Answer:
Explanation:
Assuming the spoofed 1.2.3.4, it will be sent out ARP to a router that is alive and get it MAC. Then the spoofed packet will be able to be sent out. If A spoofed 10.0.2.30, because it is a local address, it will send an ARP to the machine for been able to get the MAC. But, the IP address 10.0.2.30 is not original making it to be fake, so it will not replay to A, for this reason the spoofed packet cannot be sent out.
Answer:
I only
Explanation:
Digital certificate are virtual encrypted keys or password used by individuals or organization as a means of establishing secure connections between servers and websites so as to be able to authenticate that only the legitimate people are having access to the information.
<u>Answer:</u>
I am writing <em>partial code in</em> <em>c++ to calculate weighted average</em>. The weighted average should be calculated based on multiplying the test score and its <em>respective weight and finally add all the test score.</em>
<u>Explanation:</u>
<em>int arrtestscore[100];</em>
<em>int arrweight[100];</em>
<em>int n;</em>
<em>double weightedavg;</em>
<em>cout<<”Enter the number of test score for which weighted average needs to be calculated”;</em>
<em>cin>>n;</em>
<em>for(int x = 0; x <n;x++)</em>
<em>{</em>
<em> cout<<”Enter test score :” + (x+1) ;</em>
<em> cin>>arrtestscore[x];</em>
<em> count<<”Enter the respective weight:”;</em>
<em> cin>>arrweight[x];</em>
<em>}</em>
<em>for (int i=0; i<n;i++)</em>
<em>{</em>
<em> weightedavg = weightedavg + (arrtestscore[i] * arrweight[i])</em>
<em>}</em>
<em>cout<<”weighted average = “ <<weightedavg; </em>
Answer:
Explanation:
Farmers are always both directly and indirectly connected to each other
Their network is mostly strong
Networks become weak only on the edges (ends) of the river but doesn't completely dimnish
With the available network length, the center of river bank forms the strongest network of all and becomes a key player in defining the balance property of overall network
The network is very well structurally balanced and we can see that through the below image
20 miles 10 20 30 40 50
See attachment file for diagram
Considering the total length of river as 50miles and and the center of the whole length will be at 25th mile. From that point, if we consider a farmer will be be having friends for a length of 20miles both along upstream and downstream.
By this he'll be in friend with people who are around 80% of the total population. As me move from this point the integrity increases and this results in a highly balanced structural network.
The risk vulnerability assessment is the answer