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Alex787 [66]
2 years ago
15

A program is loaded into _________ while it is being processed on the computer and when the program is not running it is stored

in ______________. A. memory, secondary storage B. memory, the CPU C. the monitor, memory D. secondary storage, memory
Computers and Technology
2 answers:
den301095 [7]2 years ago
7 0

Answer:

idk

Explanation:

erik [133]2 years ago
4 0
Idkkkkkkkkkkkkkkkkkkk
You might be interested in
Rideshare companies like Uber or Lyft track the x,y coordinates of drivers and customers on a map. If a customer requests a ride
TiliK225 [7]

Answer:

The program in Java is as follows:

import java.util.*;

public class Main{

 public static void main (String[]args){

   Scanner input = new Scanner(System.in);

   double user[] = new double[2];    double dr1[] = new double[2];

   double dr2[] = new double[2];    double dr3[] = new double[2];    

   System.out.print("Enter user coordinates: ");

   for(int i =0;i<2;i++){        user[i] = input.nextDouble();    }

   System.out.print("Enter driver 1 coordinates: ");

   for(int i =0;i<2;i++){        dr1[i] = input.nextDouble();    }

   System.out.print("Enter driver 2 coordinates: ");

   for(int i =0;i<2;i++){        dr2[i] = input.nextDouble();    }

   System.out.print("Enter driver 3 coordinates: ");

   for(int i =0;i<2;i++){        dr3[i] = input.nextDouble();    }

   double dr1dist = Math.abs(user[0] - dr1[0]) + Math.abs(user[1] - dr1[1]);

   double dr2dist = Math.abs(user[0] - dr2[0]) + Math.abs(user[1] - dr2[1]);

   double dr3dist = Math.abs(user[0] - dr3[0]) + Math.abs(user[1] - dr3[1]);

   System.out.println("Estimated pickup time of driver 1 "+(3.5 * dr1dist)+" minutes");

   System.out.println("Estimated pickup time of driver 2 "+(3.5 * dr2dist)+" minutes");

   System.out.println("Estimated pickup time of driver 3 "+(3.5 * dr3dist)+" minutes");

 }

}

Explanation:

The following array declarations are for the customer and the three drivers

<em>    double user[] = new double[2];    double dr1[] = new double[2];</em>

<em>    double dr2[] = new double[2];    double dr3[] = new double[2];    </em>

This prompts the user for the customer's coordinates

   System.out.print("Enter user coordinates: ");

This gets the customer's coordinate

   for(int i =0;i<2;i++){        user[i] = input.nextDouble();    }

This prompts the user for the driver 1 coordinates

   System.out.print("Enter driver 1 coordinates: ");

This gets the driver 1's coordinate

   for(int i =0;i<2;i++){        dr1[i] = input.nextDouble();    }

This prompts the user for the driver 2 coordinates

   System.out.print("Enter driver 2 coordinates: ");

This gets the driver 2's coordinate

   for(int i =0;i<2;i++){        dr2[i] = input.nextDouble();    }

This prompts the user for the driver 3 coordinates

   System.out.print("Enter driver 3 coordinates: ");

This gets the driver 3's coordinate

   for(int i =0;i<2;i++){        dr3[i] = input.nextDouble();    }

This calculates the distance between driver 1 and the customer

   double dr1dist = Math.abs(user[0] - dr1[0]) + Math.abs(user[1] - dr1[1]);

This calculates the distance between driver 2 and the customer

   double dr2dist = Math.abs(user[0] - dr2[0]) + Math.abs(user[1] - dr2[1]);

This calculates the distance between driver 3 and the customer

   double dr3dist = Math.abs(user[0] - dr3[0]) + Math.abs(user[1] - dr3[1]);

The following print statements print the estimated pickup time of each driver

<em>   System.out.println("Estimated pickup time of driver 1 "+(3.5 * dr1dist)+" minutes");</em>

<em>    System.out.println("Estimated pickup time of driver 2 "+(3.5 * dr2dist)+" minutes");</em>

<em>    System.out.println("Estimated pickup time of driver 3 "+(3.5 * dr3dist)+" minutes");</em>

7 0
2 years ago
A Consider the following method definition. The method printAllCharacters is intended to print out every character in str, start
ozzi

Answer:

<em>(c) The method call, which worked correctly before the change, will now cause a run-time error because it attempts to access a character at index 7 in a string whose last element is at index 6.</em>

<em />

Explanation:

Given

printAllCharacters method and printAllCharacters("ABCDEFG");

Required

What happens when  x < str.length() is changed to x <= str.length()

First, we need to understand that str.length()  gets the length of string "ABCDEFG"

There are 7 characters in "ABCDEFG".

So: str.length()  = 7

The first character is at index 0 and the last is at index 6

Next, we need to simplify the loop:

for (int x = 0; x< str.length(); x++) means for (int x = 0; x< 7; x++)

The above loop will iterate from the character at the 0 index to the character at the 6th index

while

for (int x = 0; x<=str.length(); x++) means for (int x = 0; x<=7; x++)

The above loop will iterate from the character at the 0 index to the character at the 7th index

Because there is no character at the 7th index, the loop will return an error

Hence: (c) is correct

7 0
2 years ago
What is retrieved from a search containing two terms separated<br> by the AND operator?
egoroff_w [7]

Answer:

A AND B= 1 or 0

1 1  1

0 1  0

1 0  0

0 0 0

So, as explained above if both are 1 we then only get 1, or else we get 0 always in case of AND which is a logical operator, whose output can be 0 or 1 only. This is being depicted above.

Explanation:

If both are 1 we get 1 or always else, we get the output =0.

8 0
2 years ago
Write a recursive, string-valued method, replace, that accepts a string and returns a new string consisting of the original stri
ch4aika [34]

Answer:

Check the explanation

Explanation:

public String replace(String sentence){

  if(sentence.isEmpty()) return sentence;

  if(sentence.charAt(0) == ' ')

     return '*' + replace(sentence.substring(1,sentence.length()));

  else

     return sentence.charAt(0) +            replace(sentence.substring(1,sentence.length()));

3 0
2 years ago
A layer 2 switch is used to switch incoming frames from a 1000base-t port to a port connected to a 100base-t network. which meth
fredd [130]
<span>Shared memory buffering would work best. This would give the ports the best allocation of resources, using only those that are the most active and best allocated for the size of the frames being transmitted in the current traffic. In addition, any port can store these frames, instead of being specifically allocated as per other types of memory buffering.</span>
7 0
2 years ago
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