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pav-90 [236]
2 years ago
7

Jim is writing a program to calculate the wages of workers in a teddy bear factory.

Computers and Technology
1 answer:
34kurt2 years ago
3 0

Answer:

The algorithm is as follows;

1. Start

2. Input TeddyBears

3. Input Hours

4. WagebyTeddy = 2 * TeddyBears

5. WagebyHour = 5 * Hours

6. If WagebyHour > WagebyTeddy then

6.1 Print WagebyHour

7. Else

7.1. Print WagebyTeddy

8. Stop

Explanation:

The following variables are used;

TeddyBears -> Number of teddy bears made

Hours -> Number of Hours worked

WagebyTeddy -> Wages for the number of teddy bears made

WagebyHour -> Wages for the number of hours worked

The algorithm starts by accepting input for the number of teddy bears and hours worked from the user on line 2 and line 3

The wages for the number of teddy bears made  is calculated on line 4

The wages for the number of hours worked  is calculated on line 5

Line 6 checks if wages for the number of hours is greated than wages for the number of bears made;

If yes, the calculated wages by hour is displayed

Otherwise

the calculated wages by teddy bears made is displayed

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#Write a function called string_finder. string_finder should #take two parameters: a target string and a search string. #The fun
adoni [48]

Answer:

I am writing a Python program:

def string_finder(target,search): #function that takes two parameters i.e. target string and a search string

   position=(target.find(search))# returns lowest index of search if it is found in target string

   if position==0: # if value of position is 0 means lowers index

       return "Beginning" #the search string in the beginning of target string

   elif position== len(target) - len(search): #if position is equal to the difference between lengths of the target and search strings

       return "End" # returns end

   elif position > 0 and position < len(target) -1: #if value of position is greater than 0 and it is less than length of target -1

       return "Middle" #returns middle        

   else: #if none of above conditions is true return not found

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#you can add an elif condition instead of else for not found condition as:

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#returns "not found"

#tests the data for the following cases      

print(string_finder("Georgia Tech", "Georgia"))

print(string_finder("Georgia Tech", "gia"))

print(string_finder("Georgia Tech", "Tech"))

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Explanation:

The program can also be written in by using string methods.

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           return "Beginning"  #if above condition it true return Beginning

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       elif target.find(search) != -1:  #find method returns -1 if the search string is not in target string so if find method does not return -1 then it means that the search string is within the target string and two above conditions evaluated to false so search string must be in the middle of target string

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       else:  #if none of the above conditions is true then returns Not Found

           return "Not Found"

6 0
1 year ago
Someone claims that the big O notation does not make sense at all, and they give the following example. An algorithm A that proc
Svetllana [295]

Answer:

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Big Oh describes the worst case to describe time complexity.

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To calculate first of all discard all th constants.

And therefore; worst case is the O(N^3).

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