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dsp73
1 year ago
13

Write a program to determine all pairs of positive integers, (a, b), such that a < b < 1000 and [a2 + b2 + 1)/(ab) is an i

nteger.
Computers and Technology
1 answer:
alina1380 [7]1 year ago
5 0

Answer:

1. We must import the packages for the array list

2. We create the array to store the data

3. We make the first for cycle for 1000 values

4. The second for cycle for the variable a

5. We make the operation

6. Cast the result to an Integer and check if they are equivalent

7. We print the result

Explanation:

package javaapplication16;

import java.util.ArrayList;

public static void main(String[] args) {

ArrayList result = new ArrayList();

       for(int b = 0; b < 1000; b++) {

           for(int a = 0; a < b; a++) {

               double calculatedResult = (Math.pow(a, 2) + Math.pow(b, 2) + 1) / (a * b);

               if (calculatedResult == (int)calculatedResult) {

                   result.add("[" + a + "," + b + "]");

               }

           }

       }

       System.out.println("Result: " + result);

}

You might be interested in
#Write a function called fancy_find. fancy_find should have #two parameters: search_within and search_for. # #fancy_find should
Inessa05 [86]

Answer:

Here is the Python program:

def fancy_find(search_within , search_for):  # function definition of fancy_find function that takes two parameters

   index = 0  #to store the index of search_within where the search_for string is found

   if search_for in search_within:  #checks if the string search_for is present in string search_within

       sf = search_for[0]  #points to the first character of the search_for

       for sw in search_within:  #iterates through search_within

           if sw == sf:  #if the first character of search_for is equal to the character at sw index of search_within

               if search_within[index:index+len(search_for)] == search_for:  #checks if the value of search_for is found in search_within

                   print(search_for,"found at index",index,"!")  #if above condition is true prints the message "[search_for] found at index [index]!", with [search_for] and [index] replaced by the value of search_for and the index at which it is found

                   return ""  

           index += 1  #increments value of index at each iteration

   print(search_for,"is not found within", search_within)  #if search_for is not found within search_within, prints message "[search_for] was not found within [search_within]!" with the values of search_for and search_within.

   return ""    

#following two statements are used to test the working of above function

print(fancy_find("ABCDEF", "DEF"))  #calls fancy_find() passing "ABCDEF" as search_within and "DEF" as search_for

print(fancy_find("ABCDEF", "GHI")) #calls fancy_find() passing "ABCDEF" as search_within and "GHI" as search_for

Explanation:

The program is well explained in the comments. I will explain the working of the function with the help of an example:

Suppose

search_within = "ABCDEF"

search_for = "DEF"

We have to find if search_for i.e. DEF is present in search_within i.e. ABCDEF

if search_for in search_within statement checks using in operator that if DEF is included in ABCDEF. Here this condition evaluates to true so the next statement sf = search_for[0]  executes which sets the first element of search_for i.e. D to sf. So sf = 'D'

for sw in search_within this statement has a for loop that iterates through ABCDEF and works as following:

At first iteration:

sw contains the first character of search_within  i.e. A

if sw == sf: condition checks if the first character of the search_for i.e. D is equal to sw i.e. A. Its not true so the program control moves to this statement:

index += 1 This increases the value of index by 1. index was initialized to 0 so now it becomes 1. Hence index=1

At second iteration:

sw contains the second character of search_within  i.e. B

if sw == sf: condition checks if the first character of the search_for i.e. D is equal to sw i.e. B Its not true so the program control moves to this statement:

index += 1 This increases the value of index by 1. index was initialized to 0 so now it becomes  2. Hence index=2

At third iteration:

sw contains the third character of search_within  i.e. C

if sw == sf: condition checks if the first character of the search_for i.e. D is equal to sw i.e. C Its not true so the program control moves to this statement:

index += 1 This increases the value of index by 1. index was initialized to 0 so now it becomes  3. Hence index=3

At fourth iteration:

sw contains the third character of search_within  i.e. D

if sw == sf: condition checks if the first character of the search_for i.e. D is equal to sw i.e. D. Its true so so the program control moves to this statement:

  if search_within[index:index+len(search_for)] == search_for:

current value of index=3

len(search_for) returns the length of DEF i.e. 3

So the if condition checks for the search_for in search_within. The statement becomes:

if search_within[3:3+3] == search_for:

search_within[3:3+3]  means from 3rd index position of search_within to 6-th index position of the search_within. This means from 4th element of search_within i.e. D to the last. Hence search_within[3:3+3] is equal to DEF.

search_for = DEF so

if search_within[3:3+3] == search_for: checks if

search_within[3:3+3] = DEF is equals to search_for = DEF

Yes it is true so

print(search_for,"found at index",index,"!") statement is executef which prints the following message:

DEF found at index 3!

This output is because search_for = "DEF" and index=3

5 0
2 years ago
Explain why Windows and Linux implements multiple locking mechanisms. Describe the circumstances under which they use spinlocks,
galben [10]

Answer:

The description for the given question is described in the explanation section below.

Explanation:

Depending on the needs of the device programmers these OS have various locking frameworks. Spinlocks become beneficial for preemptive multitasking processes during which a thread will operate in such an active loop instead of risking a rest queue latency. Mutexes become beneficial to utility lockers.

  • Solaris 2 employs flexible mutexes, indicating something like this on preemptive multitasking computers, the mutex is introduced with either a spinning switch.
  • Semaphores and state variations are much more effective methods for consistency where a commodity needs to be managed for such a prolonged period of time because spinning is unstable over a prolonged time.

8 0
2 years ago
Which statement correctly describes an adaptive score?
d1i1m1o1n [39]

B. An adaptive score changes in response to player actions in the game.

it <em>could</em> be D. if the context was in a musical score...like an orchestra...I think that's just there to be funny

5 0
2 years ago
Read 2 more answers
The population of town A is less than the population of town B. However, the population of town A is growing faster than the pop
defon

Answer:

#include<iostream>

using namespace std;

void main()

{

int townA_pop,townB_pop,count_years=1;

double rateA,rateB;

cout<<"please enter the population of town A"<<endl;

cin>>townA_pop;

cout<<"please enter the population of town B"<<endl;

cin>>townB_pop;

cout<<"please enter the grothw rate of town A"<<endl;

cin>>rateA;

cout<<"please enter the grothw rate of town B"<<endl;

cin>>rateB;

while(townA_pop < townB_pop)//IF town A pop is equal or greater than town B it will break

{

townA_pop = townA_pop +( townA_pop * (rateA /100) );

townB_pop = townB_pop +( townB_pop * (rateB /100) );

count_years++;

}

cout<<"after "<<count_years<<" of years the pop of town A will be graeter than or equal To the pop of town B"<<endl;

}

Explanation:

3 0
2 years ago
(1) Prompt the user to enter two words and a number, storing each into separate variables. Then, output those three values on a
denpristay [2]

Answer:Prompt the user to enter two words and a number, storing each into separate variables. Then, output those three values on a single line separated by a space. (Submit for 1 point) Ex: If the input is: yellow Daisy 6 the output after the prompts is: You entered: yellow Daisy 6 Note: User input is not part of the program output. (2) Output two passwords using a combination of the user input. Format the passwords as shown below. (Submit for 2 points, so 3 points total). Ex: If the input is: yellow Daisy 6 the output after the prompts is: You entered: yellow Daisy 6 First password: yellow_Daisy Second password: 6yellow6 (3) Output the length of each password (the number of characters in the strings). (Submit for 2 points, so 5 points total). Ex: If the input is: yellow Daisy 6 the output after the prompts is: You entered: yellow Daisy 6 First password: yellow_Daisy Second password: 6yellow6 Number of characters in yellow_Daisy: 12 Number of characters in 6yellow6: 8

I have tried several different ways of doing this, but I keep getting an error on line 6

Explanation:

7 0
1 year ago
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