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expeople1 [14]
2 years ago
10

The attack in which the attacker sends a forged packet with the same source IP address and destination IP address in which the v

ictim may be tricked into sending messages to and from itself is a(n) _______________ attack. A. Teardrop B. Land C. myDoom D. echo-chargen
Computers and Technology
1 answer:
Sergeeva-Olga [200]2 years ago
7 0

Answer:

TEARDROP

Explanation:

Teardrop is a form of attack in which the attacker sends a forged packet with the same source IP address and destination IP address in which the victim may be tricked into sending messages to and from itself .

Teardrop attack also involves sending fragmented packets to a target machine in which the victim is been tricked into sending messages to and from itself. One of the fields in an IP header is the “fragment offset” field, indicating the starting position of the data contained in a fragmented packet relative to the data in the original packet.

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Write a class called Counter that represents a simple tally counter, which might be used to count people as they enter a room. T
Sonja [21]

Answer:

Code is in java

Explanation:

Code is self explanatory, added come comments to explain more about the code.

public class CounterDriver {

   public static void main(String[] args){

       // Creating counter first object

       Counter counter1 = new Counter();

       //performing 2 clicks

       counter1.click();

       counter1.click();

       // displaying counter 1 click count

       System.out.println("Total Number of counter1 clicks :"+counter1.getCount());

       // resetting counter 1 click count

       counter1.reset();

       // again displaying click count which will be 0 after reset

       System.out.println("Total Number of counter1 clicks :"+counter1.getCount());

      // Same operation goes with counter 2  

       // the only difference is that it performs 3 clicks

       Counter counter2 = new Counter();

       counter2.click();

       counter2.click();

       counter2.click();

       System.out.println("Total Number of counter2 clicks :"+counter2.getCount());

       counter2.reset();

       System.out.println("Total Number of counter2 clicks :"+counter2.getCount());

   }

}

class Counter{

   int count;

// defining constructor which will initialize count variable to 0

   public Counter(){

       this.count=0;

   }

// adding click method to increment count whenever it's called

   public void click(){

       this.count++;

   }

// getCount method will return total count

   public int getCount(){

       return this.count;

   }

// reset method will set count to 0

   public void reset(){

       this.count = 0;

   }

}

4 0
2 years ago
Write a single statement that will print the message "first is " followed by the value of first, and then a space, followed by "
nadezda [96]

Answer:

print("first is "+str(first)+" second = "+str(second))

Explanation:

The above written print statement is in python language.If first and second are strings then we need not to use str then we only have to write variable name.This statement prints the given in one line according to the question and it goes to new line after printing.

8 0
1 year ago
Program 4 - Pick color Class Create a class that randomly pick a color from an array of colors: string colors[7]; Have the color
xxMikexx [17]

Answer:

#include<cstdlib>

#include<bits/stdc++.h>

#include<time.h>

using namespace std;

class Colors{

string colors[7];

public:

void setElement(int,string);

void printAllColors();

void printRandomColor();

};

void Colors::setElement(int index,string color){

colors[index] = color;

}

void Colors::printAllColors(){

cout << "Printing all the colors:\n";

for(int i=0;i<7;i++){

cout << colors[i] <<"\t";

}

}

void Colors::printRandomColor(){

srand (time(NULL));

int index = rand() % 7;

cout<< "\n\nThe random picked color:";

cout << colors[index] << endl;

}

int main(){

Colors color;

color.setElement(0,"red");

color.setElement(1,"orange");

color.setElement(2,"yellow");

color.setElement(3,"green");

color.setElement(4,"blue");

color.setElement(5,"indigo");

color.setElement(6,"violet");

color.printAllColors();

color.printRandomColor();

}

to get the random color we are using srand and rand function. we are using time as seed to srand() function,because every time the time is changed. And based on that we are using rand() function and doing mod with 7 with the random number to get the index between 0 to 6, as ut array size is 7(0 to 6).

In the setElement(int index,string color) method we are inserting the value of colors in the colors array based on index.

In the printAllColors() function we are printing all the colors in the array.

In the printRandomColor() er are printing any random color based on rand() function.

and in main() we are initializing the string array with colors and calling the functions.

7 0
1 year ago
Read 2 more answers
suppose that you have been given the task of writing an unloader - that is, a piece of software that can take the image of a pro
Brums [2.3K]
............;(&;&;$;!:$:!;$;8;$;$;;$;&8;$;$;$;$;$;$;$;$;$;
8 0
2 years ago
5.14 ◆ Write a version of the inner product procedure described in Problem 5.13 that uses 6 × 1 loop unrolling. For x86-64, our
KengaRu [80]

Answer:

(a) the number of times the value is performs is up to four cycles. and as such the integer i is executed up to 5 times.  (b)The point version of the floating point can have CPE of 3.00, even when the multiplication operation required is either 4 or 5 clock.

Explanation:

Solution

The two floating point versions can have CPEs of 3.00, even though the multiplication operation demands either 4 or 5 clock cycles by the latency suggests the total number of clock cycles needed to work the actual operation, while issues time to specify the minimum number of cycles between operations.

Now,

sum = sum + udata[i] * vdata[i]

in this case, the value of i performs from 0 to 3.

Thus,

The value of sum is denoted as,

sum = ((((sum + udata[0] * vdata[0])+(udata[1] * vdata[1]))+( udata[2] * vdata[2]))+(udata[3] * vdata[3]))

Thus,

(A)The number of times the value is executed is up to 4 cycle. And the integer i performed up to 5 times.

Thus,

(B) The floating point version can have CPE of 3.00, even though the multiplication operation required either 4 or 5 clock.

3 0
1 year ago
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