0.50 MB

Total Time = 1.2 sec + 5 sec

Total Time = 6.2 sec

For situation 2:

Total Time = Compression Time + RTT + (1/Bandwidth) xTransferSize

Total Time = 2 sec + 0.200 sec + (1 / 0.10 MB/s) x 0.40 MB

Total Time = 2.2 sec + 4 sec

Total Time = 6.2 sec

Thus, latency is not a factor.

5 0

2 years ago

Write a loop that outputs the numbers in a list named salaries. The outputs should be formatted in a column that is right-justif

GalinKa [24]

Answer:

Following is the loop statement in the Python programming language

salaries=[93.85967,4232.32,13343.3434] #storing the values in salaries

for k in salaries:#iterating the loop

print("%12f"%round(k,2))# print the width of 12 and a precision of 2

Output:

93.860000

4232.320000

13343.340000

Explanation:

Following is the description of the statement

Declared a dictionary "salaries" and initialized some values into it.

iterating the for a loop .

In this for loop print the width 12 and a precision of 2 .The print statement in python will

print the data with width 12 and a precision of 2 in the console window

7 0

2 years ago

The Gas-N-Clean Service Station sells gasoline and has a car wash. Fees for the car wash are $1.25 with a gasoline purchase of $

beks73 [17]

Answer:

d = {"R":2.89,"P":3.09, "S":3.39, "N":0}

noofgallons = input("Enter number of Gallons:")

gastype = input("Enter Gas type/; R,P,S,N")

cwr = input("Is Car Was Requieed")

if(gastype == "R"):

gal == nooffgallons * d['R']

if (cwr=="y" and gal<10):

gal+=3.00;

elif(cwr=="y" and gal>=10):

gal+=1.25

elif(cwr=="n"):

gal=gal

elif(gastype==P):

gal== nooffgallons * d['P']

if(cwr="y" and gal<10):

gal+=3.00;

elif(cwr=="y"and gal>=10):

gal+=1.25

elif(cwr=="n"):

gal=gal

elif(gastype ==S):

gal=noofgallons *d['S']

if(cwr="y" and gal<10):

gal+=3.00;

elif(cwr=="y"and gal>=10):

gal+=1.25

elif(cwr=="n"):

gal=gal

print("tptal cost paid"+ gal)

The above program uses a dictionary for storing gasoline types and their cost, and dictionary is always constant, and hence its fulfilled the requirement of keeping it constant. And car wash is treated accordingly. And if elif else ladder has been used to calculate the total number of gallons.

Rest part is self explanatory.

Explanation:

The code is self explanatory.

7 0

2 years ago

Robin wants her presentation to move from one slide to another with special motion effects. Which option should Robin use?

topjm [15]

If this is in power point, then she should use the <em>transitions </em>tab on the ribbon. =)

3 0

2 years ago

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