Answer:
Python code given below
Explanation:
def calculate_storage(filesize):
block_size = 4096
full_blocks = filesize // block_size
partial_block = filesize % block_size
if partial_block > 0:
return (full_blocks + 1) * block_size
return filesize
print(calculate_storage(1))
print(calculate_storage(4096))
print(calculate_storage(4097))
Answer:
The Proper codes in Line a and Line b is given below
average=Sum/3
print (" Average is = ", average)
Explanation:
In the given question it calculated the sum but the program does not calculate the average of the 3 numbers.The average of the 3 number is calculated by using average=Sum/3 statement so we add this code in Line a then After that print the value of average by using the print function so we add this code in Line b.
Browsers ignore any values specified for the left or top properties under _____ positioning.
B
Base on the question, and in my further computation, the possible answers would be the following and I hope you are satisfied with my answer and feel free to ask for more.
- If you want to determine the Thevenin equivalent voltage and resistance without overloading the battery, then apply some known resistance
<span><span>RL</span><span>RL</span></span> and measure the output voltage as <span><span>VL</span><span>VL</span></span>. Measure the voltage without a load as <span><span>V<span>OC</span></span><span>V<span>OC</span></span></span>. The voltage divider equation tells us that
<span><span><span>VL</span>=<span>V<span>OC</span></span><span><span>RL</span><span><span>R<span>TH</span></span>×<span>RL</span></span></span></span><span><span>VL</span>=<span>V<span>OC</span></span><span><span>RL</span><span><span>R<span>TH</span></span>×<span>RL</span></span></span></span></span>
Solve for <span><span>R<span>TH</span></span><span>R<span>TH</span></span></span>, and you know that <span><span><span>V<span>TH</span></span>=<span>V<span>OC</span></span></span><span><span>V<span>TH</span></span>=<span>V<span>OC</span></span></span></span>.
int firstNumber,secondNumber = -1, duplicates = 0;
do {
cin >> firstNumber;
if ( secondNumber == -1) {
secondNumber = firstNumber;
}else {
if ( secondNumber == firstNumber )
duplicates++;
else
secondNumber = firstNumber;
}
} while(firstNumber > 0 );
cout << duplicates;
