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lilavasa [31]
2 years ago
11

Write a Java class with the following methods: getArray(int numStrings) is an instance method that takes command line input (use

a Scanner's nextLine() method) to create an array of Strings whose length is numStrings and returns a reference to the array. getArray() does not print anything! getLongestString(String[] sArray) is an instance method that returns a reference to the longest String in sArray. getLongestString() does not print anything! main() creates an instance of the class and uses it to call getArray() with the argument 5, keeping a reference to the return value, then sends the array to getLongestString(), and prints the result

Computers and Technology
1 answer:
mezya [45]2 years ago
4 0

Answer:

Follows are the code to this question:

import java.util.*;//import packae for user-input  

public class Main//defining a class Main

{

public String[] getArray(int numString)//defining a method getArray

{

String[] name=new String[numString];//defining array of String values

Scanner in = new Scanner(System.in);// creating scanner class object for input values from user-end

for(int i=0;i<numString;i++)//defining for loop for input multiple values

{

System.out.print("Enter String Value :");//print message

name[i]=in.nextLine();//input values

}

return name;//return array values

}

public String getLongestString(String[] sArray)//defining a method getLongestString

{

int m=0,mi=0; //defining integer variables

for(int i=0;i<sArray.length;i++)//defining for loop for check the longest value in array

{

if(m<sArray[i].length())//defining if block that checks m varaible value greater then sArray length  

{

m=sArray[i].length();//use m to hold sArray length

mi=i;//use max_index to hold i that is loop value

}

}

return sArray[mi];//return Longest value

}

public static void main(String[] args)//defining main method

{

Main s=new Main();//Creating object of main class    

String[] n;//defining string variable n  

n=s.getArray(5);//use n varaible to call getArray method and store its value

System.out.println("Longest value is: "+s.getLongestString(n));//use print method to call getLongestString method

}

}

Output:

please find attached file.

Explanation:

In the given java program code, inside the main class two method that is "getArray and getLongestString", is defined, in which the "getArray" method uses an integer variable in its parameter and inside the method, an array is defined that use a  scanner class for input array value.

  • In the "getLongestString" pass as a parameter and inside the method, two integer variable "m and mi" is defined that use in the loop to return the longest string value.
  • In the class main method is to define that creates a class object and call the above method and use the print method to return its value.  

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Answer:

Given that:

A= 40n^2

B = 2n^3

By given scenario:

40n^2=2n^3

dividing both sides by 2

20n^2=n^3

dividing both sides by n^2 we get

20 = n

Now putting n=20 in algorithms A and B:

A=40n^2

= 40 (20)^2

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B= 16000

Now as A and B got same on n = 20, then as given:

n0 <20 for n =20

Let us take n0 = 19, it will prove A is better than B.

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8 0
2 years ago
Write a program that has the following String variables: firstName, middleName, and lastName. Initialize these with your first,
Licemer1 [7]

Answer:

The programming language is not stated; However, I'll answer your question using C++ programming language.

Comments are used for explanatory purpose

Program starts here

#include<iostream>

#include <string>

using namespace std;

int main()

{

//Declare Variables

string firstName, middleName, lastName;

char firstInitial, middleInitial, lastInitial;

/*Initialize firstName, middleName and lastName (Replace values with your details)*/

firstName = "First Name";

middleName = "Middle Name";

lastName = "Last Name";

 

// Get Initials

firstInitial = firstName.at(0);

middleInitial = middleName.at(0);

lastInitial = lastName.at(0);

 

//Print Results

cout<<"Lastname: "<<lastName<<endl;

cout<<"Firstname: "<<firstName<<endl;

cout<<"Middlename: "<<middleName<<endl;

cout<<"Last Initial: "<<lastInitial<<endl;

cout<<"First Initial: "<<firstInitial<<endl;

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Which of the following is an advantage of inserting a page number field in your document rather than inserting each page number
Artyom0805 [142]

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The following information should be relevant with respect to the page number:

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Therefore we can conclude that the advantage of inserting the page number field is that the page number field could show the current page number.

Learn more about the page number here: brainly.com/question/3063419

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The Company management has asked that you compare the OSSTMM and the PTES to determine which methodology to select for internal
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Answer:

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Explanation:

Solution

Penetration testing has several methodologies which include :OSSTMM and PTES  

The comparison between OSSTMM and PTES is stated as follows:

OSSTMM:                                                

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Metrics based

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Now,

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Now,

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Answer:

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Neoplasm related pain (acute) (chronic)

Pain in thoracic spine. M54. 6 is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes. The 2020 edition of ICD-10-CM M54.

Malignant (primary) neoplasm, unspecified

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