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LiRa [457]
2 years ago
10

Suppose that a scheduling algorithm (at the level of short-term CPU scheduling) favors those processes that have used the least

processor time in the recent past. Why will this algorithm favor I/O-bound programs and yet not permanently starve CPU-bound programs?
Computers and Technology
1 answer:
alekssr [168]2 years ago
8 0

Answer:

Answer of the given question is :

I/O-bound

programs would not require much CPU usage, having short CPU bursts.

CPU-bound programs require large CPU bursts. CPU-bound processes do not

have to worry about starvation because I/O bound programs finish running

quickly allowing CPU-bound programs to use the CPU often.

Explanation:

I/O-bound

is a thread generally has a tight latency that needs a compare to computer bond thread on the windows workload.

When a mouse click then it response ASAP as compared to batch job which is running in the background.

If the outcome is slower, then the user switch the operating systems and server workload does not care about UI

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Write a loop to populate the list user_guesses with a number of guesses. The variable num_guesses is the number of guesses the u
Masja [62]

Answer:

num_guesses = int(input())

user_guesses = []

for i in range(num_guesses):

    x = int(input())

    user_guesses.append(x)

   

print(user_guesses)

Explanation:

This solution is provided in Python

This line prompts the user for a number of guesses

num_guesses = int(input())

This line initializes an empty list

user_guesses = []

This loop lets user input each guess

for i in range(num_guesses):

This line takes user input for each guess

    x = int(input())

This appends the input to a list

    user_guesses.append(x)

This prints the user guesses    

print(user_guesses)

6 0
1 year ago
Olivia creates a personal budget. She enters her current savings account balance in cell D3. In cell A3, she calculates her inco
alexdok [17]

Answer is :

=D3+A3-B3

These Cell address contain following statement:

D3= Olivia saving account balance

A3= Olivia 3 month income

B3= Olivia 3 month expense

so, Expense are also deducted from income and income is added into saving balance.

In this situation we are use this formula:

=D3+A3-B3

5 0
1 year ago
A(n) key is the set of steps used to convert an unencrypted message into an encrypted sequence of bits that represent the messag
a_sh-v [17]

Answer:

Algorithm

Explanation:

Algorithm is a set of instructions designed to perform a specific task, an independent sequence of actions to be perform to solve a problem and instruction for performing a computation.

Algorithm is A(n) key set of steps used to convert an unencrypted message into an encrypted sequence of bits that represent the message; it sometimes refers to the programs that enable the cryptographic processes.

5 0
1 year ago
Read 2 more answers
A company is performing an analysis on the computers at its main office. The computers are spaced along a single row. The analys
harina [27]

Answer:

array = input("Enter the list of computer memory: ").split(',')

int_arr = [int(x) for x in array]

segment = int(input("Enter the length of segment to analyze: "))

list_len = len(int_arr)

segList = []

mini = []

for x,i in enumerate(int_arr):

   seg = int_arr[i-1:segment+i-1]

   if len(seg) == segment:

       segList.append(seg)

for x in segList:

   mini.append(min(x))

result = mini.index(min(mini))

print("Segment with the minimum memory is: ",segList[result])

Explanation:

The python program prints out the segment after analysis, with the smallest disk memory space. The code gets the array of computer rows from the user input and segments the array with the number of segment input, then the minimum is compared for all segments in the network.

5 0
1 year ago
Give the logical function for the following: If cell B7 equals 12, check contents of cell B10. If cell B10 is 10, then the value
ASHA 777 [7]

Answer:

=IF( B7 = 12, ( IF( B10 = 10,"YES", "")), 7) and PRESS ENTER

Explanation:

the above logical if function checks the following

-IF cell B7 is 12, if true, check the value of cell B10, IF cell B10 contains 10 the function should produce YES as output to whatever cell selected, IF B10 is not 10 output of the function should be an empty string, IF B7 is not equal to 12 the the output of the function should be 7.

5 0
2 years ago
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