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Vilka [71]
1 year ago
12

Write an interface named HGTTU which specifies a universal constant int value of 42, and a single method named getNormilazedIntV

alue that takes no parameters and returns an int. The purpose of which is to get the value of the object's int instance variable, add the universal constant and return the result.Next, write a second named myInt which is composed of a single int instance variable (and the minimal set of customary methods) that implements HGTTU.
Computers and Technology
1 answer:
Nadusha1986 [10]1 year ago
8 0

Answer:

Hope this helps.

//HGTTU.java

public interface HGTTU {

 int universalConstant = 42;

  public int getNormilazedIntValue();

}

//MyInt.java

public class MyInt implements HGTTU {

  int instanceFiled;

Override

  public int getNormilazedIntValue() {

      return instanceFiled+universalConstant;

  }

}

Explanation:

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victus00 [196]

Answer:

I am writing a Python program.

def concordance(filename):  # function that takes a file name as parameter and returns the concordance for that file

   file = open(filename,"r")  #opens file in read mode

   unique={}  #creates and empty list

   for word in file.read().split():  #loops through every word in the file

       if word in unique:  # if words is already present in the list

           unique[word] += 1  #add 1 to the count of the existing word

       else:    #if word is not present in the list

           unique[word] = 1 #add the word to the list and add 1 to the count of word

           file.close();  # close the file

   for x in sorted(unique):  #sort the list and displays words with frequencies

       print(x, unique[x]);  #prints the unique words and their frequencies in alphabetical order

#prompts user to enter the name of the file

file_name=input('Enter the input file name: ')

concordance(file_name)  #calls concordance method by passing file name to it

Explanation:

The program has a function concordance that takes a text file name as parameter and returns a list of unique words and their frequencies.

The program first uses open() method to open the file in read mode. Here "r" represents the mode. Then creates an empty list named unique. Then the for loop iterates through each word in the file. Here the method read() is used to read the contents of file and split() is used to return these contents as a list of strings. The if condition inside the loop body checks each word if it is already present in the list unique. If the word is present then it adds 1 to the count of that word and if the word is not already present then it adds that unique word to the list and assign 1 as a count to that word. close() method then closes the file. The second for loop for x in sorted(unique):  is used to display the list of unique words with their frequencies. sorted() method is used to sort the list and then the loop iterates through each word in the list, through x, which acts like an index variable, and the loop displays each word along with its frequency.

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1 year ago
Given a scanner reference variable named input that has been associated with an input source consisting of a sequence of strings
Makovka662 [10]

The code that examines all the strings in the input source and determines how long the longest string (or strings are) is the following:

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while(input.hasNextInt()){

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}

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1 year ago
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inysia [295]

Answer:

Option (c) is the correct answer of this question.

Explanation:

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Answer:

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