An attribute of a website that will indicate a more reliable source of information is when the site ends in ".edu". It is a top-level domain for education. It would mean that this particular site is linked to universities, colleges or other educational sites thus it gives more information that is real and factual.
The below code will help you to solve the given problem and you can execute and cross verify with sample input and output.
#include<stdio.h>
#include<string.h>
int* uniqueValue(int input1,int input2[])
{
int left, current;
static int arr[4] = {0};
int i = 0;
for(i=0;i<input1;i++)
{
current = input2[i];
left = 0;
if(current > 0)
left = arr[(current-1)];
if(left == 0 && arr[current] == 0)
{
arr[current] = input1-current;
}
else
{
for(int j=(i+1);j<input1;j++)
{
if(arr[j] == 0)
{
left = arr[(j-1)];
arr[j] = left - 1;
}
}
}
}
return arr;
}
Answer:
See explanation
Explanation:
Replace the ____ with the expressions in bold and italics
1) <em> return km</em>
return km returns the result of the computation
2) = <em>convert_distance(my_trip_miles)</em>
convert_distance(my_trip_miles) calls the function and passes my_trip_miles to the function
3) + <em>str(my_trip_km)</em>
The above statement prints the returned value
4) +str(my_trip_km * 2)
The above statement prints the returned value multiplied by 2
Answer:
A Standard Lens
Explanation:
Since David wants to take pictures of people around him and also the objects far away, a standard lens would be fit for that.
Answer: see description
Explanation:
first we accommodate the bit pattern in a matrix of 4x4 which is the minimum length checksum field, now with even parity two-dimensional scheme we need to complete this matrix by adding one row and one column by adding at the end of each row a 1 or a 0 to complete pairs of 1's:
we have
![\left[\begin{array}{cccc}1&1&1&0\\0&1&1&0\\1&0&0&1\\1&1&0&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%261%261%260%5C%5C0%261%261%260%5C%5C1%260%260%261%5C%5C1%261%260%261%5Cend%7Barray%7D%5Cright%5D)
so we complete with this, adding a row at the end which matches a pair number of 1's
![\left[\begin{array}{ccccc}1&1&1&0&1\\0&1&1&0&0\\1&0&0&1&0\\1&1&0&1&1\\1&1&0&0&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccccc%7D1%261%261%260%261%5C%5C0%261%261%260%260%5C%5C1%260%260%261%260%5C%5C1%261%260%261%261%5C%5C1%261%260%260%260%5Cend%7Barray%7D%5Cright%5D)
