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2 years ago

Raj needs to apply sorting to a current list in his Word document.

Computers and Technology

2 answers:

nordsb [41]2 years ago

7 0

Answer:

The Home tab, Under paragraph

Explanation:

The Microsoft home tab houses many features.

Clipboard, paragraph, styles and editing.

Sorting can be found under the Paragraph feature

Ludmilka [50]2 years ago

4 0

Answer:

Select "Sort" from the "paragraph and text" option which is listed in the "home" tab.

Explanation:

Sorting techniques are used to sort the element either in ascending order or in descending order. When a user wants to apply the sorting techniques in any word type document then he needs to do the following task--

Select the list on which a user wants to apply the sorting techniques.
Click the Home tab from task pane on the word file and then
Click the paragraph and text from the home tab and then
Click sort and then
Chose the sorting techniques (Ascending or descending order) to apply the sort.

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1- Design a brute-force algorithm for solving the problem below (provide pseudocode): You have a large container with storage si

sladkih [1.3K]

Answer:

Pseudocode is as follows:

// below is a function that takes two parameters:1. An array of items 2. An integer for weight W

// it returns an array of selected items which satisfy the given condition of sum <= max sum.

function findSubset( array items[], integer W)

{

initialize:

maxSum = 0;

ansArray = [];

// take each "item" from array to create all possible combinations of arrays by comparing with "W" and // "maxSum"

start the loop:

// include item in the ansArray[]

ansArray.push(item);

// remove the item from the items[]

items.pop(item);

ansArray.push(item1);

start the while loop(sum(ansArray[]) <= W):

// exclude the element already included and start including till

if (sum(ansArray[]) > maxSum)

// if true then include item in ansArray[]

ansArray.push(item);

// update the maxSum

maxSum = sum(ansArray[items]);

else

// move to next element

continue;

end the loop;

// again make the item[] same by pushing the popped element

items.push(item);

end the loop;

return the ansArray[]

}

Explanation:

You can find example to implement the algorithm.

3 0

2 years ago

Write any 5 activities that help to remove bad events from the society?

vova2212 [387]

Answer:

1. Awareness program

2. Education

3. women empowerment

6 0

2 years ago

Read 2 more answers

What will be displayed after code corresponding to the following pseudocode is run? Main Set OldPrice = 100 Set SalePrice = 70 C

Tatiana [17]

Answer:

A jacket that originally costs $ 100 is on sale today for $ 80

Explanation:

Main : From here the execution of the program begins

Set OldPrice = 100 -> This line assigns 100 to the OldPrice variable

Set SalePrice = 70 -> This line assigns 70to the SalePrice variable

Call BigSale(OldPrice, SalePrice) -> This line calls BigSale method by passing OldPrice and SalePrice to that method

Write "A jacket that originally costs $ ", OldPrice -> This line prints/displays the line: "A jacket that originally costs $ " with the resultant value in OldPrice variable that is 100

Write "is on sale today for $ ", SalePrice -> This line prints/displays the line: "is on sale today for $ " with the resultant value in SalePrice variable that is 80

End Program -> the main program ends

Subprogram BigSale(Cost, Sale As Ref) -> this is a definition of BigSale method which has two parameters i.e. Cost and Sale. Note that the Sale is declared as reference type

Set Sale = Cost * .80 -> This line multiplies the value of Cost with 0.80 and assigns the result to Sale variable

Set Cost = Cost + 20 -> This line adds 20 to the value of Cost and assigns the result to Cost variable

End Subprogram -> the method ends

This is the example of call by reference. So when the method BigSale is called in Main by reference by passing argument SalePrice to it, then this call copies the reference of SalePrice argument into formal parameter Sale. Inside BigSale method the reference &Sale is used to access actual argument i.e. SalePrice which is used in BigSale(OldPrice, SalePrice) call. So any changes made to value of Sale will affect the value of SalePrice

So when the method BigSale is called two arguments are passed to it OldPrice argument and SalePrice is passed by reference.

The value of OldPrice is 100 and SalePrice is 70

Now when method BigSale is called, the reference &Sale is used to access actual argument SalePrice = 70

In the body of this method there are two statements:

Sale = Cost * .80;

Cost = Cost + 20;

So when these statement execute:

Sale = 100 * 0.80 = 80

Cost = 100 + 20 = 120

Any changes made to value of Sale will affect the value of SalePrice as it is passed by reference. So when the Write "A jacket that originally costs $ " + OldPrice Write "is on sale today for $ " + SalePrice statement executes, the value of OldPrice remains 100 same as it does not affect this passed argument, but SalePrice was passed by reference so the changes made to &Sale by statement in method BigSale i.e. Sale = Cost * .80; has changed the value of SalePrice from 70 to 80 because Sale = 100 * 0.80 = 80. So the output produced is:

A jacket that originally costs $ 100 is on sale today for $ 80

7 0

2 years ago

Which organization supports professionals who assist families in making informed choices about products and services?

Naily [24]

The organisation that would best aid families and choose the right products to buy would be the American Association of Family and Consumer Sciences. In addition, the institution is primarily composed of home economists wherein these professionals promote efficient consumer consumption of goods.

6 0

2 years ago

Read 2 more answers

Write an if-else statement to describe an integer. Print "Positive even number" if isEven and is Positive are both true. Print "

Nina [5.8K]

Answer:

C code explained below

Explanation:

#include <stdio.h>

#include <stdbool.h>

int main(void) {

int userNum;

bool isPositive;

bool isEven;

scanf("%d", &userNum);

isPositive = (userNum > 0);

isEven = ((userNum % 2) == 0);

if(isPositive && isEven){

printf("Positive even number");

}

else if(isPositive && !isEven){

printf("Positive number");

}

else{

printf("Not a positive number");

}

printf("\n");

return 0;

}

6 0

2 years ago