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arlik [135]
2 years ago
5

A circuit contains three resistors connected in parallel. The value of R1 is 2 K , the value or R2 is 6 K , and the value of R3

is 10 K . If the supplied voltage is 100 VDC, what is the total power in the circuit
Computers and Technology
1 answer:
mezya [45]2 years ago
6 0
In a parallel connection, the voltage is same in every branch.
Now, three <span>three resistors connected in parallel.
R1 = 2k ohm
</span>R2 = 6k ohm
R3 = 10k ohm
in parallel, net resisitance  = \frac{ R_{1}R_{2}R_{3} }{R_{1}R_{2} + R_{2}R_{3} + R_{3}R_{1}}

Now, putting the values, we get, R net = 1.30 k ohm.
Ans, voltage = 100 VDC
Thus, power = \frac{ V^{2} }{R} = \frac{ 100^{2} }{1.3 k} \\ \\ where \\ k = 10^{3} 
                      = 7.69 Watt
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I'm going to assume this is Java, because you said "method" meaning it will be some sort of object oriented language, and Java's really common. Here would be the full program, but you can just take the method out isolated if you need it.

package lastname;

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   public static void main(String[] args) {

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       // Output: Acord G.

   }

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This program will store roster and rating information for a soccer team. Coaches rate players during tryouts to ensure a balance
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Answer:

Question Options :

(1) Prompt the user to input five pairs of numbers: A player’s jersey number (0 – 99) and the player’s rating (1 – 9). Store the jersey numbers in one int array and the ratings in another int array. Output these array(i.e., output the roster).

(2) Implement a menu of options for a user to modify the roster. Each option is represented by a single character. The program initially outputs the menu, and outputs the menu after a user chooses an option. The program ends when the user chooses the option to Quit. For this step, the other options do nothing. (2 pt)

(3) Implement the “Output roster” menu option. (1 pt)

(4) Implement the “Add player” menu option. Prompt the user for a new player’s jersey number and rating. Append the values to the two arrays. (1 pt)

(5) Implement the “Delete player” menu option. Prompt the user for a player’s jersey number. Remove the player from the roster (delete the jersey number and rating). (2 pts)

(6) Implement the “Update player rating” menu option. Prompt the user for a player’s jersey number. Prompt again for a new rating for the player, and then change that player’s rating. (1 pt)

(7) Implement the “Output players above a rating” menu option. Prompt the user for a rating. Print the jersey number and rating for all players with ratings above the entered value. (2 pts)

/******************************************************************************

This program will store roster and rating information for a soccer team.

                             

*******************************************************************************/

#include <iostream>

#include <vector>

using namespace std;

int main() {

   vector< int> jerseyNumber;

   vector< int> rating;

   int temp;

   for (int i = 1; i <= 5; i++) {

       cout << "\nEnter player " << i << "'s jersey number: ";

       cin >> temp;

       if ((temp >= 0) && (temp <= 99)){

           jerseyNumber.push_back(temp);}

       cout << "Enter player " << i << "'s rating: ";

       cin >> temp;

       if ((temp >= 0) && (temp <= 9)){

       rating.push_back(temp);}

       cout << endl;

   } cout << endl;

   cout << "ROSTER" << endl;

   for (int i = 0; i < 5; i++)

cout << "Player " << i + 1 << " -- " << "Jersey number: " << jerseyNumber.at(i) << ", Rating: " << rating.at(i) << endl;

   char option;

   while (true) {

       cout << endl;

       cout << "MENU" << endl;

       cout << "a - Add player" << endl;

       cout << "d - Remove player" << endl;

       cout << "u - Update player rating" << endl;

       cout << "r - Output players above a rating" << endl;

       cout << "o - Output roster" << endl;

       cout << "q - Quit" << endl << endl;

       cout << "Choose an option: " << endl;

       cin >> option;

       switch (option) {

           case 'a':

           case 'A':

               cout << "Enter another player's jersey number: " << endl;

               cin >> temp;

               if ((temp >= 0) && (temp <= 99)){

                   jerseyNumber.push_back(temp);}

               cout << "Enter another player's rating: " << endl;

               cin >> temp;

               if ((temp >= 0) && (temp <= 9)){

                   rating.push_back(temp);}

               break;

           case 'd':

           case 'D':

               cout << "Enter a jersey number: ";

               cin >> temp;

               for (int i = 0; i < jerseyNumber.size(); i++) {

                   if (jerseyNumber.at(i) == temp) {

                       jerseyNumber.erase(jerseyNumber.begin() + i);

                       rating.erase(rating.begin() + i);

                       break; }

               } break;

           case 'u':

           case 'U':

               cout << "Enter a jersey number: ";

               cin >> temp;

               for (int i = 0; i < jerseyNumber.size(); i++) {

                   if (jerseyNumber.at(i) == temp) {

                       cout << "Enter a new rating " << "for player: ";

                       cin >> temp;

                       rating.at(i) = temp;

                       break; }

               } break;

           case 'r':

           case 'R':

               cout << "Enter a rating: ";

               cin >> temp;

               cout << "\nABOVE " << temp << endl;

               for (int i = 0; i < jerseyNumber.size(); i++)

                   if (rating.at(i) > temp)

               cout << "Player " << i + 1 << " -- " << "Jersey number: " << jerseyNumber.at(i)

               << ", Rating: " << rating.at(i) << endl;

               break;

           case 'o':

           case 'O':

               cout << "ROSTER" << endl;

               for (int i = 0; i < jerseyNumber.size(); i++)

               cout << "Player " << i + 1 << " -- " << "Jersey number: " << jerseyNumber.at(i)

               << ", Rating: " << rating.at(i) << endl;

               break;

           case 'q':

               return 0;

               default: cout << "Invalid menu option." << " Try again." << endl;

       }

     }

   }

Explanation:

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Answer:

  1. def driving_cost(driven_miles, miles_per_gallon, dollars_per_gallon):
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  3.    cost = gallon_used * dollars_per_gallon  
  4.    return cost  
  5. miles_per_gallon = float(input("Input miles per gallon: "))
  6. dollars_per_gallon = float(input("Input dollar per gallon: "))
  7. cost1 = driving_cost(10, miles_per_gallon, dollars_per_gallon)
  8. cost2 = driving_cost(50, miles_per_gallon, dollars_per_gallon)
  9. cost3 = driving_cost(400, miles_per_gallon, dollars_per_gallon)
  10. print("$ %.2f" % cost1)
  11. print("$ %.2f" % cost2)
  12. print("$ %.2f" % cost3)

Explanation:

The solution is written in Python 3.

Firstly, create a function driving_cost that takes three parameters, driven_miles, miles_per_gallon and dollars_per_gallon (Line 1). In the function, calculate the gallon consumption by applying formula driven_miles / miles_per_gallon and then use it to calculate the cost (Line 2 - 3). Return the cost as output (Line 4).

In the main program, prompt user to input miles per gallon and dollars per gallon and then use these input values as arguments to call the function driving_cost function for three times with each time with different driven_miles value (Line 6 - 11).

At last, use formatted print to display the output to two decimal points (Line 13 - 15).

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