Answer:
The External Data Bus is used to transport binary data and Address bus is used to transport memory addresses.
Explanation:
- External Data Bus is a combination of data bus and external bus. Data bus is used to carry data and instructions between two or more components in the system e.g. CPU and all other computer components.
- External bus is also called expansion bus. It is used to connect external components to the computer. Its a communication medium between CPU and other components. These components can be peripheral device like USB or flash memory.
- So External Data Bus is used to transport data between CPU and external components. It is a primary communication pathway for data in a computer. The external data components are connected to this bus and the instruction or data on this bus is available to all external components. But the data communication is slower as compared to that of internal bus.
- Address Bus carries physical location or address of data and transports memory addresses. Processor uses address bus when it wants to read data from memory or write data to the memory by sending a read/write signal by placing the read/write address of the specific memory location on the address bus.
This is done by a very simple formula: the only thing you need to type is =x-y where x is the cell that contains the total of 2018 and y being the cell that contains the total for 2017. If both are numeric values you can use the formula = A1-B1 and get your result. Your <span>cells don't have to be in the same order as your formula.</span>
Answer:
B. blocking I/O
Explanation:
Most of the input and output request placed to the computer considers the blocking request. It means that the controls given cannot be returned to the given application until and unless the input/output is complete.
Thus, blocking the input/output does not return till the input and output is complete.
With a blocking I/O, the process is moved to a wait queue when the I/O request is made, and it moved backs to the ready queue as soon as the request is complete, thereby allowing the other processes to run in the meantime.
Thus (B) blocking I/O is the answer.
Answer:
public class Main {
public static void main(String[] args)
{
int n,m;
int k=5;
for(n=1;n<=k;n++)
{
for(m=1;m<=n;m++)
System.out.print(m);
System.out.print(" ");
}
}
}
Explanation:
The solution to this problem is the use of nested loops of an inner and outer loop to generate a half pyramid of numbers, but displayed on the same line so we have a sequence 1 12 123 1234 12345. The outer loop iterates for n=1 to n<=5 and the inner loop that has the print statement prints the integers from for m = 1 to m<=n.
Note that the value k = 5 is hard coded which in some sense is the number of rows, that is the length of iteration of the outer loop.
Answer:
E) Encoding.
Explanation:
Communication is important aspect of life.Communication barriers occurs at all stages of communication from when the sender sends the message to the receiver receiving the message. Lack of communication skill in that particular comes in encoding barrier.So we conclude that the answer is Encoding.
