Answer:
Fault-Tolerance
Explanation:
Fault tolerance refers to the ability of a system (computer, network, cloud cluster, etc.) to continue operating without interruption when one or more of its components fail.
Answer:
<em>Ethernet cables, Network Adapters, Modem, Routers, Switches.</em>
Explanation:
<em>The devices that are required in setting up a wired network for the 5 computer comprises of the following devices </em>
- <em>Ethernet Cables</em>
- <em>Network Adapters</em>
- <em>Modem/Router</em>
- <em>Network Switch</em>
<em>Ethernet cables: They are called network cables or RJ-45 cables used to in connecting two or more computers together. it has different categories called, the untwisted pair and twisted pair Ethernet, with a speed from 10-1000</em>
<em>Network Adapters : This adapters allows a computer device to connect and interface with a network computer</em>
<em>Modem/Routers : A router is a device that that sits in the middle between your local computers and modems. it takes receives information or gets information from the modem and delivers it to the computer</em>
<em>Network switch: it connects more than two computers together to a network and share data among themselves and other devices on the network</em>
I believe the word you're looking for is properties.
Answer:
The decimal value of 101₂² base 2 = 25 base 10
Explanation:
The number 101₂² in decimal value is found as follows;
101₂ × 101₂ = 101₂ + 0₂ + 10100₂
We note that in 101 + 10100 the resultant 2 in the hundred position will have to be converted to a zero while carrying over 1 to the thousand position to give;
101₂ + 0₂ + 10100₂ = 11001₂
Therefore;
101₂² = 11001₂
We now convert the result of the square of the base 2 number, 101², which is 11001₂ to base 10 as follows;
Therefore converting 11001₂ to base 10 gives;
11001₂= 1 × 2⁴ + 1 × 2³ + 0 × 2² + 0 × 2 ¹ + 1 × 2⁰
Which gives;
16 + 8 + 0 + 0 + 1 = 25₁₀.
Answer:
Motivation? The search problem.
Sorting algorithms: insertion sort, shellsort, heapsort, mergesort, quicksort, bubblesort
At the very least, "general purpose" sorting algorithms require O(n log n) comparisons
Explanation: