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Yuki888 [10]
2 years ago
11

An entrepreneur is opening a computer store in a small town and wants to display a few laptops in the store, but is concerned ab

out security. What physical laptop feature might assist in addressing this issue

Computers and Technology
2 answers:
Andru [333]2 years ago
8 0

Answer:

a security slot

Explanation:

Based on the scenario being described within the question it can be said that the feature that might assist in this case would be a security slot. This is a slot that comes built into most notebooks manufactured since 2000 allowing a cable to be attached and secured to a stationary object such as a table so that the device is not stolen or falls.

nirvana33 [79]2 years ago
3 0

Answer:

Security slot

Explanation:

The security slot, which is usually known as Kensington Slot, K-lock or Universal Security Lock, allows the use of certain hardware accessories, which can attach your laptop to an immovable object, making it quite a challenge for the potential thieves to steal it.

Cheers

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When should a developer begin thinking about scalability? 1 during the design phase 2during testing 3when traffic increases by 2
Tanzania [10]

Answer:

in my opinion 4

Explanation:

when the system is available to users

(sorry and thanks)

4 0
2 years ago
At one college, the tuition for a full-time student is $8,000 per semester. It has been announced that the tuition will increase
inn [45]

Answer:

#include <iostream>

using namespace std;

 

int main () {

  // for loop execution

  int semester_fees=8000;

  int b=1;

  cout<<"there are 5 years or 10 semester fees breakdown is given below"<<endl;

  for( int a = 1; a <=5; a++ ) {

     semester_fees = semester_fees*1.03;

     cout<<"Semester fees for each of semester"<<b++<<"and"<<b++<<"is:$"<<semester_fees<<endl;

     

  }

 

  return 0;

}

Explanation:

code is in c++ language

Fees is incremented yearly and i have considered only two semester per year

3 0
1 year ago
Someone claims that the big O notation does not make sense at all, and they give the following example. An algorithm A that proc
Svetllana [295]

Answer:

Big Oh notation is used to asymptotically bound the growth of running time above and below the constant factor.

Big Oh notation is used to describe time complexity, execution time of an algorithm.

Big Oh describes the worst case to describe time complexity.

For the equation; T(N) = 10000*N + 0.00001*N^3.

To calculate first of all discard all th constants.

And therefore; worst case is the O(N^3).

7 0
2 years ago
Write a second constructor as indicated. Sample output: User1: Minutes: 0, Messages: 0 User2: Minutes: 1000, Messages: 5000
Mashcka [7]

Complete Question:

Write a second constructor as indicated. Sample output:User1: Minutes: 0, Messages: 0User2: Minutes: 1000, Messages: 5000// ===== Code from file PhonePlan.java =====public class PhonePlan { private int freeMinutes; private int freeMessages; public PhonePlan() { freeMinutes = 0; freeMessages = 0; } // FIXME: Create a second constructor with numMinutes and numMessages parameters. /* Your solution goes here */ public void print() { System.out.println("Minutes: " + freeMinutes + ", Messages: " + freeMessages); return; }}

Answer:

The second constructor is given as:

//This defines the constructor, the name has to be the same as the class //name

PhonePlan(int numOfMinutes, int numberOfMessages) {

this.freeMinutes = numOfMinutes;

this.freeMessages = numberOfMessages

}

Explanation:

The second constructor is defined using java programming language.

  1. The given class has two constructors This is called "Constructor Overloading) which implements polymophism
  2. In the second constructor that we created, we pass in two arguments of type integer numOfMinutes and numberOfMessages.
  3. In the constructor's body we assign these values to the initially declared variables freeMinutes and freeMessages
6 0
2 years ago
6. Write pseudo code that will perform the following. a) Read in 5 separate numbers. b) Calculate the average of the five number
Alex

Answer:

Pseudo CODE

a)

n= Input “Enter 5 integer value”

b)

sum=0.0

For loop with i ranging from 0 - 5

Inside loop sum=n[i]+sum

Outside loop avg= sum/5

Print avg

c)

small=n[0] # assume the first number in the list is smallest

large= n[0] # assume the first number in the list is largest

For loop with i ranging from 0 - 5

Inside loop if n[i]<small #if any another number is smaller than small(variable)

Inside if Then small=n[i]

Inside loop if n[i]>large # if any another number is larger than large(variable)

Inside if then large=n[i]

Print small

Print large

d)

print avg

print small

print large

8 0
2 years ago
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