Answer:
- def is_prime(n):
- for i in range(2, n):
- if(n % i == 0):
- return False
- return True
-
- prime_truths = [is_prime(x) for x in range(2,101)]
- print(prime_truths)
Explanation:
The solution code is written in Python 3.
Presume there is a given function is_prime (Line 1 - 5) which will return True if the n is a prime number and return False if n is not prime.
Next, we can use the list comprehension to generate a list of True and False based on the prime status (Line 7). To do so, we use is_prime function as the expression in the comprehension list and use for loop to traverse through the number from 2 to 100. The every loop, one value x will be passed to is_prime and the function will return either true or false and add the result to prime_truth list.
After completion of loop within the comprehension list, we can print the generated prime_truths list (Line 8).
Answer:
Following are the method definition to this question:
public String notice_bill(double amount) //defining method
{
return this.name+", account number "+this.currAccNum+", please pay $"+amt; //return value.
}
Explanation:
In the given question some information is missing, that is example So, method definition to this question can be described as follows:
- In the above method definition a string method "notice_bill" is declared, which accepts a double value in its parameter, that is "amount".
- Inside the method, this keyword is used, that hold values and return its value as a message.
Answer:
The answer to the given question is given bellow in the explanation section:
Explanation:
<p>This is python code</p>
<p>In python when you enter input into the input function as given:</p>
<code> answer = input("How much does the sample weigh in grams? ") </code>
I will be taken as string.
So I have to convert this string to number format here the given data is float value i-e 3.5
so let convert it. using float function.
<code> answer = float (input("How much does the sample weigh in grams? ") ) </code>
Answer:
The most straight forward way to do it: in general string are zero index based array of characters, so you need to get the length of the string, subtract one and that will be the last character, some expressions in concrete languages would be:
In Python:
name = "blair"
name[len(name) - 1]
In JavaScript:
name = "blair"
name[name.length - 1]
In C++:
#include <string>
string name = "blair";
name[name.length() - 1];
Answer:
I get 0x55 and this the linking address of the main function.
use this function to see changes:
/* bar6.c */
#include <stdio.h>
char main1;
void p2()
{
printf("0x%X\n", main1);
}
Output is probably 0x0
you can use your original bar6.c with updaated foo.c
char main;
int main() // error because main is already declared
{
p2();
//printf("Main address is 0x%x\n",main);
return 0;
}
Will give u an error
again
int main()
{
char ch = main;
p2(); //some value
printf("Main address is 0x%x\n",main); //some 8 digit number not what printed in p2()
printf("Char value is 0x%x\n",ch); //last two digit of previous line output
return 0;
}
So the pain in P2() gets the linking address of the main function and it is different from address of the function main.
Now char main (uninitialized) in another compilation unit fools the compiler by memory-mapping a function pointer on a char directly, without any conversion: that's undefined behavior. Try char main=12; you'll get a multiply defined symbol main...
Explanation:
