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2 years ago

15

A program is loaded into _________ while it is being processed on the computer and when the program is not running it is stored

in ______________. A. memory, secondary storage B. memory, the CPU C. the monitor, memory D. secondary storage, memory

Computers and Technology

2 answers:

den301095 [7]2 years ago

7 0

Answer:

idk

Explanation:

erik [133]2 years ago

4 0

Idkkkkkkkkkkkkkkkkkkk

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A vehicle fails an HC emission test at idle and 2,500 rpm, and the engine has an acceleration stumble. The heated oxygen sensor

Natalija [7]

I would say a defective O2 sensor

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2 years ago

A 1.17 g sample of an alkane hydrocarbon gas occupies a volume of 674 mL at 28°C and 741 mmHg. Alkanes are known to have the gen

Nina [5.8K]

Answer:

C3H8

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Mass of alkane = 1.17g

Volume (V) = 674 mL

Temperature (T) = 28°C

Pressure (P) = 741 mmHg.

Gas constant (R) = 0.08206 atm.L/Kmol

Step 2:

Conversion to appropriate unit.

For Volume:

1000mL = 1L

Therefore, 674mL = 674/1000 = 0.674L

For Temperature:

Temperature (Kelvin) = Temperature (celsius) + 273

Temperature (celsius) = 28°C

Temperature (Kelvin) = 28°C + 273 = 301K

For Pressure:

760mmHg = 1atm

Therefore, 741 mmHg = 741/760 = 0.975atm

Step 3:

Determination of the number of mole of the alkane..

The number of mole of the alkane can be obtained by using the ideal gas equation. This is illustrated below:

Volume (V) = 0.674L

Temperature (T) = 301K

Pressure (P) = 0.975atm

Gas constant (R) = 0.08206 atm.L/Kmol

Number of mole (n) =?

PV = nRT

n = PV /RT

n = (0.975 x 0.674)/(0.08206x301)

n = 0.0266 mole

Step 4:

Determination of the molar mass of the alkane.

Mass of alkane = 1.17g

Number of mole of the alkane = 0.0266mole

Molar Mass of the alkane =?

Number of mole = Mass/Molar Mass

Molar Mass = Mass/number of mole

Molar Mass of the alkane = 1.17/0.0266 = 44g/mol

Step 5:

Determination of the molecular formula of the alkane.

This is illustrated below:

The general formula for the alkane is CnH2n+2

To obtain the molecular formula for the alkane we shall assume n = 1, 2, 3 or more till we arrive at molar Mass of 44.

When n = 1

CnH2n+2 = CH4 = 12 + (4x1) = 16g/mol

When n = 2

CnH2n+2 = C2H6 = (12x2) + (6x1) = 30g/mol

When n = 3

CnH2n+2 = C3H8 = (12x3) + (8x1) = 44g/mol

We can see that when n is 3, the molar mass is 44g/mol.

Therefore, the molecular formula for the alkane is C3H8.

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2 years ago

In three to four sentences, describe why CEOs (the chief executive officers, that is, the leaders of large companies) make very

mixer [17]

Well, CEOs are on the top of the food chain. It takes a lot of work and ambition to become one, and once they are one, <span>CEOs accept a huge amount of responsibility - that means having to take blame if things go wrong and </span><span>having more tasks to complete such as having to attend numerous meetings, make decisions. They are also on the board of directors.</span>

Assistants do not have to do as much, they likely won't have that much responsibility or experience, their tasks revolve around ensuring meetings are scheduled and performing other ad-hoc duties.

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2 years ago

Computers represent color by combining the sub-colors red, green, and blue (rgb). Each sub-color's value can range from 0 to 255

maxonik [38]

Answer:

Follows are the code to this question:

#include <iostream>//defining a header file

using namespace std; //using namespace

int main() //defining main method

{

int red,green,blue,s; //defining integer variable

cout<<"Enter value: \n ";//print message

cin>>red>>green>>blue; //input value

if(red<green && red<blue)//defining if block that checks red value

s=red;//store red variable value to s variable

else if(green<blue)//defining else if block that checks green value less then blue

s=green;//store green variable value in s variable

else//defining else block

s=blue; //store blue variable value in s variable

//calculating red, green, blue value

red=red-s;//store red value

green=green-s;//store green value

blue=blue-s;//store blue value

cout<<red<<" "<<green<<" "<<blue;

}

Output:

Enter value:

130

50

130

80 0 80

Explanation:

In the above code, inside the Main method, four integer variable "red, green, blue, and s" is defined, in which "red, green, and blue" is used for input the value from the user end.

In the next step, a conditional statement is used, that checks the red variable value, if the condition is true, it will store its value in the "s" variable, otherwise, it will go to else if block.
In this block, the green variable checks its value less than then blue variable value, if the condition is true, it will store the green value in the "s" variable, otherwise, it will goto else block.
In this block, it will store the blue variable value in the "s" variable, and subtract the value of "red, green, and blue" value from "s" and store its value, and at the last, it will print its value.

4 0

2 years ago

Write the printitem() method for the base class. sample output for below program: last name: smith first and last name: bill jon

ella [17]

The question involves basic polymorphism. The following is the partial flow of the program.

baseItemPtr = new BaseItem();
baseItemPtr.setLastName("Smith");

derivedItemPtr = new DerivedItem();
derivedItemPtr.setLastName("Jones");
derivedItemPtr.setFirstName("Bill");

itemList.add(baseItemPtr);
itemList.add(derivedItemPtr);

for (i = 0; i < itemList.size(); ++i) {
itemList.get(i).printItem();
}

return;

7 0

2 years ago

Read 2 more answers