The following cose will be used to copy assignment operator for CarCounter
<u>Explanation:</u>
Complete Program:
#include <iostream>
using namespace std;
class CarCounter
{
public:
CarCounter();
CarCounter& operator=(const CarCounter& objToCopy);
void SetCarCount(const int setVal)
{
carCount = setVal;
}
int GetCarCount() const
{
return carCount;
}
private:
int carCount;
};
CarCounter::CarCounter()
{
carCount = 0;
return;
}
// FIXME write copy assignment operator
/* Your solution goes here */
CarCounter& CarCounter::operator=(const CarCounter& objToCopy)
{
if(this != &objToCopy)
carCount = objToCopy.carCount;
return *this;
}
int main()
{
CarCounter frontParkingLot;
CarCounter backParkingLot;
frontParkingLot.SetCarCount(12);
backParkingLot = frontParkingLot;
cout << "Cars counted: " << backParkingLot.GetCarCount();
cout << endl << endl;
system("pause");
return 0;
}
Answer:
Option a: a sorted array
Explanation:
Since the expectation on the data structure never need to add or delete items, a sorted array is the most desirable option. An array is known for its difficulty to modify the size (either by adding item or removing item). However, this disadvantage would no longer be a concern for this task. This is also the reason, linked list, binary search tree and queue is not a better option here although they offer much greater efficiency to add and remove item from collection.
On another hand, any existing items from the sorted array can be easily retrieved using address indexing and therefore the data query process can be very fast and efficient.
Answer:
- #include <stdio.h>
- int main()
- {
- const double piVal = 3.14159;
- double sphereVolume = 0.0;
- double sphereRadius = 0.0;
-
- sphereRadius = 1.0;
- sphereVolume = 4.0/ 3.0 * piVal * sphereRadius * sphereRadius * sphereRadius;
-
-
- printf("Sphere volume: %lf\n", sphereVolume);
- return 0;
- }
Explanation:
Firstly we can identify the formula to calculate volume of sphere which is
Volume = 4/3 
With this formula in mind, we can apply this formula to calculate the volume of sphere in Line 10. This is important to perform floating-point division 4.0/3.0 to ensure the resulting value is a floating value as well. Since we have been given piVal and sphereRadius, we can just multiply the result of floating-point division with piVal and sphereRadius and get the sphereVolume value.
At last, display the sphere volume using printf method (Line 13).
