Write a script that prints the multiples of 7 between 0 and 100. Print one multiple per line and avoid printing any numbers that
aren't multiples of 7. Remember that 0 is also a multiple of 7.
1 answer:
Answer:
The program to this question can be described as follows:
Program:
#include <iostream> //defining header file
using namespace std;
int main() //defining main method
{
int x; //defining integer variable
for(x=0;x<=100;x++) //defining loop to count value from 0 to 100
{
if(x%7==0) //check value is divisable by 7
{
cout<<x<<endl; //print value
}
}
return 0;
}
Output:
please find the attachment.
Explanation:
In the above code, an integer variable x is declared, which is used in the for loop, in this loop variable "x" starts from 0 and ends when the value of x is less than and equal to 100.
- Inside the loop an, if block is used that defines a condition that is (i%7==0), it will check, that the value is divided by 7.
- In this loop, a print method is used, that prints its values.
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Solution :
class Employee:
#Define the
#constructor.
def ____(
, ID_number,
, email):
#Set the values of
#the data members of the class.
= name
_number = ID_number
= salary
self.email_address = email
#Define the function
#make_employee_dict().
def make_employee_dict(list_names, list_ID, list_salary, list_email):
#Define the dictionary
#to store the results.
employee_dict = {}
#Store the length
#of the list.
list_len = len(list_ID)
#Run the loop to
#traverse the list.
for i in range(list_len):
#Access the lists to
#get the required details.
name = list_names[i]
id_num = list_ID[i]
salary = list_salary[i]
email = list_email[i]
#Define the employee
#object and store
#it in the dictionary.
employee_dict[id_num] = Employee(name, id_num, salary, email)
#Return the
#resultant dictionary.
return employee_dict